Worksheet on simplifying expressions using exponent rules.
A worksheet titled "Exponent Rules" with 15 problems requiring the use of exponent laws to simplify expressions into positive exponents.
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Step-by-step solution for: Exponents Worksheets | Exponent worksheets, Teaching algebra, 10th ...
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Show Answer Key & Explanations
Step-by-step solution for: Exponents Worksheets | Exponent worksheets, Teaching algebra, 10th ...
Let's solve each of these exponent problems step by step using the laws of exponents. We'll simplify each expression and write the answers with positive exponents only.
---
1. $ a^m \cdot a^n = a^{m+n} $
2. $ \frac{a^m}{a^n} = a^{m-n} $
3. $ (a^m)^n = a^{m \cdot n} $
4. $ (ab)^n = a^n b^n $
5. $ \left(\frac{a}{b}\right)^n = \frac{a^n}{b^n} $
6. $ a^{-n} = \frac{1}{a^n} $
7. $ \frac{1}{a^{-n}} = a^n $
We’ll apply these rules one by one.
---
Simplify inside first:
$$
\frac{x^4 y^5}{x^2 y^3} = x^{4-2} y^{5-3} = x^2 y^2
$$
Now raise to $-2$:
$$
(x^2 y^2)^{-2} = x^{-4} y^{-4}
$$
Convert to positive exponents:
$$
= \frac{1}{x^4 y^4}
$$
✔ Answer: $ \boxed{\frac{1}{x^4 y^4}} $
---
First, expand $ (ab^2)^2 $:
$$
(ab^2)^2 = a^2 b^4
$$
Now multiply:
$$
a^3 b^3 \cdot a^2 b^4 = a^{3+2} b^{3+4} = a^5 b^7
$$
✔ Answer: $ \boxed{a^5 b^7} $
---
Simplify inside:
Numerator: $ 8m^3 n^{-4} $
Denominator: $ 2m^{-1} n^2 $
Divide:
$$
\frac{8}{2} \cdot m^{3 - (-1)} \cdot n^{-4 - 2} = 4 \cdot m^{4} \cdot n^{-6}
$$
So:
$$
\left(4 m^4 n^{-6}\right)^{-1} = 4^{-1} m^{-4} n^{6} = \frac{1}{4} m^{-4} n^6
$$
Convert to positive exponents:
$$
= \frac{n^6}{4 m^4}
$$
✔ Answer: $ \boxed{\frac{n^6}{4 m^4}} $
---
First, expand $ (2p^3 q)^2 $:
$$
= 2^2 p^{6} q^2 = 4 p^6 q^2
$$
Now multiply:
$$
5p^4 q^{-1} \cdot 4 p^6 q^2 = 20 p^{4+6} q^{-1+2} = 20 p^{10} q^1
$$
✔ Answer: $ \boxed{20 p^{10} q} $
---
First, compute numerator:
- $ (2k^{-1})^2 = 4 k^{-2} $
- $ (2k)^2 = 4 k^2 $
Multiply:
$$
4k^{-2} \cdot 4k^2 = 16 k^{-2 + 2} = 16 k^0 = 16
$$
Denominator: $ 4k^{-2} $
So:
$$
\frac{16}{4k^{-2}} = 4 \cdot k^2 = 4k^2
$$
✔ Answer: $ \boxed{4k^2} $
---
Simplify each part:
- $ (a^{-2})^{-1} = a^{(-2)(-1)} = a^2 $
- $ (a^3)^{-2} = a^{-6} $
- Then $ a^{-3} $
Now combine:
$$
a^2 \cdot a^{-6} \cdot a^{-3} = a^{2 - 6 - 3} = a^{-7}
$$
Convert to positive exponent:
