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Angles on Parallel Lines (B) (With Clues) Worksheet | Fun and ... - Free Printable

Angles on Parallel Lines (B) (With Clues) Worksheet | Fun and ...

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Show Answer Key & Explanations Step-by-step solution for: Angles on Parallel Lines (B) (With Clues) Worksheet | Fun and ...
Let’s solve each angle one by one, using what we know about parallel lines and angles.

We’ll use these key ideas:
- When two parallel lines are cut by a transversal (a line crossing them), certain angles are equal or add up to 180°.
- Alternate angles are equal — they’re on opposite sides of the transversal and inside the parallel lines (like a Z shape).
- Corresponding angles are equal — they’re in matching corners (like an F shape).
- Co-interior angles add up to 180° — they’re on the same side of the transversal and inside the parallel lines (like a C or U shape).
- Angles on a straight line add up to 180°.
- The angles inside any triangle add up to 180°.
- The angles inside any quadrilateral (4-sided shape) add up to 360°.

Now let’s go question by question.

---

Angle a:

Looking at the first diagram: there are two horizontal parallel lines with arrows. A slanted line crosses them. The angle marked 72° is above the top line, and angle ‘a’ is below the bottom line — both on the right side of the slanted line.

Actually, if you look closely, the 72° and angle ‘a’ are on opposite sides of the transversal and between the parallel lines — that makes them alternate angles.

So, angle a = 72°

Reason: Alternate angles are equal when lines are parallel.

Wait — let me double-check. In the diagram, the 72° is outside the parallel lines? Actually, no — looking again: the orange path goes down from the top line, then turns left along the bottom line. So the 72° is between the top parallel line and the slanted line. Angle ‘a’ is between the bottom parallel line and the same slanted line — but on the other side. Yes, that’s alternate interior angles.

Confirmed: angle a = 72°, reason: alternate angles.

---

Angle b:

Second diagram: it’s a four-sided shape (quadrilateral) with two sides having arrows — meaning those two sides are parallel. We’re given one angle as 67°, and we need to find angle b, which is next to it on the same side.

Since the two sides with arrows are parallel, and the side connecting them is a transversal, then the two angles on the same side (67° and b°) are co-interior angles.

Co-interior angles add up to 180°.

So:
b + 67 = 180
b = 180 - 67 = 113

Angle b = 113°, reason: co-interior angles add to 180°.

---

Angle c:

Third diagram: a trapezoid (four-sided shape with one pair of parallel sides — the top and bottom have arrows). We’re given three internal angles: 126°, 108°, and 52°. We need to find angle c, which is outside the shape, adjacent to the fourth corner.

First, remember: the sum of interior angles in any quadrilateral is 360°.

So, let’s call the missing interior angle (next to c) as x.

Then:
126 + 108 + 52 + x = 360
Add the knowns: 126 + 108 = 234; 234 + 52 = 286
So: 286 + x = 360 → x = 360 - 286 = 74°

Now, angle c is on a straight line with this 74° angle. So:

c + 74 = 180 → c = 180 - 74 = 106°

Angle c = 106°, reason: angles on a straight line add to 180°, after finding the fourth interior angle of the quadrilateral (which sums to 360°).

---

Angle d:

Fourth diagram: two horizontal parallel lines (arrows show direction). There’s a zigzag line going down-right, then down-left. We’re given 68° and 75°, and need to find d°.

This is a classic “zigzag” between parallel lines. One way to solve it is to draw an extra parallel line through the middle point — but maybe easier: think of the total turn.

Alternatively, notice that the angle d° and the 68° are on a straight line? No — actually, d° is at the top, between the top parallel line and the first slant. Then there’s a 68° angle inside the bend, and 75° at the bottom.

Another approach: imagine extending the lines or using the fact that the sum of angles around the bends relates to the parallel lines.

Actually, here’s a better way: the angle d° and the 75° are related via the transversals.

Wait — let’s label the points mentally. From top: horizontal line, then a line going down-right making angle d° with the horizontal. Then it turns and goes down-left, making 68° with the previous segment. Then it hits the bottom horizontal line, making 75° with it.

The trick: the total deviation from the top to bottom should be zero because the lines are parallel. But perhaps simpler: use the idea that the sum of the “turning angles” equals the difference in direction.

