Finding the Average Word Problems Worksheet - Free Printable

Let’s solve each problem one by one. To find the average, we add up all the numbers and then divide by how many numbers there are.

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Problem 1:
Scores: 89, 90, 95, 72, 83, 100, 94
Add them:
89 + 90 = 179
179 + 95 = 274
274 + 72 = 346
346 + 83 = 429
429 + 100 = 529
529 + 94 = 623

There are 7 scores → Divide 623 ÷ 7 = 89

✔ Average Science test score: 89

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Problem 2:
Miles: 345, 279, 583, 404, 556, 702, 636
Add them:
345 + 279 = 624
624 + 583 = 1,207
1,207 + 404 = 1,611
1,611 + 556 = 2,167
2,167 + 702 = 2,869
2,869 + 636 = 3,505

There are 7 trips → Divide 3,505 ÷ 7 = 500.714... → Round to nearest whole number? Let’s check exact division:

3,505 ÷ 7 = 500.714… but since miles can be decimal, maybe keep as is? Wait — let me recalculate sum to be sure.

Double-check addition:
345
+279 = 624
+583 = 1,207
+404 = 1,611
+556 = 2,167
+702 = 2,869
+636 = 3,505 ✔

3,505 ÷ 7 = 500.714... But in context, maybe they expect rounded or exact? Let’s do exact fraction or decimal.

Actually, 7 × 500 = 3,500 → remainder 5 → so 500 and 5/7 ≈ 500.71

But looking at other problems, some have decimals. So we’ll write it as 500.71 if rounding to two decimals, or leave as fraction? The problem doesn’t specify. Since mileage is often recorded as whole numbers, but average can be decimal.

Wait — let me calculate again carefully:

345 + 279 = 624
624 + 583 = 1,207
1,207 + 404 = 1,611
1,611 + 556 = 2,167
2,167 + 702 = 2,869
2,869 + 636 = 3,505 → correct.

3,505 ÷ 7 = 500.7142857...

In school worksheets, sometimes they expect you to round to nearest tenth or whole number. But since no instruction, I’ll go with exact value: 500.71 (rounded to two decimals) OR perhaps they want it as a mixed number? No, probably decimal.

Wait — let me see if it divides evenly? 7 × 500 = 3500, 3505 - 3500 = 5 → so 500 + 5/7 → 500.714...

I think for this level, they might accept 500.7 or 501? But let’s hold on — maybe I made a mistake.

Alternative: Use calculator-style adding:

345
279 → 624
583 → 1207
404 → 1611
556 → 2167
702 → 2869
636 → 3505 → yes.

3505 ÷ 7 = 500.714... → I'll write 500.71 for now, but let’s move on and come back if needed.

Actually, looking at Problem 3, they have money with cents, so decimals are fine. For consistency, I’ll use two decimals where needed.

But 3505 ÷ 7 is exactly 500.7142857... so perhaps write as 500.71 if rounding to hundredths.

Wait — let me check online or think: 7 * 500.7142857 = 3505, yes.

But in many elementary contexts, they might expect you to leave it as a fraction or round. However, since the next problem has dollars and cents, I’ll assume decimals are okay.

Actually, let me proceed and verify later.

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Problem 3:
Prices: $24.65, $20.99, $25.59, $26.90, $27.10, $22.36

Add them step by step:

Start with 24.65 + 20.99 = 45.64
45.64 + 25.59 = 71.23
71.23 + 26.90 = 98.13
98.13 + 27.10 = 125.23
125.23 + 22.36 = 147.59

There are 6 prices → Divide 147.59 ÷ 6

Calculate: 147.59 ÷ 6

6 × 24 = 144 → subtract: 147.59 - 144 = 3.59
3.59 ÷ 6 = 0.598333...

So total = 24 + 0.598333 = 24.598333...

Rounded to nearest cent (since it's money): $24.60

Check: 6 × 24.60 = 147.60 → which is 1 cent more than 147.59 → so actually 24.598333 is closer to 24.60? 24.598333 rounds to 24.60 when to two decimals.