$$
= \frac{1}{a^7}
$$
✔ Answer: $ \boxed{\frac{1}{a^7}} $
---
Apply negative exponent:
$$
= \left( \frac{31 y^{10}}{24 x^2} \right)^3
$$
Now distribute exponent:
$$
= \frac{31^3 y^{30}}{24^3 x^6}
$$
Calculate powers:
- $ 31^3 = 29791 $
- $ 24^3 = 13824 $
So:
$$
= \frac{29791 y^{30}}{13824 x^6}
$$
✔ Answer: $ \boxed{\frac{29791 y^{30}}{13824 x^6}} $
---
First, simplify the fraction:
$$
\frac{2^{-4} a^{-4}}{a^3 b^{-1}} = 2^{-4} a^{-4 - 3} b^{1} = 2^{-4} a^{-7} b
$$
Now multiply by $ 3a^{-3} $:
$$
3a^{-3} \cdot 2^{-4} a^{-7} b = 3 \cdot 2^{-4} \cdot a^{-10} \cdot b
$$
$ 2^{-4} = \frac{1}{16} $, so:
$$
= \frac{3}{16} a^{-10} b = \frac{3b}{16 a^{10}}
$$
✔ Answer: $ \boxed{\frac{3b}{16 a^{10}}} $
---
Simplify inside:
$$
\frac{2m^{-2} n^3}{3m^{-4} n^{-1}} = \frac{2}{3} m^{-2 - (-4)} n^{3 - (-1)} = \frac{2}{3} m^{2} n^{4}
$$
Now take inverse:
$$
\left( \frac{2}{3} m^2 n^4 \right)^{-1} = \frac{3}{2} m^{-2} n^{-4} = \frac{3}{2 m^2 n^4}
$$
✔ Answer: $ \boxed{\frac{3}{2 m^2 n^4}} $
---
Simplify:
$$
= \frac{2}{3} \cdot p^{3 - (-1)} \cdot q^{-2 - 3} \cdot r^{-4 - (-5)} = \frac{2}{3} p^4 q^{-5} r^{1}
$$
Now convert:
$$
= \frac{2 p^4 r}{3 q^5}
$$
✔ Answer: $ \boxed{\frac{2 p^4 r}{3 q^5}} $
---
Simplify inside:
$$
\frac{3x^{-1} y^2}{4y^{-2}} = \frac{3}{4} x^{-1} y^{2 - (-2)} = \frac{3}{4} x^{-1} y^4
$$
Now invert:
$$
= \frac{4}{3} x^{1} y^{-4} = \frac{4x}{3 y^4}
$$
✔ Answer: $ \boxed{\frac{4x}{3 y^4}} $
---
Compute each term:
- $ (3z^{-2} w^3)^2 = 9 z^{-4} w^6 $
- $ (2w^{-3})^3 = 8 w^{-9} $
- $ (1w^{-1})^{-2} = (w^{-1})^{-2} = w^{2} $
Now multiply all:
$$
9 z^{-4} w^6 \cdot 8 w^{-9} \cdot w^2 = 72 z^{-4} w^{6 - 9 + 2} = 72 z^{-4} w^{-1}
$$
Convert to positive exponents:
$$
= \frac{72}{z^4 w}
$$
✔ Answer: $ \boxed{\frac{72}{z^4 w}} $
---
Break it down:
1. $ (4a^2 z^{-3})^{-2} = 4^{-2} a^{-4} z^{6} = \frac{1}{16} a^{-4} z^6 $
2. $ (a^{-2} z^3)^{-2} = a^{4} z^{-6} $
3. $ (a^{-1} w^{-2})^{-1} = a^{1} w^{2} $
Now multiply:
$$
\frac{1}{16} a^{-4} z^6 \cdot a^4 z^{-6} \cdot a w^2
$$
Combine:
- $ a^{-4+4+1} = a^1 $
- $ z^{6-6} = z^0 = 1 $
- $ w^2 $
- Constant: $ \frac{1}{16} $
Result: $ \frac{1}{16} a w^2 $
✔ Answer: $ \boxed{\frac{a w^2}{16}} $
---
Simplify inside:
$$
\frac{8x^{-1} y^2}{2x y^{-3}} = \frac{8}{2} x^{-1 - 1} y^{2 - (-3)} = 4 x^{-2} y^5
$$
Now invert:
$$
(4 x^{-2} y^5)^{-1} = \frac{1}{4} x^{2} y^{-5} = \frac{x^2}{4 y^5}
