To solve the problems, we need to evaluate the functions from the given graphs. Let's go through each graph step by step.
Graph 1:
-
Equation of the line: The line is a straight line passing through the origin with a slope of 1. Therefore, the equation is \( f(x) = x \).
#### Questions:
1.
\( f(3) = \)
- Substitute \( x = 3 \) into \( f(x) = x \):
\[
f(3) = 3
\]
2.
\( f(x) = -3 \), \( x = \)
- Solve for \( x \) when \( f(x) = -3 \):
\[
f(x) = x \implies x = -3
\]
Graph 2:
-
Shape of the graph: This is a V-shaped graph (absolute value function shifted and scaled). The vertex is at \( (-1, 3) \), and the slopes are symmetric.
#### Questions:
1.
\( f(2) = \)
- Locate \( x = 2 \) on the graph. The corresponding \( y \)-value is \( -1 \):
\[
f(2) = -1
\]
2.
\( f(x) = 3 \), \( x = \)
- Find the \( x \)-values where the graph intersects \( y = 3 \). From the graph, this occurs at \( x = -1 \):
\[
f(x) = 3 \implies x = -1
\]
Graph 3:
-
Shape of the graph: This is a piecewise linear graph with a flat segment.
#### Questions:
1.
\( f(-1) = \)
- Locate \( x = -1 \) on the graph. The corresponding \( y \)-value is \( 2 \):
\[
f(-1) = 2
\]
2.
\( f(x) = -2 \), \( x = \)
- Find the \( x \)-values where the graph intersects \( y = -2 \). From the graph, this occurs at \( x = -4 \):
\[
f(x) = -2 \implies x = -4
\]
Graph 4:
-
Shape of the graph: This is a parabolic graph opening downwards with a vertex at \( (0, 5) \).
#### Questions:
1.
\( f(0) = \)
- Locate \( x = 0 \) on the graph. The corresponding \( y \)-value is \( 5 \):
\[
f(0) = 5
\]
2.
\( f(x) = 5 \), \( x = \)
- Find the \( x \)-values where the graph intersects \( y = 5 \). From the graph, this occurs at \( x = 0 \):
\[
f(x) = 5 \implies x = 0
\]
Final Answers:
\[
\boxed{
\begin{array}{ll}
f(3) = 3 & f(2) = -1 \\
f(x) = -3, \, x = -3 & f(x) = 3, \, x = -1 \\
f(-1) = 2 & f(0) = 5 \\
f(x) = -2, \, x = -4 & f(x) = 5, \, x = 0 \\
\end{array}
}
\]
Parent Tip: Review the logic above to help your child master the concept of evaluating functions worksheet.