Practice problems for identifying even and odd functions through graphical and algebraic methods.
Graphs and algebraic functions for determining even, odd, or neither properties in a practice worksheet.
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Step-by-step solution for: Free Printable Even and Odd Functions Worksheets
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Step-by-step solution for: Free Printable Even and Odd Functions Worksheets
Let's go through the Even and Odd Functions Practice Problems step by step, explaining how to determine whether a function is even, odd, or neither, both graphically (Section A) and algebraically (Section B).
---
- A function $ f(x) $ is even if:
$$
f(-x) = f(x)
$$
→ The graph is symmetric about the y-axis.
- A function $ f(x) $ is odd if:
$$
f(-x) = -f(x)
$$
→ The graph is symmetric about the origin (180° rotation).
- If neither condition holds, the function is neither even nor odd.
---
## ✔ Section A: Graphical Analysis
We analyze each graph based on symmetry.
---
- The graph appears to be symmetric about the origin.
- For example, if you rotate it 180° around the origin, it maps onto itself.
- Points like $ (a, b) $ have corresponding points $ (-a, -b) $.
- This is characteristic of an odd function.
✔ Answer: Odd
---
- This graph is a parabola-like shape opening upward, but shifted right.
- It’s not symmetric about the y-axis (because the vertex is not at $ x=0 $), so it's not even.
- It’s also not symmetric about the origin — for example, $ f(1) \neq -f(-1) $, and values don’t reflect through the origin.
- So it fails both conditions.
✔ Answer: Neither
---
- This is a parabola opening downward with its vertex at the origin.
- Symmetric about the y-axis: $ f(-x) = f(x) $
- Example: $ f(2) = f(-2) $, etc.
✔ Answer: Even
---
## ✔ Section B: Algebraic Analysis
We will use the definitions:
- Compute $ f(-x) $
- Compare with $ f(x) $ and $ -f(x) $
---
Compute $ f(-x) $:
$$
f(-x) = (-x)^3 - (-x)^2 + 4(-x) + 2 = -x^3 - x^2 - 4x + 2
$$
Compare:
- Is $ f(-x) = f(x) $? No.
- Is $ f(-x) = -f(x) $? Let's check $ -f(x) $:
$$
-f(x) = -(x^3 - x^2 + 4x + 2) = -x^3 + x^2 - 4x - 2
$$
Not equal to $ f(-x) $
✘ Neither
✔ Answer: Neither
---
$$
f(-x) = -(-x)^2 + 10 = -x^2 + 10 = f(x)
$$
→ $ f(-x) = f(x) $ → Even
✔ Answer: Even
---
$$
f(-x) = (-x)^3 + 4(-x) = -x^3 - 4x = -(x^3 + 4x) = -f(x)
$$
→ $ f(-x) = -f(x) $ → Odd
✔ Answer: Odd
---
$$
f(-x) = -(-x)^3 + 5(-x) - 2 = -(-x^3) - 5x - 2 = x^3 - 5x - 2
$$
Now compare:
- $ f(x) = -x^3 + 5x - 2 $
- $ f(-x) = x^3 - 5x - 2 $
- $ -f(x) = x^3 - 5x + 2 $
Is $ f(-x) = f(x) $? No
Is $ f(-x) = -f(x) $? No (because constant term is $-2$ vs $+2$)
✘ Neither
✔ Answer: Neither
---
Note: $ x^4 $ and $ x^2 $ are even powers.
$$
f(-x) = \sqrt{(-x)^4 - (-x)^2 + 4} = \sqrt{x^4 - x^2 + 4} = f(x)
$$
→ $ f(-x) = f(x) $ → Even
✔ Answer: Even
---
$$
f(-x) = |-x + 4| = |-(x - 4)| = |x - 4|
$$
Compare:
- $ f(x) = |x + 4| $
- $ f(-x) = |x - 4| $
- These are not equal → not even
- $ -f(x) = -|x + 4| $, which is negative, while $ f(-x) $ is non-negative → not odd
✘ Neither
✔ Answer: Neither
---
$$
f(-x) = |-x| + 4 = |x| + 4 = f(x)
$$
→ $ f(-x) = f(x) $ → Even
✔ Answer: Even
---
All terms have even powers.
