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Exponential growth and decay word problems riddle - Free Printable

Exponential growth and decay word problems riddle

Educational worksheet: Exponential growth and decay word problems riddle. Download and print for classroom or home learning activities.

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Show Answer Key & Explanations Step-by-step solution for: Exponential growth and decay word problems riddle
Let’s solve each problem one by one. We’ll write the equation, plug in the numbers, calculate carefully, and round to the nearest whole number as instructed.

---

Problem W: Sarah invests $500 at 1.5% compounded quarterly for 5 years.

Formula for compound interest:
A = P(1 + r/n)^(nt)

Where:
P = principal = 500
r = annual rate = 1.5% = 0.015
n = times per year = 4 (quarterly)
t = time in years = 5

So:
A = 500 × (1 + 0.015/4)^(4×5)
= 500 × (1 + 0.00375)^20
= 500 × (1.00375)^20

Calculate (1.00375)^20:
≈ 1.07763 (using calculator)

Then:
500 × 1.07763 ≈ 538.815 → Round to 539

But wait — let me double-check that exponentiation.

Actually, 1.00375^20:

Step-by-step approximation or use calculator:
1.00375^20 = e^(20 * ln(1.00375)) ≈ e^(20 * 0.003743) ≈ e^0.07486 ≈ 1.0777

Yes, so 500 × 1.0777 = 538.85 → rounds to 539

BUT — looking at the answer choices at the bottom: 22,756; 112; 12,800; 673; 30,425; 13

539 is not among them. Did I misread?

Wait — maybe I made a mistake. Let me recalculate with more precision.

Use exact calculation:

1.00375^20:

Let’s compute step by step:

1.00375^2 = 1.0075140625
^4 = (1.0075140625)^2 ≈ 1.015084
^8 ≈ (1.015084)^2 ≈ 1.030395
^16 ≈ (1.030395)^2 ≈ 1.061714

Now multiply by ^4 again? Wait, 20 = 16 + 4

So 1.061714 × 1.030395 ≈ ?

1.061714 × 1.03 = 1.093565, plus 1.061714 × 0.000395 ≈ negligible → approx 1.0936

That can’t be right — earlier we had ~1.077.

Better to use direct calculator value:

Actually, using precise calc:
(1 + 0.015/4) = 1.00375
1.00375^20 = 1.077632...

500 × 1.077632 = 538.816 → still 539.

But 539 isn't an option. Hmm.

Wait — perhaps I misread the problem? Or maybe the answer key has a typo? But let’s check other problems first.

Maybe I should proceed and see which answers match the given options.

---

Problem A: Joseph buys car for $26,500, depreciates 3% annually for 5 years.

Depreciation formula:
A = P(1 - r)^t

P = 26500
r = 0.03
t = 5

A = 26500 × (0.97)^5

Calculate 0.97^5:

0.97^2 = 0.9409
0.97^4 = (0.9409)^2 = 0.88529281
0.97^5 = 0.88529281 × 0.97 ≈ 0.858734

Then:
26500 × 0.858734 ≈ ?

First, 26500 × 0.85 = 22525
26500 × 0.008734 ≈ 26500 × 0.008 = 212, 26500 × 0.000734 ≈ 19.45 → total ≈ 231.45

So total ≈ 22525 + 231.45 = 22756.45 → rounds to 22,756

Ah! That matches one of the answer choices: 22,756

So Problem A → 22,756

And letter A corresponds to that box.

So if A = 22,756, then that’s correct.

Back to W — maybe I miscalculated? Or perhaps the problem expects simple interest? No, it says “compounded quarterly”.

Wait — let me try calculating W again with more care.

W: 500*(1 + 0.015/4)^(20)

0.015/4 = 0.00375

1.00375^20:

Using calculator: 1.00375^20 = 1.077632...

500 * 1.077632 = 538.816 → 539

But 539 is not in the list. The list is: 22,756; 112; 12,800; 673; 30,425; 13

None close to 539. Unless... did I misread the rate? 1.5% is very low. Maybe it's 15%? But no, it says 1.5%.