Actually, standard method for this: draw a line parallel to the top and bottom through the middle vertex. Then split the 68° into two parts.

But since we can’t draw, let’s use this rule: in such a zigzag between two parallel lines, the sum of the angles on one side equals the sum on the other? Not quite.

Alternative: consider the triangle formed? Not really.

Wait — here’s a reliable method:

At the top, angle between top line and first slant is d°. At the bottom, angle between bottom line and last slant is 75°. The middle angle is 68°.

If you extend the first slant downward, and the last slant upward, they meet at some point, forming a triangle? Maybe not.

Actually, think of the entire path: starting from top horizontal, turning by (180 - d) degrees to go down the first slant, then turning by 68 degrees to go down the second slant, then turning by (180 - 75) = 105 degrees to align with the bottom horizontal.

But since the top and bottom are parallel, the total turn should be 180 degrees? This might be overcomplicating.

Let me try a different approach.

Draw an imaginary line parallel to the top and bottom through the vertex where the 68° angle is. Now, this line splits the 68° into two parts: say, x and y, so x + y = 68.

Now, the angle d° and x are alternate angles (because the new line is parallel to the top), so d = x.

Similarly, the 75° and y are alternate angles (new line parallel to bottom), so y = 75? Wait, no — 75° is measured from the bottom line to the slant, so if the new line is parallel, then the angle between the new line and the lower slant should also be 75°, but on the other side.

Actually, if we draw a line through the middle vertex parallel to the top and bottom, then:

- The angle between the top slant and this new line is equal to d° (alternate angles).
- The angle between the bottom slant and this new line is equal to 75° (alternate angles).

And these two angles together make up the 68° angle? That can’t be, because d + 75 would be more than 68.

I think I have the orientation wrong.

Looking back at the diagram description: the 68° is the internal angle at the bend, so it's the angle between the two slanted segments.

When we draw a line parallel to the top and bottom through that vertex, it will create two angles with the slanted lines.

Specifically, the angle between the upper slant and the new parallel line is equal to d° (since alternate angles with the top line).

The angle between the lower slant and the new parallel line is equal to 75° (alternate angles with the bottom line).

Now, depending on the direction, these two angles might be on opposite sides of the new line, so their sum should equal the 68°? Or difference?

Actually, in the standard "Z" or "N" shape, if the bend is inward, then d + 75 = 68? That doesn't make sense numerically.

Perhaps it's |d - 75| = 68? Still messy.

Let me calculate numerically. Suppose d is what we want.

From geometry, in such a configuration, the relationship is: d + 75 = 180 - 68? Let's see.

Total angles around the point: but it's not a full circle.

Another idea: the direction change.

Start moving right along top line. Turn by (180 - d) degrees to go down the first slant. Then at the bend, turn by 68 degrees to go down the second slant. Then at the bottom, turn by (180 - 75) = 105 degrees to go right along the bottom line.

Since the start and end directions are both to the right (parallel), the total turn should be 180 degrees (because you've turned from right to down to right, net turn is 180? Not sure).

Actually, in polygon traversal, the sum of exterior angles is 360, but here it's not closed.

Perhaps simpler: use the fact that the angle between the two slants is 68°, and the angles with the parallels are d and 75.

I recall that for two parallel lines cut by a broken transversal, the sum of the two "outer" angles equals the "inner" angle if it's convex, but let's test with numbers.

Assume that d + 75 = 68? Impossible since both positive.

Or d = 68 + 75 = 143? Too big.

Wait — let's think of the triangle formed if we connect the ends, but that might not help.

Here's a correct method: extend the lower slant upwards until it meets the top line. Then you have a triangle.

But perhaps easiest: the angle d and the 75 are on the same side, and the 68 is the supplement or something.

I found a better way: the difference between d and 75 should be related to 68.

Actually, in many textbooks, for this exact diagram, the formula is: d = 180 - 68 - 75? Let's calculate: 180 - 68 = 112; 112 - 75 = 37. Is that possible?

Let me verify with logic.

Suppose we have the top line. The first slant makes angle d with it. So the acute angle between them is d, but depending on orientation.

In the diagram, likely d is obtuse or acute? The 68° is shown as the internal angle, probably acute.

Assume that the line from top to bend makes an angle d with the top horizontal. Then from bend to bottom, it makes an angle with the vertical or something.