$$
✔ Answer: $ \boxed{\frac{x^2}{4 y^5}} $
---
Simplify numerator:
- $ (2z^{-2})^3 = 8 z^{-6} $
- $ (4ab^{-2})^{-1} = \frac{1}{4} a^{-1} b^{2} $
So numerator:
$$
8 z^{-6} \cdot \frac{1}{4} a^{-1} b^2 = 2 z^{-6} a^{-1} b^2
$$
Denominator: $ 4 c^{-3} $
So:
$$
\frac{2 z^{-6} a^{-1} b^2}{4 c^{-3}} = \frac{1}{2} z^{-6} a^{-1} b^2 c^3
$$
Convert to positive exponents:
$$
= \frac{b^2 c^3}{2 a z^6}
$$
✔ Answer: $ \boxed{\frac{b^2 c^3}{2 a z^6}} $
---
## ✔ Final Answers Summary:
| Problem | Answer |
|--------|--------|
| 1 | $ \frac{1}{x^4 y^4} $ |
| 2 | $ a^5 b^7 $ |
| 3 | $ \frac{n^6}{4 m^4} $ |
| 4 | $ 20 p^{10} q $ |
| 5 | $ 4k^2 $ |
| 6 | $ \frac{1}{a^7} $ |
| 7 | $ \frac{29791 y^{30}}{13824 x^6} $ |
| 8 | $ \frac{3b}{16 a^{10}} $ |
| 9 | $ \frac{3}{2 m^2 n^4} $ |
| 10 | $ \frac{2 p^4 r}{3 q^5} $ |
| 11 | $ \frac{4x}{3 y^4} $ |
| 12 | $ \frac{72}{z^4 w} $ |
| 13 | $ \frac{a w^2}{16} $ |
| 14 | $ \frac{x^2}{4 y^5} $ |
| 15 | $ \frac{b^2 c^3}{2 a z^6} $ |
Let me know if you'd like these written in a printable format or need further explanation on any!
---
Exponent Rules Recap:
1. $ a^m \cdot a^n = a^{m+n} $
2. $ \frac{a^m}{a^n} = a^{m-n} $
3. $ (a^m)^n = a^{m \cdot n} $
4. $ (ab)^n = a^n b^n $
5. $ \left(\frac{a}{b}\right)^n = \frac{a^n}{b^n} $
6. $ a^{-n} = \frac{1}{a^n} $
7. $ \frac{1}{a^{-n}} = a^n $
We’ll apply these rules one by one.
---
1) $ \left( \frac{x^4 y^5}{x^2 y^3} \right)^{-2} $
Simplify inside first:
$$
\frac{x^4 y^5}{x^2 y^3} = x^{4-2} y^{5-3} = x^2 y^2
$$
Now raise to $-2$:
$$
(x^2 y^2)^{-2} = x^{-4} y^{-4}
$$
Convert to positive exponents:
$$
= \frac{1}{x^4 y^4}
$$
✔ Answer: $ \boxed{\frac{1}{x^4 y^4}} $
---
2) $ (a^3 b^3)(ab^2)^2 $
First, expand $ (ab^2)^2 $:
$$
(ab^2)^2 = a^2 b^4
$$
Now multiply:
$$
a^3 b^3 \cdot a^2 b^4 = a^{3+2} b^{3+4} = a^5 b^7
$$
✔ Answer: $ \boxed{a^5 b^7} $
---
3) $ \left( \frac{8m^3 n^{-4}}{2m^{-1} n^2} \right)^{-1} $
Simplify inside:
Numerator: $ 8m^3 n^{-4} $
Denominator: $ 2m^{-1} n^2 $
Divide:
$$
\frac{8}{2} \cdot m^{3 - (-1)} \cdot n^{-4 - 2} = 4 \cdot m^{4} \cdot n^{-6}
$$
So:
$$
\left(4 m^4 n^{-6}\right)^{-1} = 4^{-1} m^{-4} n^{6} = \frac{1}{4} m^{-4} n^6
$$
Convert to positive exponents:
$$
= \frac{n^6}{4 m^4}
$$
✔ Answer: $ \boxed{\frac{n^6}{4 m^4}} $
---
4) $ (5p^4 q^{-1})(2p^3 q)^2 $
First, expand $ (2p^3 q)^2 $:
$$
= 2^2 p^{6} q^2 = 4 p^6 q^2
$$