Perhaps the answer is supposed to be matched differently. Let’s do all problems and see which ones match the given numbers.

---

Problem L: Medication metabolizes at 4% per hour. Take 20mg at 8am, how much at 6pm?

From 8am to 6pm is 10 hours.

Decay formula: A = P(1 - r)^t

P = 20
r = 0.04
t = 10

A = 20 × (0.96)^10

Calculate 0.96^10:

0.96^2 = 0.9216
0.96^4 = (0.9216)^2 = 0.84934656
0.96^8 = (0.84934656)^2 ≈ 0.721389

Then 0.96^10 = 0.96^8 × 0.96^2 ≈ 0.721389 × 0.9216 ≈ ?

0.721389 × 0.9 = 0.64925
0.721389 × 0.0216 ≈ 0.01558
Total ≈ 0.66483

So A = 20 × 0.66483 ≈ 13.2966 → rounds to 13

Yes! 13 is in the answer choices.

So Problem L → 13

Letter L corresponds to that box.

---

Problem E: Population 22,640 in 2015, grows 3% yearly, what in 2025?

2025 - 2015 = 10 years

Growth formula: A = P(1 + r)^t

P = 22640
r = 0.03
t = 10

A = 22640 × (1.03)^10

Calculate 1.03^10:

1.03^2 = 1.0609
1.03^4 = (1.0609)^2 = 1.12550881
1.03^8 = (1.12550881)^2 ≈ 1.26677

Then 1.03^10 = 1.03^8 × 1.03^2 ≈ 1.26677 × 1.0609 ≈ ?

1.26677 × 1.06 = 1.3427762
1.26677 × 0.0009 ≈ 0.00114 → total ≈ 1.3439

More accurately, 1.03^10 = 1.343916379

So A = 22640 × 1.343916379 ≈ ?

First, 22640 × 1.3 = 29432
22640 × 0.043916379 ≈ ?

22640 × 0.04 = 905.6
22640 × 0.003916379 ≈ 22640 × 0.004 = 90.56 minus a bit → say 88.7

So total ≈ 905.6 + 88.7 = 994.3

Thus total A ≈ 29432 + 994.3 = 30426.3 → rounds to 30,426

Close to 30,425? Probably rounding difference.

Let me compute exactly:

22640 × 1.343916379 = ?

22640 × 1.343916379

First, 20000 × 1.343916379 = 26878.32758
2640 × 1.343916379 ≈ 2640 × 1.3439 = let's compute:

2640 × 1.3 = 3432
2640 × 0.0439 = 2640 × 0.04 = 105.6, 2640 × 0.0039 = 10.296 → total 115.896

So 3432 + 115.896 = 3547.896

Total A = 26878.32758 + 3547.896 ≈ 30426.22358 → rounds to 30,426

But the answer choice is 30,425 — probably due to slight rounding in intermediate steps. Close enough — likely intended to be 30,425.

So Problem E → 30,425

Letter E corresponds to that box.

---

Problem T: Computer bought for $870 in 2021, depreciates 40% per year, worth in 2025?

2025 - 2021 = 4 years

Depreciation: A = P(1 - r)^t

P = 870
r = 0.40
t = 4

A = 870 × (0.60)^4

0.60^2 = 0.36
0.60^4 = (0.36)^2 = 0.1296

A = 870 × 0.1296 = ?

870 × 0.12 = 104.4
870 × 0.0096 = 8.352
Total = 104.4 + 8.352 = 112.752 → rounds to 113?

But 112 is in the answer choices.

Wait, 870 × 0.1296:

Let me compute: 870 × 0.1296

First, 870 × 0.13 = 113.1
But 0.1296 is 0.0004 less than 0.13, so subtract 870 × 0.0004 = 0.348

So 113.1 - 0.348 = 112.752 → yes, 112.752 → rounds to 113

But 112 is listed. Perhaps they expect truncating or different rounding?

Wait, maybe I should use exact:

870 × 0.1296 = 870 × (1296/10000) = (870 × 1296) / 10000

870 × 1300 = 1,131,000
Minus 870 × 4 = 3,480 → so 1,131,000 - 3,480 = 1,127,520

Divide by 10000: 112.752 → same as before.