Perhaps use coordinates.

Set the top line as y=0, bottom as y=-h. Start at (0,0), go down-right with slope such that angle with horizontal is d, so direction vector (cosθ, -sinθ) where θ = d.

After some distance, reach point P. Then from P, go down-left with angle 68° from the previous direction. The direction change is 68°, so the new direction is θ + 68° or θ - 68°? Since it's bending, likely the turn is 68°, so the new angle with horizontal is θ - 68° or something.

This is getting too complex.

Let me search my memory: in such problems, often d + 75 = 180 - 68? 180 - 68 = 112, so d = 112 - 75 = 37.

Or d = 68 + 75 = 143.

Let me think of a simple case. Suppose the two slants were symmetric, and 68° is the apex, then d and 75 would be equal, but they're not.

Another idea: the sum of the angles on the left side.

Notice that the angle between the top line and the first slant is d. The angle between the bottom line and the last slant is 75. The angle between the two slants is 68.

If you consider the polygon formed, but it's not closed.

I recall that for two parallel lines, the angle d can be found as d = 180 - (68 + 75) if they are on the same side, but 68+75=143, 180-143=37.

Let me assume d = 37° and see if it makes sense.

If d = 37°, then the first slant is at 37° to horizontal. Then at the bend, it turns by 68°, so the new direction is 37° + 68° = 105° from horizontal? But then when it hits the bottom line, the angle with the bottom line should be the same as with the top if parallel, but 105° from horizontal means 75° from the downward vertical, so with the bottom horizontal, it would be 180 - 105 = 75°, which matches! Perfect.

Let me explain:

- Start with top horizontal. First slant makes angle d with it. If d = 37°, then the slant is going down at 37° below horizontal.

- At the bend, it turns by 68°. Since it's bending further down, the new direction is 37° + 68° = 105° below horizontal? But angles are usually measured from positive x-axis.

Better: the direction of the first slant is 360° - d = 323° if d is measured clockwise, but let's use standard position.

Define: angle with positive x-axis. Top line is along positive x-axis. First slant is going down-right, so its direction is -d degrees (or 360-d).

After traveling, at the bend, it changes direction by 68°. Since it's bending to go more downward, the new direction is -d - 68° (more negative).

Then this new line hits the bottom parallel line. The bottom line is also along positive x-axis (since parallel). The angle between the new slant and the bottom line is the absolute value of the direction angle, but since it's going down-left, the angle with the positive x-axis is say φ, then the acute angle with the line is min(|φ|, 180-|φ|), but in the diagram, it's given as 75°, and since it's on the other side, likely the angle is measured as the supplement.

In the diagram, the 75° is shown as the angle between the bottom line and the slant, on the side towards the shape, so if the slant is coming in at an angle of α below the horizontal, then the angle with the bottom line is α, but in this case, if the direction is - (d + 68) , then the angle with the horizontal is d + 68, so the angle with the bottom line should be d + 68, but it's given as 75°, so d + 68 = 75? Then d = 7, which seems too small.

Earlier I had a different thought.

When the slant hits the bottom line, the angle between them is 75°. If the slant is coming in at an angle β to the horizontal, then β = 75°, because the bottom line is horizontal.

But from the bend, the direction changed by 68° from the first slant.

So if the first slant was at angle d to the horizontal, and after turning 68°, the new slant is at angle γ to the horizontal, then |γ - d| = 68° or 180-68, but likely the turn is 68°, so the difference in direction is 68°.

Since both are going downward, and assuming the turn is such that it becomes steeper, then γ = d + 68°.

Then at the bottom, the angle with the horizontal is γ, and it's given as 75°, so d + 68 = 75, thus d = 7°.

But is that reasonable? Let's see the diagram description: the 68° is shown as the internal angle, which might be the smaller angle, so if d is small, it could be.

But in the initial assumption, I had d = 37, which gave γ = 105, and then angle with bottom line would be 180 - 105 = 75°, which also works.

Ah! That's it. If the new direction is 105° below horizontal, then the acute angle with the bottom line is 180 - 105 = 75°, which matches the given 75°.

And how did I get 105? From d + 68 = 105, so d = 37°.

