Molar Mass Worksheet – Elements Molar Mass - Worksheets Library - Free Printable

Let’s solve each compound step by step. We’ll calculate the molar mass by adding up the atomic masses of all atoms in the formula. Atomic masses are rounded to nearest 0.1 g/mol as instructed.

We’ll use these standard atomic masses (rounded to 0.1):
- H = 1.0
- C = 12.0
- N = 14.0
- O = 16.0
- Na = 23.0
- Mg = 24.3 → but we’ll use 24.3? Wait — instruction says round to nearest 0.1, so let’s check common values used in such worksheets:
Actually, for consistency with the example given (Ba(NO₃)₂ uses Ba=137.3, N=14.0, O=16.0), we’ll use:

Standard rounded atomic masses (to 0.1 g/mol) commonly used in high school:
- H = 1.0
- C = 12.0
- N = 14.0
- O = 16.0
- Na = 23.0
- Mg = 24.3 → but since example uses whole numbers except Ba, and says “round all atomic masses to nearest 0.1”, we’ll use precise rounding:
Actually, let’s stick to typical textbook values rounded to 0.1:
- H: 1.0
- C: 12.0
- N: 14.0
- O: 16.0
- Na: 23.0
- Ca: 40.1
- Al: 27.0
- S: 32.1
- Cl: 35.5
- Ba: 137.3 (as given)
- Mg: 24.3

But note: In the example, they used:
Ba: 137.3
N: 14.0
O: 16.0

So we’ll follow that pattern — use atomic masses rounded to 0.1 as per periodic table standard values.

Let me list them clearly:

Atomic Masses (g/mol, rounded to 0.1):
- H: 1.0
- C: 12.0
- N: 14.0
- O: 16.0
- Na: 23.0
- Mg: 24.3
- Ca: 40.1
- Al: 27.0
- S: 32.1
- Cl: 35.5
- Ba: 137.3 (given)

Also:
- For NH₄CH₂CO₂H — this is glycine, but we’ll break it down atom by atom.

Now, let’s go compound by compound.

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1. NaOH

Elements: Na, O, H

Atoms:
- Na: 1 × 23.0 = 23.0
- O: 1 × 16.0 = 16.0
- H: 1 × 1.0 = 1.0

Total = 23.0 + 16.0 + 1.0 = 40.0 g/mol

Type: formula mass (ionic compound)

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2. Na₂CO₃

Elements: Na, C, O

Atoms:
- Na: 2 × 23.0 = 46.0
- C: 1 × 12.0 = 12.0
- O: 3 × 16.0 = 48.0

Total = 46.0 + 12.0 + 48.0 = 106.0 g/mol

Type: formula mass

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3. CaCl₂

Elements: Ca, Cl

Atoms:
- Ca: 1 × 40.1 = 40.1
- Cl: 2 × 35.5 = 71.0

Total = 40.1 + 71.0 = 111.1 g/mol

Type: formula mass

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4. Al₂(SO₄)₃

Breakdown: Al₂ S₃ O₁₂ (because SO₄ has 1 S and 4 O; times 3 → 3 S, 12 O)

Atoms:
- Al: 2 × 27.0 = 54.0
- S: 3 × 32.1 = 96.3
- O: 12 × 16.0 = 192.0

Total = 54.0 + 96.3 + 192.0 = 342.3 g/mol

Type: formula mass

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5. magnesium hydroxide → Mg(OH)₂

Formula: Mg(OH)₂ → Mg, O₂, H₂

Atoms:
- Mg: 1 × 24.3 = 24.3
- O: 2 × 16.0 = 32.0
- H: 2 × 1.0 = 2.0

Total = 24.3 + 32.0 + 2.0 = 58.3 g/mol

Type: formula mass

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6. NH₃

Elements: N, H

Atoms:
- N: 1 × 14.0 = 14.0
- H: 3 × 1.0 = 3.0

Total = 14.0 + 3.0 = 17.0 g/mol

Type: molecular mass (covalent molecule)

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7. CO₂

Elements: C, O

Atoms:
- C: 1 × 12.0 = 12.0
- O: 2 × 16.0 = 32.0

Total = 12.0 + 32.0 = 44.0 g/mol

Type: molecular mass

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8. C₆H₁₂O₆

Elements: C, H, O

Atoms:
- C: 6 × 12.0 = 72.0
- H: 12 × 1.0 = 12.0
- O: 6 × 16.0 = 96.0

Total = 72.0 + 12.0 + 96.0 = 180.0 g/mol

Type: molecular mass

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9. CH₃OH (methanol)