$$
f(-x) = (-x)^4 - 2(-x)^2 + 4 = x^4 - 2x^2 + 4 = f(x)
$$
→ Even
✔ Answer: Even
---
Cube root is defined for all real numbers.
$$
f(-x) = \sqrt[3]{-x} = -\sqrt[3]{x} = -f(x)
$$
→ $ f(-x) = -f(x) $ → Odd
✔ Answer: Odd
---
Check domain first: $ x^2 - 1 \geq 0 $ → $ |x| \geq 1 $
Now compute $ f(-x) $:
$$
f(-x) = (-x)\sqrt{(-x)^2 - 1} = (-x)\sqrt{x^2 - 1} = -x\sqrt{x^2 - 1} = -f(x)
$$
→ $ f(-x) = -f(x) $ → Odd
✔ Answer: Odd
---
## ✔ Final Answers Summary
1. Odd
2. Neither
3. Even
1. Neither
2. Even
3. Odd
4. Neither
5. Even
6. Neither
7. Even
8. Even
9. Odd
10. Odd
These match the provided answers!
---
- Even functions: Symmetric about y-axis → $ f(-x) = f(x) $
- Odd functions: Symmetric about origin → $ f(-x) = -f(x) $
- Polynomials: Only even-powered terms → even; only odd-powered terms → odd; mixed → neither
- Absolute value & roots: Check behavior under $ -x $
- Always test $ f(-x) $ algebraically when possible
Let me know if you'd like visual explanations or graphs!
---
🔷 Definitions:
- A function $ f(x) $ is even if:
$$
f(-x) = f(x)
$$
→ The graph is symmetric about the y-axis.
- A function $ f(x) $ is odd if:
$$
f(-x) = -f(x)
$$
→ The graph is symmetric about the origin (180° rotation).
- If neither condition holds, the function is neither even nor odd.
---
## ✔ Section A: Graphical Analysis
We analyze each graph based on symmetry.
---
1. First Graph
- The graph appears to be symmetric about the origin.
- For example, if you rotate it 180° around the origin, it maps onto itself.
- Points like $ (a, b) $ have corresponding points $ (-a, -b) $.
- This is characteristic of an odd function.
✔ Answer: Odd
---
2. Second Graph
- This graph is a parabola-like shape opening upward, but shifted right.
- It’s not symmetric about the y-axis (because the vertex is not at $ x=0 $), so it's not even.
- It’s also not symmetric about the origin — for example, $ f(1) \neq -f(-1) $, and values don’t reflect through the origin.
- So it fails both conditions.
✔ Answer: Neither
---
3. Third Graph
- This is a parabola opening downward with its vertex at the origin.
- Symmetric about the y-axis: $ f(-x) = f(x) $
- Example: $ f(2) = f(-2) $, etc.
✔ Answer: Even
---
## ✔ Section B: Algebraic Analysis
We will use the definitions:
- Compute $ f(-x) $
- Compare with $ f(x) $ and $ -f(x) $
---
1. $ f(x) = x^3 - x^2 + 4x + 2 $
Compute $ f(-x) $:
$$
f(-x) = (-x)^3 - (-x)^2 + 4(-x) + 2 = -x^3 - x^2 - 4x + 2
$$
Compare:
- Is $ f(-x) = f(x) $? No.
