Force - MA Notes Worksheet online exercise for - Free Printable
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Step-by-step solution for: Force - MA Notes Worksheet online exercise for
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Show Answer Key & Explanations
Step-by-step solution for: Force - MA Notes Worksheet online exercise for
Let’s go through each problem one by one, using the equations:
F = m × a
a = F ÷ m
m = F ÷ a
Remember:
- Mass (m) is in kg
- Force (F) is in newtons (N)
- Acceleration (a) is in m/s²
---
Problem 1:
How much force is needed to accelerate a 66 kg skier at 2 m/s²?
→ Use F = m × a
→ F = 66 × 2 = 132 N
✔ Check: 66 × 2 = 132 → Correct.
---
Problem 2:
What is the force on a 1000 kg elevator that is falling freely at 9.8 m/s²?
→ Falling freely means acceleration = gravity = 9.8 m/s²
→ F = m × a = 1000 × 9.8 = 9800 N
✔ Check: 1000 × 9.8 = 9800 → Correct.
---
Problem 3:
What is the acceleration of a 50 kg object pushed with a force of 500 newtons?
→ Use a = F ÷ m
→ a = 500 ÷ 50 = 10 m/s²
✔ Check: 500 ÷ 50 = 10 → Correct.
---
Problem 4:
The mass of a large car is 1000 kg. How much force would be required to accelerate the car at a rate of 3 m/s²?
→ F = m × a = 1000 × 3 = 3000 N
✔ Check: 1000 × 3 = 3000 → Correct.
---
Problem 5:
A 50 kg skater pushed by a friend accelerates 5 m/s². How much force did the friend apply?
→ F = m × a = 50 × 5 = 250 N
✔ Check: 50 × 5 = 250 → Correct.
---
Problem 6:
A force of 250 N is applied to an object that accelerates at a rate of 5 m/s². What is the mass of the object?
→ m = F ÷ a = 250 ÷ 5 = 50 kg
✔ Check: 250 ÷ 5 = 50 → Correct.
---
Problem 7:
A bowling ball rolled with a force of 15 N accelerates at a rate of 3 m/s²; a second ball rolled with the same force accelerates 4 m/s². What are the masses of the two balls?
→ First ball: m = F ÷ a = 15 ÷ 3 = 5 kg
→ Second ball: m = 15 ÷ 4 = 3.75 kg
✔ Check:
15 ÷ 3 = 5 → Correct
15 ÷ 4 = 3.75 → Correct
---
Problem 8:
If a 60 kg person on a 15 kg sled is pushed with a force of 300 N, what will be person’s acceleration?
→ Total mass = 60 + 15 = 75 kg
→ a = F ÷ m = 300 ÷ 75 = 4 m/s²
✔ Check: 300 ÷ 75 = 4 → Correct.
---
Problem 9:
A force of 20 N acts upon a 5 kg block. Calculate the acceleration of the object.
→ a = F ÷ m = 20 ÷ 5 = 4 m/s²
✔ Check: 20 ÷ 5 = 4 → Correct.
---
Problem 10:
An object of mass 300 kg is observed to accelerate at the rate of 4 m/s². Calculate the force required to produce this acceleration.
→ F = m × a = 300 × 4 = 1200 N
✔ Check: 300 × 4 = 1200 → Correct.
---
Problem 11:
A 5 kg block is pulled across a table by a horizontal force of 40 N with a frictional force of 8 N opposing the motion. Calculate the acceleration of the object.
→ Net force = applied force – friction = 40 – 8 = 32 N
→ a = F_net ÷ m = 32 ÷ 5 = 6.4 m/s²
✔ Check: 40 – 8 = 32; 32 ÷ 5 = 6.4 → Correct.
---
Problem 12:
An object of mass 30 kg is in free fall in a vacuum where there is no air resistance. Determine the acceleration of the object.
→ In free fall (no air resistance), acceleration = gravity = 9.8 m/s²
✔ This is a standard fact — no calculation needed.
---
Problem 13:
An object of mass 30 kg is falling in air and experiences a force due to air resistance of 50 newtons.
a. Determine the net force acting on the object
b. Calculate the acceleration of the object.
→ Gravity pulls down: F_gravity = m × g = 30 × 9.8 = 294 N
→ Air resistance pushes up: 50 N
→ Net force = 294 – 50 = 244 N (downward)
→ a = F_net ÷ m = 244 ÷ 30 ≈ 8.13 m/s² (rounded to two decimals)
✔ Check:
30 × 9.8 = 294 → Correct
294 – 50 = 244 → Correct
244 ÷ 30 = 8.133... → Rounded to 8.13 → Correct
---
Final Answer:
1. 132 N
2. 9800 N
3. 10 m/s²
4. 3000 N
5. 250 N
6. 50 kg
7. 5 kg and 3.75 kg
8. 4 m/s²
9. 4 m/s²
10. 1200 N
11. 6.4 m/s²
12. 9.8 m/s²
13. a. 244 N, b. 8.13 m/s²
F = m × a
a = F ÷ m
m = F ÷ a
Remember:
- Mass (m) is in kg
- Force (F) is in newtons (N)
- Acceleration (a) is in m/s²
---
Problem 1:
How much force is needed to accelerate a 66 kg skier at 2 m/s²?