Yes, because third decimal is 8 > 5 → round up 24.59 → wait no:

24.598333 → look at thousandths place: 8 ≥ 5 → so round up the hundredths: 9 becomes 10 → so 24.60

Yes → $24.60

✔ Average price: $24.60

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Problem 4:
Temperatures: 78°, 82°, 85°, 74°, 98°, 90°, 80°, 62°, 71°, 91° → 10 days

Add them:

Group to make easier:

78 + 82 = 160
85 + 74 = 159
98 + 90 = 188
80 + 62 = 142
71 + 91 = 162

Now add those: 160 + 159 = 319
319 + 188 = 507
507 + 142 = 649
649 + 162 = 811

Total = 811
Number of days = 10 → 811 ÷ 10 = 81.1

✔ Average temperature: 81.1°F

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Problem 5:
Weights: 45,824 lbs; 56,189 lbs; 71,291 lbs; 30,219 lbs; 89,331 lbs

Add them:

First, 45,824 + 56,189 = 102,013
102,013 + 71,291 = 173,304
173,304 + 30,219 = 203,523
203,523 + 89,331 = 292,854

There are 5 containers → Divide 292,854 ÷ 5

292,854 ÷ 5 = ?

5 × 58,000 = 290,000
Subtract: 292,854 - 290,000 = 2,854
2,854 ÷ 5 = 570.8
So total = 58,000 + 570.8 = 58,570.8

Or directly: 292,854 ÷ 5 = 58,570.8

✔ Average weight: 58,570.8 lbs

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Problem 6:
Lights: a. 7,465; b. 9,556; c. 7,120; d. 10,229; e. 8,089 → 5 venues

Add them:

7,465 + 9,556 = 17,021
17,021 + 7,120 = 24,141
24,141 + 10,229 = 34,370
34,370 + 8,089 = 42,459

Divide by 5: 42,459 ÷ 5

5 × 8,000 = 40,000
Subtract: 42,459 - 40,000 = 2,459
2,459 ÷ 5 = 491.8
So total = 8,000 + 491.8 = 8,491.8

Or 42,459 ÷ 5 = 8,491.8

✔ Average number of lights: 8,491.8

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Now back to Problem 2: Miles were 345, 279, 583, 404, 556, 702, 636 → sum 3,505 ÷ 7

Let me compute exactly: 3,505 ÷ 7

7 × 500 = 3,500 → remainder 5 → so 500 + 5/7 = 500.7142857...

In most school settings, unless specified, they might expect it rounded to nearest whole number or one decimal. But since Problem 3 had money to cents, and Problem 5 and 6 have decimals, I think it’s safe to write as 500.71 if rounding to two decimals, or perhaps they want exact fraction? But unlikely.

Looking at the worksheet, all answers are likely expected as decimals or whole numbers. Let me see if 3,505 ÷ 7 is meant to be integer? 7×500=3500, 3505-3500=5, not divisible.

Perhaps I misadded? Let me add again:

List: 345, 279, 583, 404, 556, 702, 636

Add in pairs:

345 + 636 = 981
279 + 702 = 981
583 + 556 = 1,139
And 404 left.

Now: 981 + 981 = 1,962
1,962 + 1,139 = 3,101
3,101 + 404 = 3,505 → same.

So 3,505 ÷ 7 = 500.7142857...

I think for consistency, since other averages have decimals, I’ll write it as 500.71 (rounded to two decimal places).

But let me confirm with another method: 7 × 500.71 = 7×500 = 3500, 7×0.71=4.97, total 3504.97 → close to 3505, difference due to rounding.

Actually, 500.7142857 × 7 = 3505 exactly.

So perhaps write as 500.71 or 500.7? In many cases, they might expect one decimal.

Looking at Problem 4: 81.1 (one decimal), Problem 5: 58,570.8 (one decimal), Problem 6: 8,491.8 (one decimal), Problem 3: $24.60 (two decimals for money).

For miles, probably one decimal is fine. 3,505 ÷ 7 = 500.714... → to one decimal: 500.7

Because 0.714 rounds to 0.7? No: 0.714 to one decimal: look at second decimal is 1 < 5, so 0.7? Wait no:

500.714 → tenths place is 7, hundredths is 1 → since 1<5, don't round up → so 500.7

But 500.714 is closer to 500.7 than 500.8? Yes.

However, 500.714 × 7 = 3504.998 ≈ 3505, so it's fine.

I think 500.7 is acceptable.

To match the precision of other non-money answers, I'll use one decimal place.

So for Problem 2: 500.7

Final decision:

Problem 1: 89 (whole number)

Problem 2: 500.7

Problem 3: 24.60

Problem 4: 81.1

Problem 5: 58,570.8

Problem 6: 8,491.8

All seem consistent.

Now compile final answers.

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Final Answer:
1. 89
2. 500.7
3. 24.60
4. 81.1
5. 58,570.8
6. 8,491.8