Now multiply:
$$
5p^4 q^{-1} \cdot 4 p^6 q^2 = 20 p^{4+6} q^{-1+2} = 20 p^{10} q^1
$$
✔ Answer: $ \boxed{20 p^{10} q} $
---
5) $ \frac{(2k^{-1})^2 (2k)^2}{4k^{-2}} $
First, compute numerator:
- $ (2k^{-1})^2 = 4 k^{-2} $
- $ (2k)^2 = 4 k^2 $
Multiply:
$$
4k^{-2} \cdot 4k^2 = 16 k^{-2 + 2} = 16 k^0 = 16
$$
Denominator: $ 4k^{-2} $
So:
$$
\frac{16}{4k^{-2}} = 4 \cdot k^2 = 4k^2
$$
✔ Answer: $ \boxed{4k^2} $
---
6) $ (a^{-2})^{-1}(a^3)^{-2} a^{-3} $
Simplify each part:
- $ (a^{-2})^{-1} = a^{(-2)(-1)} = a^2 $
- $ (a^3)^{-2} = a^{-6} $
- Then $ a^{-3} $
Now combine:
$$
a^2 \cdot a^{-6} \cdot a^{-3} = a^{2 - 6 - 3} = a^{-7}
$$
Convert to positive exponent:
$$
= \frac{1}{a^7}
$$
✔ Answer: $ \boxed{\frac{1}{a^7}} $
---
7) $ \left( \frac{24 x^2}{31 y^{10}} \right)^{-3} $
Apply negative exponent:
$$
= \left( \frac{31 y^{10}}{24 x^2} \right)^3
$$
Now distribute exponent:
$$
= \frac{31^3 y^{30}}{24^3 x^6}
$$
Calculate powers:
- $ 31^3 = 29791 $
- $ 24^3 = 13824 $
So:
$$
= \frac{29791 y^{30}}{13824 x^6}
$$
✔ Answer: $ \boxed{\frac{29791 y^{30}}{13824 x^6}} $
---
8) $ \left( \frac{2^{-4} a^{-4}}{a^3 b^{-1}} \right) (3a^{-3}) $
First, simplify the fraction:
$$
\frac{2^{-4} a^{-4}}{a^3 b^{-1}} = 2^{-4} a^{-4 - 3} b^{1} = 2^{-4} a^{-7} b
$$
Now multiply by $ 3a^{-3} $:
$$
3a^{-3} \cdot 2^{-4} a^{-7} b = 3 \cdot 2^{-4} \cdot a^{-10} \cdot b
$$
$ 2^{-4} = \frac{1}{16} $, so:
$$
= \frac{3}{16} a^{-10} b = \frac{3b}{16 a^{10}}
$$
✔ Answer: $ \boxed{\frac{3b}{16 a^{10}}} $
---
9) $ \left( \frac{2m^{-2} n^3}{3m^{-4} n^{-1}} \right)^{-1} $
Simplify inside:
$$
\frac{2m^{-2} n^3}{3m^{-4} n^{-1}} = \frac{2}{3} m^{-2 - (-4)} n^{3 - (-1)} = \frac{2}{3} m^{2} n^{4}
$$
Now take inverse:
$$
\left( \frac{2}{3} m^2 n^4 \right)^{-1} = \frac{3}{2} m^{-2} n^{-4} = \frac{3}{2 m^2 n^4}
$$
✔ Answer: $ \boxed{\frac{3}{2 m^2 n^4}} $
---
10) $ \frac{2p^3 q^{-2} r^{-4}}{3 p^{-1} q^3 r^{-5}} $
Simplify:
$$
= \frac{2}{3} \cdot p^{3 - (-1)} \cdot q^{-2 - 3} \cdot r^{-4 - (-5)} = \frac{2}{3} p^4 q^{-5} r^{1}
$$
Now convert:
$$
= \frac{2 p^4 r}{3 q^5}
$$
✔ Answer: $ \boxed{\frac{2 p^4 r}{3 q^5}} $
---
11) $ \left( \frac{3x^{-1} y^2}{4y^{-2}} \right)^{-1} $
Simplify inside:
$$
\frac{3x^{-1} y^2}{4y^{-2}} = \frac{3}{4} x^{-1} y^{2 - (-2)} = \frac{3}{4} x^{-1} y^4
$$
Now invert:
$$
= \frac{4}{3} x^{1} y^{-4} = \frac{4x}{3 y^4}
$$
✔ Answer: $ \boxed{\frac{4x}{3 y^4}} $