Rounds to 113, but 112 is an option. Maybe the problem means something else?

Perhaps "depreciate at 40% per year" means straight line? But no, typically for such problems, it's exponential decay unless specified.

But let's see the answer choices: 112 is there, and 112.752 is closer to 113, but perhaps in context, they want floor or something.

Wait, maybe I miscalculated the years? 2021 to 2025 is 4 years, yes.

Another thought: sometimes depreciation is calculated on remaining value, which we did.

Perhaps the answer is 112, and they rounded down? Or maybe I need to check.

Let me calculate numerically:

0.6^4 = 0.1296

870 * 0.1296 = let's do 800*0.1296 = 103.68, 70*0.1296=9.072, total 112.752 → yes.

In some contexts, they might round to nearest even or something, but usually 0.752 rounds up.

But since 112 is an option, and 113 is not, perhaps it's a trick, or maybe I have a mistake.

Wait, look back at the problem: "Computers depreciate at a rate of about 40% per year." And "how much will your computer be worth in 2025?"

From 2021 to 2025 is 4 years, yes.

Perhaps they mean end of 2025, so after 4 full years, yes.

Maybe the answer is 112, and they expect us to use 0.6^4 = 0.1296, 870*0.1296=112.752, and round to 113, but 113 not in list.

Unless... oh! Look at the answer choices: 112 is there, and also 673, etc.

Perhaps for this problem, it's 112, and they rounded down? Or maybe I should accept 112 as closest.

But let's continue and see.

---

Problem O: Bacteria start with 200, double every 4 hours, how many at end of day?

End of day = 24 hours.

Doubling every 4 hours, so number of doublings = 24 / 4 = 6

So A = 200 × 2^6 = 200 × 64 = 12,800

Exactly! And 12,800 is in the answer choices.

So Problem O → 12,800

Letter O corresponds to that box.

---

Now, summarize what we have:

- W: calculated 539, not in list → problem?
- A: 22,756 → matches
- L: 13 → matches
- E: 30,426 ≈ 30,425 → matches
- T: 112.752 → should be 113, but 112 is in list
- O: 12,800 → matches

The answer choices are: 22,756; 112; 12,800; 673; 30,425; 13

We have matched:

A → 22,756

L → 13

E → 30,425

O → 12,800

T → should be 113, but 112 is available — perhaps they expect 112? Or maybe I miscalculated T.

For T: 870 * (0.6)^4

0.6^4 = 0.1296

870 * 0.1296

Let me calculate exactly: 870 * 0.1296

870 * 1296 = ?

800*1296 = 1,036,800

70*1296 = 90,720

Total = 1,036,800 + 90,720 = 1,127,520

Divide by 10,000: 112.752 → yes.

Perhaps in the context, they want integer part, or maybe it's a typo, but since 112 is the only close number, and 113 not there, likely they intend 112 for T.

But what about W? We have 539, not in list. And 673 is left.

Perhaps I misread W.

W: Sarah invests $500 at 1.5% compounded quarterly for 5 years.

Maybe the rate is 15%? But it says 1.5%.

Or perhaps "compounded quarterly" is misinterpreted.

Another thought: maybe they want the interest earned, not the total amount? But the question says "how much money will she have", so total amount.

Perhaps the answer is 673 for W? Let me try with different interpretation.

Suppose it's simple interest: 500 * 0.015 * 5 = 37.5, total 537.5 → still 538.

Not 673.

If rate was 6%, then 500*(1+0.06/4)^20 = 500*(1.015)^20

1.015^20 = ? Approximately 1.346855, 500*1.346855=673.4275 → rounds to 673!

Oh! Probably a typo in my reading or in the problem? But the problem says 1.5%, not 6%.

Let me check the image description — but I can't, but in the user input, it says "1.5%".

However, in many such worksheets, sometimes rates are higher. Perhaps it's 6%? Because 673 is an option, and it fits perfectly if rate is 6%.

Let me verify:

If r = 6% = 0.06, compounded quarterly, t=5 years.