Formula: C H₄ O (since CH₃OH = C + 4H + O)

Atoms:
- C: 1 × 12.0 = 12.0
- H: 4 × 1.0 = 4.0
- O: 1 × 16.0 = 16.0

Total = 12.0 + 4.0 + 16.0 = 32.0 g/mol

Type: molecular mass

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10. CH₃CO₂H (acetic acid)

Formula: C₂H₄O₂ (CH₃CO₂H = 2C, 4H, 2O)

Atoms:
- C: 2 × 12.0 = 24.0
- H: 4 × 1.0 = 4.0
- O: 2 × 16.0 = 32.0

Total = 24.0 + 4.0 + 32.0 = 60.0 g/mol

Type: molecular mass

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11. NH₄CH₂CO₂H (glycine)

Let’s count atoms carefully:

NH₄CH₂CO₂H → Break into parts:

- N from NH₄
- H from NH₄: 4 H
- Then CH₂: 1 C, 2 H
- Then CO₂H: 1 C, 2 O, 1 H (the H at end is acidic hydrogen)

Wait — better to write full formula: Glycine is H₂N–CH₂–COOH → which is C₂H₅NO₂

Confirm:
- Carbon: 2 (one in CH₂, one in COOH)
- Hydrogen: 5 (2 in NH₂, 2 in CH₂, 1 in COOH) — wait no:

Standard glycine: NH₂CH₂COOH

Atoms:
- N: 1
- H: from NH₂ → 2H, from CH₂ → 2H, from COOH → 1H → total H = 5
- C: 2 (CH₂ and COOH)
- O: 2 (from COOH)

Yes: C₂H₅NO₂

So:

Atoms:
- C: 2 × 12.0 = 24.0
- H: 5 × 1.0 = 5.0
- N: 1 × 14.0 = 14.0
- O: 2 × 16.0 = 32.0

Total = 24.0 + 5.0 + 14.0 + 32.0 = 75.0 g/mol

Type: molecular mass

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Now, let’s compile all answers in order as they appear on the worksheet.

Worksheet order:

Left column:
1. Ba(NO₃)₂ — already done: 261.3 g/mol (formula mass)
2. NaOH → 40.0 g/mol (formula mass)
3. Na₂CO₃ → 106.0 g/mol (formula mass)
4. CaCl₂ → 111.1 g/mol (formula mass)
5. Al₂(SO₄)₃ → 342.3 g/mol (formula mass)
6. magnesium hydroxide → 58.3 g/mol (formula mass)

Right column:
7. NH₃ → 17.0 g/mol (molecular mass)
8. CO₂ → 44.0 g/mol (molecular mass)
9. C₆H₁₂O₆ → 180.0 g/mol (molecular mass)
10. CH₃OH → 32.0 g/mol (molecular mass)
11. CH₃CO₂H → 60.0 g/mol (molecular mass)
12. NH₄CH₂CO₂H → 75.0 g/mol (molecular mass)

Note: The worksheet has "Type" field — for ionic compounds (like salts, metal + nonmetal or polyatomic ions), we say “formula mass”. For covalent molecules (nonmetals only), we say “molecular mass”.

All left-side compounds are ionic → formula mass.
All right-side except possibly some are molecular → molecular mass.

NH₃, CO₂, C₆H₁₂O₆, CH₃OH, CH₃CO₂H, NH₄CH₂CO₂H — all are covalent molecules → molecular mass.

Even though NH₄⁺ is ion, in NH₄CH₂CO₂H it's part of a molecular compound (amino acid), so still called molecular mass.

Okay, now final answer should be presented as filled tables? But user didn’t specify format. Since it’s a worksheet, perhaps list each with its molar mass and type.

But instruction says: “Final Answer: [Provide only the final correct answer]”

Since there are multiple compounds, I think we need to provide all calculated molar masses and types.

Perhaps list them in order.

Alternatively, since the worksheet has blanks, maybe just give the totals and types.

I think best is to present each compound with its molar mass and type.