→ Use F = m × a
→ F = 66 × 2 = 132 N
✔ Check: 66 × 2 = 132 → Correct.
---
Problem 2:
What is the force on a 1000 kg elevator that is falling freely at 9.8 m/s²?
→ Falling freely means acceleration = gravity = 9.8 m/s²
→ F = m × a = 1000 × 9.8 = 9800 N
✔ Check: 1000 × 9.8 = 9800 → Correct.
---
Problem 3:
What is the acceleration of a 50 kg object pushed with a force of 500 newtons?
→ Use a = F ÷ m
→ a = 500 ÷ 50 = 10 m/s²
✔ Check: 500 ÷ 50 = 10 → Correct.
---
Problem 4:
The mass of a large car is 1000 kg. How much force would be required to accelerate the car at a rate of 3 m/s²?
→ F = m × a = 1000 × 3 = 3000 N
✔ Check: 1000 × 3 = 3000 → Correct.
---
Problem 5:
A 50 kg skater pushed by a friend accelerates 5 m/s². How much force did the friend apply?
→ F = m × a = 50 × 5 = 250 N
✔ Check: 50 × 5 = 250 → Correct.
---
Problem 6:
A force of 250 N is applied to an object that accelerates at a rate of 5 m/s². What is the mass of the object?
→ m = F ÷ a = 250 ÷ 5 = 50 kg
✔ Check: 250 ÷ 5 = 50 → Correct.
---
Problem 7:
A bowling ball rolled with a force of 15 N accelerates at a rate of 3 m/s²; a second ball rolled with the same force accelerates 4 m/s². What are the masses of the two balls?
→ First ball: m = F ÷ a = 15 ÷ 3 = 5 kg
→ Second ball: m = 15 ÷ 4 = 3.75 kg
✔ Check:
15 ÷ 3 = 5 → Correct
15 ÷ 4 = 3.75 → Correct
---
Problem 8:
If a 60 kg person on a 15 kg sled is pushed with a force of 300 N, what will be person’s acceleration?
→ Total mass = 60 + 15 = 75 kg
→ a = F ÷ m = 300 ÷ 75 = 4 m/s²
✔ Check: 300 ÷ 75 = 4 → Correct.
---
Problem 9:
A force of 20 N acts upon a 5 kg block. Calculate the acceleration of the object.
→ a = F ÷ m = 20 ÷ 5 = 4 m/s²
✔ Check: 20 ÷ 5 = 4 → Correct.
---
Problem 10:
An object of mass 300 kg is observed to accelerate at the rate of 4 m/s². Calculate the force required to produce this acceleration.
→ F = m × a = 300 × 4 = 1200 N
✔ Check: 300 × 4 = 1200 → Correct.
---
Problem 11:
A 5 kg block is pulled across a table by a horizontal force of 40 N with a frictional force of 8 N opposing the motion. Calculate the acceleration of the object.
→ Net force = applied force – friction = 40 – 8 = 32 N
→ a = F_net ÷ m = 32 ÷ 5 = 6.4 m/s²
✔ Check: 40 – 8 = 32; 32 ÷ 5 = 6.4 → Correct.
---
Problem 12:
An object of mass 30 kg is in free fall in a vacuum where there is no air resistance. Determine the acceleration of the object.
→ In free fall (no air resistance), acceleration = gravity = 9.8 m/s²
✔ This is a standard fact — no calculation needed.
---
Problem 13:
An object of mass 30 kg is falling in air and experiences a force due to air resistance of 50 newtons.
a. Determine the net force acting on the object
b. Calculate the acceleration of the object.
→ Gravity pulls down: F_gravity = m × g = 30 × 9.8 = 294 N
→ Air resistance pushes up: 50 N
→ Net force = 294 – 50 = 244 N (downward)
→ a = F_net ÷ m = 244 ÷ 30 ≈ 8.13 m/s² (rounded to two decimals)
✔ Check:
30 × 9.8 = 294 → Correct
294 – 50 = 244 → Correct
244 ÷ 30 = 8.133... → Rounded to 8.13 → Correct
---
Final Answer:
1. 132 N
2. 9800 N
3. 10 m/s²
4. 3000 N
5. 250 N
6. 50 kg
7. 5 kg and 3.75 kg
8. 4 m/s²
9. 4 m/s²
10. 1200 N
11. 6.4 m/s²
12. 9.8 m/s²
13. a. 244 N, b. 8.13 m/s²
Parent Tip: Review the logic above to help your child master the concept of force and mass worksheet.