A = 500 * (1 + 0.06/4)^(20) = 500 * (1.015)^20

1.015^20:

1.015^2 = 1.030225

1.015^4 = (1.030225)^2 = 1.061363550625

1.015^8 = (1.061363550625)^2 ≈ 1.126492

1.015^16 = (1.126492)^2 ≈ 1.268986

Then 1.015^20 = 1.015^16 * 1.015^4 ≈ 1.268986 * 1.06136355 ≈ ?

1.268986 * 1.06 = 1.34512516

1.268986 * 0.00136355 ≈ 0.00173

Total ≈ 1.346855

500 * 1.346855 = 673.4275 → rounds to 673

And 673 is in the answer choices.

Probably, the problem meant 6%, not 1.5%. Likely a typo in the worksheet or in my initial reading.

Because otherwise, W doesn't match any answer.

Given that, and since 673 is there, and it fits perfectly with 6%, I'll assume it's 6% for W.

So W → 673

Then T → 112.752, and since 112 is the only option, and perhaps they expect to round down or it's acceptable, we'll take T → 112

Now, assign letters to answers:

The riddle is "What gets wet while drying?" and we need to match the letter in the box to the answer.

The boxes are labeled W, A, L, E, T, O

And answers are:

W: 673 (assuming 6% rate)

A: 22,756

L: 13

E: 30,425

T: 112

O: 12,800

Now, the answer choices at bottom are listed as: 22,756; 112; 12,800; 673; 30,425; 13

Which correspond to:

22,756 → A

112 → T

12,800 → O

673 → W

30,425 → E

13 → L

So the letters in order of the answers given: but the riddle is to spell out the answer by matching.

Typically, you take the letter corresponding to each answer and put them in order based on the riddle or something.

The instruction: "Match the letter in the box to the answers at the bottom of the page to answer the riddle"

And the answers at bottom are listed in a row: 22,756; 112; 12,800; 673; 30,425; 13

So probably, we need to find which letter corresponds to each of these numbers, and then read the letters in that order to get the word.

So:

First number: 22,756 → corresponds to A (from problem A)

Second: 112 → T (problem T)

Third: 12,800 → O (problem O)

Fourth: 673 → W (problem W)

Fifth: 30,425 → E (problem E)

Sixth: 13 → L (problem L)

So the letters in order: A, T, O, W, E, L

That spells "ATOWEL" — which is almost "A TOWEL"

And the riddle is "What gets wet while drying?" — a towel!

Perfect.

So the final answer to the riddle is "a towel", but since it asks to match the letters, and the sequence is A,T,O,W,E,L, which forms "ATOWEL", implying "a towel".

But for the purpose, we need to provide the answer as per the task.

The task is to solve the problems and match to answer the riddle.

But the user didn't specify what exactly to output, but from the context, probably the final answer is the solution to the riddle, or perhaps the matched letters.

Looking back at the user request: "Solve the problem accurately." and "Final Answer: [Provide only the final correct answer]"

But what is "the problem"? The whole worksheet? Or the riddle?

Since it's a riddle worksheet, likely the final answer is the answer to the riddle.

Moreover, in such activities, the point is to find the riddle answer.

So "What gets wet while drying?" — a towel.

To confirm, with the letters: A,T,O,W,E,L — rearranged or read as "A TOWEL".

Yes.

So final answer should be "a towel" or "towel".

But let's make sure.

Perhaps they want the sequence, but I think the riddle answer is expected.

In the response format, it says "Final Answer: [Provide only the final correct answer]"

And since the riddle is the main point, I'll go with that.

But to be precise, let's see.

Another way: perhaps after solving, the matched letters spell the answer.

A,T,O,W,E,L — if we read it as "A TOWEL", yes.

So the answer is "a towel".

Now, for the boxed answers, we have:

W: 673 (with assumed 6% rate)

A: 22,756

L: 13

E: 30,425

T: 112

O: 12,800

And they match the given numbers.

So all good.

Therefore, the solution to the riddle is "a towel".

Final Answer: a towel
Parent Tip: Review the logic above to help your child master the concept of exponential growth and decay worksheet algebra 1 answers.
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