- Is $ f(-x) = -f(x) $? Let's check $ -f(x) $:
$$
-f(x) = -(x^3 - x^2 + 4x + 2) = -x^3 + x^2 - 4x - 2
$$
Not equal to $ f(-x) $
✘ Neither
✔ Answer: Neither
---
2. $ f(x) = -x^2 + 10 $
$$
f(-x) = -(-x)^2 + 10 = -x^2 + 10 = f(x)
$$
→ $ f(-x) = f(x) $ → Even
✔ Answer: Even
---
3. $ f(x) = x^3 + 4x $
$$
f(-x) = (-x)^3 + 4(-x) = -x^3 - 4x = -(x^3 + 4x) = -f(x)
$$
→ $ f(-x) = -f(x) $ → Odd
✔ Answer: Odd
---
4. $ f(x) = -x^3 + 5x - 2 $
$$
f(-x) = -(-x)^3 + 5(-x) - 2 = -(-x^3) - 5x - 2 = x^3 - 5x - 2
$$
Now compare:
- $ f(x) = -x^3 + 5x - 2 $
- $ f(-x) = x^3 - 5x - 2 $
- $ -f(x) = x^3 - 5x + 2 $
Is $ f(-x) = f(x) $? No
Is $ f(-x) = -f(x) $? No (because constant term is $-2$ vs $+2$)
✘ Neither
✔ Answer: Neither
---
5. $ f(x) = \sqrt{x^4 - x^2 + 4} $
Note: $ x^4 $ and $ x^2 $ are even powers.
$$
f(-x) = \sqrt{(-x)^4 - (-x)^2 + 4} = \sqrt{x^4 - x^2 + 4} = f(x)
$$
→ $ f(-x) = f(x) $ → Even
✔ Answer: Even
---
6. $ f(x) = |x + 4| $
$$
f(-x) = |-x + 4| = |-(x - 4)| = |x - 4|
$$
Compare:
- $ f(x) = |x + 4| $
- $ f(-x) = |x - 4| $
- These are not equal → not even
- $ -f(x) = -|x + 4| $, which is negative, while $ f(-x) $ is non-negative → not odd
✘ Neither
✔ Answer: Neither
---
7. $ f(x) = |x| + 4 $
$$
f(-x) = |-x| + 4 = |x| + 4 = f(x)
$$
→ $ f(-x) = f(x) $ → Even
✔ Answer: Even
---
8. $ f(x) = x^4 - 2x^2 + 4 $
All terms have even powers.
$$
f(-x) = (-x)^4 - 2(-x)^2 + 4 = x^4 - 2x^2 + 4 = f(x)
$$
→ Even
✔ Answer: Even
---
9. $ f(x) = \sqrt[3]{x} $
Cube root is defined for all real numbers.
$$
f(-x) = \sqrt[3]{-x} = -\sqrt[3]{x} = -f(x)
$$
→ $ f(-x) = -f(x) $ → Odd
✔ Answer: Odd
---
10. $ f(x) = x\sqrt{x^2 - 1} $
Check domain first: $ x^2 - 1 \geq 0 $ → $ |x| \geq 1 $
Now compute $ f(-x) $:
$$
f(-x) = (-x)\sqrt{(-x)^2 - 1} = (-x)\sqrt{x^2 - 1} = -x\sqrt{x^2 - 1} = -f(x)
$$
→ $ f(-x) = -f(x) $ → Odd
✔ Answer: Odd
---
## ✔ Final Answers Summary
Section A (Graphs):
1. Odd
2. Neither
3. Even
Section B (Algebra):
1. Neither
2. Even
3. Odd
4. Neither
5. Even
6. Neither
7. Even
8. Even
9. Odd
10. Odd
These match the provided answers!
---
🧠 Key Takeaways:
- Even functions: Symmetric about y-axis → $ f(-x) = f(x) $
- Odd functions: Symmetric about origin → $ f(-x) = -f(x) $
- Polynomials: Only even-powered terms → even; only odd-powered terms → odd; mixed → neither
- Absolute value & roots: Check behavior under $ -x $
- Always test $ f(-x) $ algebraically when possible
Let me know if you'd like visual explanations or graphs!
Parent Tip: Review the logic above to help your child master the concept of even odd functions worksheet.