But to match “final answer” format, perhaps:

Final Answer:

NaOH: 40.0 g/mol, formula mass
Na₂CO₃: 106.0 g/mol, formula mass
CaCl₂: 111.1 g/mol, formula mass
Al₂(SO₄)₃: 342.3 g/mol, formula mass
Mg(OH)₂: 58.3 g/mol, formula mass
NH₃: 17.0 g/mol, molecular mass
CO₂: 44.0 g/mol, molecular mass
C₆H₁₂O₆: 180.0 g/mol, molecular mass
CH₃OH: 32.0 g/mol, molecular mass
CH₃CO₂H: 60.0 g/mol, molecular mass
NH₄CH₂CO₂H: 75.0 g/mol, molecular mass

(Note: Ba(NO₃)₂ was already completed as 261.3 g/mol, formula mass)

But since the question is to calculate for the following compounds, and Ba(NO₃)₂ is example, we don't include it in answer? Or do we?

Looking back: “Calculate the molar mass of the following compounds...” and lists several, including Ba(NO₃)₂ which is already filled. So probably we start from NaOH onwards.

In the image, Ba(NO₃)₂ is shown as example with answer, then next is NaOH, etc.

So our answer should cover all blank ones.

To be safe, I'll include all that need calculation.

But in final answer section, perhaps just the numerical results in order.

Since it's a worksheet, maybe present as:

For NaOH: Total = 40.0 g/mol, Type = formula mass
... and so on.

But instruction says "only the final correct answer", so perhaps a concise list.

I think the expected output is the molar masses and types for each compound listed after the example.

Let me list them in the order they appear on the page, skipping the example.

Order on worksheet:

After Ba(NO₃)₂:

Left column:
- NaOH
- Na₂CO₃
- CaCl₂
- Al₂(SO₄)₃
- magnesium hydroxide

Right column:
- NH₃
- CO₂
- C₆H₁₂O₆
- CH₃OH
- CH₃CO₂H
- NH₄CH₂CO₂H

So 11 compounds to fill.

Final Answer will be their molar masses and types.

To make it clear:

Final Answer:
NaOH: 40.0 g/mol, formula mass
Na₂CO₃: 106.0 g/mol, formula mass
CaCl₂: 111.1 g/mol, formula mass
Al₂(SO₄)₃: 342.3 g/mol, formula mass
Mg(OH)₂: 58.3 g/mol, formula mass
NH₃: 17.0 g/mol, molecular mass
CO₂: 44.0 g/mol, molecular mass
C₆H₁₂O₆: 180.0 g/mol, molecular mass
CH₃OH: 32.0 g/mol, molecular mass
CH₃CO₂H: 60.0 g/mol, molecular mass
NH₄CH₂CO₂H: 75.0 g/mol, molecular mass

I think that's complete.

Double-check calculations:

NaOH: 23+16+1=40 ✓
Na₂CO₃: 46+12+48=106 ✓
CaCl₂: 40.1 + 71.0 = 111.1 ✓
Al₂(SO₄)₃: Al2=54, S3=96.3, O12=192 → 54+96.3=150.3; +192=342.3 ✓
Mg(OH)₂: 24.3 + 32 + 2 = 58.3 ✓
NH₃: 14+3=17 ✓
CO₂: 12+32=44 ✓
C₆H₁₂O₆: 72+12+96=180 ✓
CH₃OH: C12 + H4*1=4 + O16 = 32 ✓
CH₃CO₂H: C2=24, H4=4, O2=32 → 60 ✓
NH₄CH₂CO₂H: C2=24, H5=5, N14, O2=32 → 24+5=29; +14=43; +32=75 ✓

All good.

Final Answer:
NaOH: 40.0 g/mol, formula mass
Na₂CO₃: 106.0 g/mol, formula mass
CaCl₂: 111.1 g/mol, formula mass
Al₂(SO₄)₃: 342.3 g/mol, formula mass
Mg(OH)₂: 58.3 g/mol, formula mass
NH₃: 17.0 g/mol, molecular mass
CO₂: 44.0 g/mol, molecular mass
C₆H₁₂O₆: 180.0 g/mol, molecular mass
CH₃OH: 32.0 g/mol, molecular mass
CH₃CO₂H: 60.0 g/mol, molecular mass
NH₄CH₂CO₂H: 75.0 g/mol, molecular mass