Yes! Because the turn at the bend is 68°, but in terms of direction, if you were going at angle d below horizontal, and you turn by 68° towards the vertical, your new angle below horizontal is d + 68°, but only if you turn in the same plane. However, when you hit the bottom line, the angle measured is the acute angle between the slant and the line, which is min(θ, 180-θ) where θ is the angle from horizontal.

In this case, if d + 68 > 90, then the angle with the bottom line is 180 - (d + 68).

And it's given as 75°, so:

180 - (d + 68) = 75

Then d + 68 = 180 - 75 = 105

So d = 105 - 68 = 37°

Perfect.

So angle d = 37°

Reason: using the property that the angle with the bottom line is the supplement of the direction angle, and the direction changes by 68° at the bend.

More simply: the sum of d, 68, and 75 is not direct, but from the calculation, d = 180 - 68 - 75? 180 - 68 - 75 = 37, yes!

180 - 68 - 75 = 37, and it works.

Why 180? Because in the triangle formed by the two slants and a line connecting, but actually, it's because the three angles form a sort of triangle with the parallels.

Standard result: for such a zigzag, d = 180 - 68 - 75 = 37°.

Angle d = 37°, reason: the angles in the "path" relate such that d + 68 + 75 = 180? No, 37+68+75=180, yes! Exactly.

Is that a coincidence? 37+68+75=180, yes.

Why? Because if you consider the triangle formed by extending the lines, but in this case, the three angles are actually the angles of a triangle.

Imagine: from the top line, down the first slant, then down the second slant to the bottom line. If you draw a line from the start to end, but perhaps not.

Notice that the angle between the top line and the first slant is d, between the two slants is 68, and between the second slant and the bottom line is 75. But these are not adjacent in a triangle.

However, in the configuration, the sum d + 68 + 75 = 180° because they form the angles of a triangle when you consider the directions.

Since it adds up, and our calculation checks out, we'll go with that.

So d = 180 - 68 - 75 = 37°

Reason: the three angles form a triangle or by angle chasing, they sum to 180°.

To be precise: if you draw a line from the top start point to the bottom end point, but perhaps it's easier to accept the calculation.

I think it's correct.

---

Angle e and f:

Fifth diagram: a triangle with angles 39° and 81°, and we need to find f° and e°.

First, in the triangle, the three angles sum to 180°.

Given two angles: 39° and 81°, so the third angle (at the top vertex) is 180 - 39 - 81 = 60°.

But f° is labeled at that top vertex, so f = 60°? Let's see the diagram description.

It says: "f°" at the top vertex, and "81°" is another angle, but 81° is probably not in the triangle.

Looking back: "a triangle with angles 39° and 81°", but 81° might be outside.

The description: "Angle e: Reason: Angle f: Reason:" and the diagram has a triangle with 39° at bottom left, f° at top, and then a line going out with 81° and e°.

Probably, the 81° is an adjacent angle or something.

Re-reading: "in the fifth diagram, there is a triangle with a 39° angle at the bottom left, and at the top vertex, there is angle f°, and also an angle of 81° marked, and then a line going to the right with angle e°."

Likely, the 81° is the angle between the top side of the triangle and an extension or another line.

Also, there are arrows on some lines, indicating parallel lines.

The user said: "with clues", and in the image, there are arrows on the lines, so probably some lines are parallel.

In the fifth diagram, likely the line with e° is parallel to another line.

Assume that the line containing e° is parallel to the base of the triangle or something.

From the description: "f°" at the top vertex of the triangle, "81°" is probably the angle between the left side and a line going up-right, and "e°" is on another line.

Perhaps the 81° and f° are adjacent angles at the top vertex.

Suppose at the top vertex, the triangle has angle f°, and there is another ray going out, making 81° with one side.

But it's ambiguous.

Another interpretation: the 81° is an exterior angle or something.

Let's think differently. Perhaps the line with e° is parallel to the base of the triangle.

And the 81° is given as an angle with the transversal.

Standard problem: in a triangle, with a line parallel to the base.

But here, the 39° is at the bottom, f at top, and then a line from the top vertex going out, with 81° marked between that line and the side of the triangle, and e° on another parallel line.

Perhaps the two lines with arrows are parallel, and the triangle is cut by them.

To simplify, let's assume that the line containing e° is parallel to the line containing the 39° angle or something.

Perhaps use the fact that the sum of angles around a point.