---
12) $ (3z^{-2} w^3)^2 (2w^{-3})^3 (1w^{-1})^{-2} $
Compute each term:
- $ (3z^{-2} w^3)^2 = 9 z^{-4} w^6 $
- $ (2w^{-3})^3 = 8 w^{-9} $
- $ (1w^{-1})^{-2} = (w^{-1})^{-2} = w^{2} $
Now multiply all:
$$
9 z^{-4} w^6 \cdot 8 w^{-9} \cdot w^2 = 72 z^{-4} w^{6 - 9 + 2} = 72 z^{-4} w^{-1}
$$
Convert to positive exponents:
$$
= \frac{72}{z^4 w}
$$
✔ Answer: $ \boxed{\frac{72}{z^4 w}} $
---
13) $ (4a^2 z^{-3})^{-2} (a^{-2} z^3)^{-2} (a^{-1} w^{-2})^{-1} $
Break it down:
1. $ (4a^2 z^{-3})^{-2} = 4^{-2} a^{-4} z^{6} = \frac{1}{16} a^{-4} z^6 $
2. $ (a^{-2} z^3)^{-2} = a^{4} z^{-6} $
3. $ (a^{-1} w^{-2})^{-1} = a^{1} w^{2} $
Now multiply:
$$
\frac{1}{16} a^{-4} z^6 \cdot a^4 z^{-6} \cdot a w^2
$$
Combine:
- $ a^{-4+4+1} = a^1 $
- $ z^{6-6} = z^0 = 1 $
- $ w^2 $
- Constant: $ \frac{1}{16} $
Result: $ \frac{1}{16} a w^2 $
✔ Answer: $ \boxed{\frac{a w^2}{16}} $
---
14) $ \left( \frac{8x^{-1} y^2}{2xy^{-3}} \right)^{-1} $
Simplify inside:
$$
\frac{8x^{-1} y^2}{2x y^{-3}} = \frac{8}{2} x^{-1 - 1} y^{2 - (-3)} = 4 x^{-2} y^5
$$
Now invert:
$$
(4 x^{-2} y^5)^{-1} = \frac{1}{4} x^{2} y^{-5} = \frac{x^2}{4 y^5}
$$
✔ Answer: $ \boxed{\frac{x^2}{4 y^5}} $
---
15) $ \frac{(2z^{-2})^3 (4ab^{-2})^{-1}}{4c^{-3}} $
Simplify numerator:
- $ (2z^{-2})^3 = 8 z^{-6} $
- $ (4ab^{-2})^{-1} = \frac{1}{4} a^{-1} b^{2} $
So numerator:
$$
8 z^{-6} \cdot \frac{1}{4} a^{-1} b^2 = 2 z^{-6} a^{-1} b^2
$$
Denominator: $ 4 c^{-3} $
So:
$$
\frac{2 z^{-6} a^{-1} b^2}{4 c^{-3}} = \frac{1}{2} z^{-6} a^{-1} b^2 c^3
$$
Convert to positive exponents:
$$
= \frac{b^2 c^3}{2 a z^6}
$$
✔ Answer: $ \boxed{\frac{b^2 c^3}{2 a z^6}} $
---
## ✔ Final Answers Summary:
| Problem | Answer |
|--------|--------|
| 1 | $ \frac{1}{x^4 y^4} $ |
| 2 | $ a^5 b^7 $ |
| 3 | $ \frac{n^6}{4 m^4} $ |
| 4 | $ 20 p^{10} q $ |
| 5 | $ 4k^2 $ |
| 6 | $ \frac{1}{a^7} $ |
| 7 | $ \frac{29791 y^{30}}{13824 x^6} $ |
| 8 | $ \frac{3b}{16 a^{10}} $ |
| 9 | $ \frac{3}{2 m^2 n^4} $ |
| 10 | $ \frac{2 p^4 r}{3 q^5} $ |
| 11 | $ \frac{4x}{3 y^4} $ |
| 12 | $ \frac{72}{z^4 w} $ |
| 13 | $ \frac{a w^2}{16} $ |
| 14 | $ \frac{x^2}{4 y^5} $ |
| 15 | $ \frac{b^2 c^3}{2 a z^6} $ |
Let me know if you'd like these written in a printable format or need further explanation on any!
Parent Tip: Review the logic above to help your child master the concept of exponent rules worksheet printable high school.