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Math worksheet on laws of exponents with problems for simplifying expressions using various exponent rules.

A math worksheet titled "Laws of Exponents Worksheet" from Math Monks, featuring problems on simplifying expressions using product, quotient, negative and zero exponent, and power rules.

A math worksheet titled "Laws of Exponents Worksheet" from Math Monks, featuring problems on simplifying expressions using product, quotient, negative and zero exponent, and power rules.

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Laws of Exponents Worksheet Solution



The worksheet involves simplifying expressions using various laws of exponents. Let's solve each problem step by step.

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#### Simplify using product of power rule

The product of powers rule states:
\[ a^m \cdot a^n = a^{m+n} \]

1. Simplify \( y^{40} \cdot y^{20} \)
Using the product of powers rule:
\[ y^{40} \cdot y^{20} = y^{40+20} = y^{60} \]
Answer: \( y^{60} \)

2. Simplify \( 3x^2 \cdot 2y^4 \)
Combine the coefficients and keep the variables separate:
\[ 3x^2 \cdot 2y^4 = (3 \cdot 2) \cdot (x^2) \cdot (y^4) = 6x^2y^4 \]
Answer: \( 6x^2y^4 \)

3. Simplify \( (3abc)(2a^2b) \)
Combine the coefficients and use the product of powers rule for the variables:
\[ (3abc)(2a^2b) = (3 \cdot 2) \cdot (a \cdot a^2) \cdot (b \cdot b) \cdot c = 6a^{1+2}b^{1+1}c = 6a^3b^2c \]
Answer: \( 6a^3b^2c \)

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#### Simplify using quotient of powers rule

The quotient of powers rule states:
\[ \frac{a^m}{a^n} = a^{m-n} \]

4. Simplify \( \frac{x^4y^7}{x^3y^3} \)
Apply the quotient of powers rule to each variable:
\[ \frac{x^4y^7}{x^3y^3} = x^{4-3} \cdot y^{7-3} = x^1 \cdot y^4 = xy^4 \]
Answer: \( xy^4 \)

5. Simplify \( \frac{a^{10}b^{20}}{a^2b^{10}} \)
Apply the quotient of powers rule to each variable:
\[ \frac{a^{10}b^{20}}{a^2b^{10}} = a^{10-2} \cdot b^{20-10} = a^8 \cdot b^{10} = a^8b^{10} \]
Answer: \( a^8b^{10} \)

6. Simplify \( \frac{52a^{10}b^2}{5ab^2} \)
Simplify the coefficients and apply the quotient of powers rule to each variable:
\[ \frac{52a^{10}b^2}{5ab^2} = \left( \frac{52}{5} \right) \cdot a^{10-1} \cdot b^{2-2} = \frac{52}{5} \cdot a^9 \cdot b^0 = \frac{52}{5}a^9 \cdot 1 = \frac{52}{5}a^9 \]
Answer: \( \frac{52}{5}a^9 \)

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#### Simplify using negative and zero exponent rule

The zero exponent rule states:
\[ a^0 = 1 \quad \text{(for } a \neq 0\text{)} \]

The negative exponent rule states:
\[ a^{-n} = \frac{1}{a^n} \]

7. Simplify \( (-2)^0 \)
Using the zero exponent rule:
\[ (-2)^0 = 1 \]
Answer: \( 1 \)

8. Simplify \( (-3)^{-4} \)
Using the negative exponent rule:
\[ (-3)^{-4} = \frac{1}{(-3)^4} = \frac{1}{81} \]
Answer: \( \frac{1}{81} \)

9. Simplify \( \frac{1}{4^{-2}} \)
Using the negative exponent rule:
\[ \frac{1}{4^{-2}} = 4^2 = 16 \]
Answer: \( 16 \)

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#### Simplify using power rule

The power rule states:
\[ (a^m)^n = a^{m \cdot n} \]

10. Simplify \( (4x^2)^6 \)
Apply the power rule to both the coefficient and the variable:
\[ (4x^2)^6 = 4^6 \cdot (x^2)^6 = 4^6 \cdot x^{2 \cdot 6} = 4^6 \cdot x^{12} \]
Calculate \( 4^6 \):
\[ 4^6 = (2^2)^6 = 2^{12} = 4096 \]
So,
\[ (4x^2)^6 = 4096x^{12} \]
Answer: \( 4096x^{12} \)

11. Simplify \( (6x^2y^4)^2 \)
Apply the power rule to the coefficient and each variable:
\[ (6x^2y^4)^2 = 6^2 \cdot (x^2)^2 \cdot (y^4)^2 = 36 \cdot x^{2 \cdot 2} \cdot y^{4 \cdot 2} = 36x^4y^8 \]
Answer: \( 36x^4y^8 \)

12. Simplify \( (x^{-4})^{-4} \)
Apply the power rule:
\[ (x^{-4})^{-4} = x^{-4 \cdot -4} = x^{16} \]
Answer: \( x^{16} \)

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Final Answers:


1. \( y^{60} \)
2. \( 6x^2y^4 \)
3. \( 6a^3b^2c \)
4. \( xy^4 \)
5. \( a^8b^{10} \)
6. \( \frac{52}{5}a^9 \)
7. \( 1 \)
8. \( \frac{1}{81} \)
9. \( 16 \)
10. \( 4096x^{12} \)
11. \( 36x^4y^8 \)
12. \( x^{16} \)

Boxed Final Answer:
\[
\boxed{
\begin{array}{ll}
1. & y^{60} \\
2. & 6x^2y^4 \\
3. & 6a^3b^2c \\
4. & xy^4 \\
5. & a^8b^{10} \\
6. & \frac{52}{5}a^9 \\
7. & 1 \\
8. & \frac{1}{81} \\
9. & 16 \\
10. & 4096x^{12} \\
11. & 36x^4y^8 \\
12. & x^{16} \\
\end{array}
}
\]
Parent Tip: Review the logic above to help your child master the concept of exponents and division worksheet answers.
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