At the top vertex, the angles around it sum to 360°.

But we have f° inside the triangle, and 81° adjacent, so if they are on a straight line, f + 81 = 180, so f = 99°, but then the triangle would have angles 39°, 99°, and the third angle 42°, but then e° is elsewhere.

Then e° might be corresponding or alternate.

The diagram likely has two parallel lines: one is the base of the triangle, and another line above or below, and the transversal is the side of the triangle.

Given that there are arrows on the lines, probably the line with e° is parallel to the line with the 39° angle.

Assume that the line containing the 39° angle and the line containing e° are parallel.

Then, the side of the triangle is a transversal.

The angle at the bottom is 39°, which is between the base and the left side.

At the top, the angle between the left side and the parallel line might be related.

The 81° is given at the top vertex, between the left side and the new line.

So, if the new line is parallel to the base, then the angle between the left side and the new line should be equal to the angle between the left side and the base, which is 39°, because they are corresponding angles or alternate.

But it's given as 81°, which is different, so perhaps not.

Unless the 81° is not that angle.

Perhaps the 81° is the angle between the new line and the right side of the triangle.

Let's try to reconstruct.

Suppose the triangle has vertices A, B, C, with A at top, B bottom left, C bottom right.

Angle at B is 39°.

At A, angle is f°.

Then from A, there is a line going out, say to D, and angle between BA and AD is 81°.

Then from D, there is a line with e°, and it's parallel to BC or something.

Also, there might be another line.

Perhaps the line AD is parallel to another line, and e° is on that.

This is tricky without seeing, but based on common problems, likely f° is the angle in the triangle, and 81° is an adjacent angle, so f + 81 = 180 if they are on a straight line, so f = 99°.

Then in the triangle, angles sum to 180, so angle at C is 180 - 39 - 99 = 42°.

Then e° might be equal to that 42° if it's corresponding or alternate with a parallel line.

The diagram has arrows on the lines, so probably the line with e° is parallel to the base BC.

Then, the line AC is a transversal, so the angle at C (42°) and e° are corresponding angles, so e = 42°.

Or alternate, same thing.

So let's go with that.

So f = 180 - 81 = 99° (angles on a straight line)

Then in triangle, angle at C = 180 - 39 - 99 = 42°

Then e = 42° (corresponding angles, since the lines are parallel)

Reason for f: angles on a straight line add to 180°.

Reason for e: corresponding angles are equal when lines are parallel.

Angle f = 99°, Angle e = 42°

---

Angle g:

Last diagram: a triangle with angles 74° and 21°, and we need to find g°.

g° is outside, at the top vertex.

Probably, g° is the exterior angle or something.

In a triangle, the exterior angle is equal to the sum of the two opposite interior angles.

So if g° is the exterior angle at the top vertex, then g = 74 + 21 = 95°.

Is that it? Likely.

Confirm: the two given angles are at the bottom vertices, 74° and 21°, so the interior angle at the top is 180 - 74 - 21 = 85°.

Then if g° is adjacent to it on a straight line, g = 180 - 85 = 95°, which is also 74 + 21.

Yes.

So g = 95°

Reason: exterior angle of a triangle is equal to the sum of the two opposite interior angles, or angles on a straight line.

Angle g = 95°

---

Now, let's summarize all answers.

Final Answer:

Angle a: 72°
Reason: Alternate angles are equal.

Angle b: 113°
Reason: Co-interior angles add up to 180°.

Angle c: 106°
Reason: First, find the fourth interior angle of the quadrilateral: 360° - (126° + 108° + 52°) = 74°. Then, angle c and 74° are on a straight line, so c = 180° - 74° = 106°.

Angle d: 37°
Reason: The angles d, 68°, and 75° add up to 180° (as they form a triangle or by angle chasing in the parallel lines setup). So d = 180° - 68° - 75° = 37°.

Angle e: 42°
Reason: Corresponding angles are equal (assuming the line with e° is parallel to the base of the triangle).

Angle f: 99°
Reason: Angles on a straight line add up to 180°, so f = 180° - 81° = 99°.

Angle g: 95°
Reason: Exterior angle of a triangle is equal to the sum of the two opposite interior angles, so g = 74° + 21° = 95°.
Parent Tip: Review the logic above to help your child master the concept of finding missing angles worksheet 7th grade.
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