Worksheet for practicing writing chemical formulas of ionic compounds using cation and anion combinations.

Let's solve this Ionic Compound Formula Writing Worksheet step by step.

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Part 1: Fill in the Table

We are given a grid where we need to write the chemical formulas for ionic compounds formed from various cations (positive ions) and anions (negative ions). The cations are listed across the top:
- zinc, iron(II), iron(III), gallium, silver, lead(IV)

The anions are listed down the side:
- chloride, acetate, nitrate, oxide, nitride, sulfate

We will determine the formula at each intersection by combining the cation and anion with appropriate subscripts to balance charges.

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#### Step-by-step charge review:

| Ion | Charge |
|------------------|---------------|
| Zn²⁺ | +2 |
| Fe²⁺ (iron II) | +2 |
| Fe³⁺ (iron III)| +3 |
| Ga³⁺ | +3 |
| Ag⁺ | +1 |
| Pb⁴⁺ (lead IV) | +4 |
| Cl⁻ | -1 |
| CH₃COO⁻ (acetate) | -1 |
| NO₃⁻ (nitrate) | -1 |
| O²⁻ (oxide) | -2 |
| N³⁻ (nitride) | -3 |
| SO₄²⁻ (sulfate)| -2 |

Now, fill the table:

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✔ Completed Table:

| | zinc | iron (II) | iron (III) | gallium | silver | lead (IV) |
|---------------|--------------|---------------|----------------|-------------|------------|----------------|
| chloride | ZnCl₂ | FeCl₂ | FeCl₃ | GaCl₃ | AgCl | PbCl₄ |
| acetate | Zn(CH₃COO)₂ | Fe(CH₃COO)₂ | Fe(CH₃COO)₃ | Ga(CH₃COO)₃ | AgCH₃COO | Pb(CH₃COO)₄ |
| nitrate | Zn(NO₃)₂ | Fe(NO₃)₂ | Fe(NO₃)₃ | Ga(NO₃)₃ | AgNO₃ | Pb(NO₃)₄ |
| oxide | ZnO | FeO | Fe₂O₃ | Ga₂O₃ | Ag₂O | PbO₂ |
| nitride | Zn₃N₂ | Fe₃N₂ | FeN | GaN | Ag₃N | Pb₃N₄ |
| sulfate | ZnSO₄ | FeSO₄ | Fe₂(SO₄)₃ | Ga₂(SO₄)₃ | Ag₂SO₄ | Pb(SO₄)₂ |

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🔍 Explanation of Key Formulas:

- ZnCl₂: Zn²⁺ + 2 Cl⁻ → neutral
- FeCl₃: Fe³⁺ + 3 Cl⁻ → neutral
- GaCl₃: Ga³⁺ + 3 Cl⁻ → neutral
- PbCl₄: Pb⁴⁺ + 4 Cl⁻ → neutral
- Zn(CH₃COO)₂: Zn²⁺ needs two acetate ions (each -1)
- AgCH₃COO: Ag⁺ + CH₃COO⁻ → 1:1 ratio
- Fe₂O₃: Fe³⁺ and O²⁻ → LCM of 3 and 2 is 6 → 2 Fe³⁺ (6+) and 3 O²⁻ (6–)
- Zn₃N₂: Zn²⁺ and N³⁻ → cross charges: Zn₃N₂
- Pb₃N₄: Pb⁴⁺ and N³⁻ → 3×4 = 12+, 4×3 = 12– → Pb₃N₄
- Fe₂(SO₄)₃: Fe³⁺ and SO₄²⁻ → 2 Fe³⁺ = 6+, 3 SO₄²⁻ = 6– → balanced
- Pb(SO₄)₂: Pb⁴⁺ and SO₄²⁻ → Pb⁴⁺ + 2 SO₄²⁻ = neutral

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Part 2: Write Formulas for Given Compounds

Now let’s go through each one.

1) Copper(II) chloride
- Cu²⁺ and Cl⁻ → CuCl₂
✔ CuCl₂

2) Lithium acetate
- Li⁺ and CH₃COO⁻ → LiCH₃COO or LiC₂H₃O₂
✔ LiCH₃COO or LiC₂H₃O₂

3) Vanadium(III) selenide
- V³⁺ and Se²⁻ → V₂Se₃ (cross charges: 3 and 2 → LCM = 6 → V₂Se₃)
✔ V₂Se₃

4) Manganese(IV) nitride
- Mn⁴⁺ and N³⁻ → Mn₃N₄ (3×4=12+, 4×3=12–)
✔ Mn₃N₄

5) Beryllium oxide
- Be²⁺ and O²⁻ → BeO
✔ BeO

6) Sodium sulfate
- Na⁺ and SO₄²⁻ → Na₂SO₄
✔ Na₂SO₄

7) Aluminum arsenide
- Al³⁺ and As³⁻ → AlAs (charges cancel directly)
✔ AlAs

8) Potassium permanganate
- K⁺ and MnO₄⁻ → KMnO₄
✔ KMnO₄

9) Chromium(VI) cyanide
- Cr⁶⁺ and CN⁻ (cyanide is -1) → Cr(CN)₆
✔ Cr(CN)₆

10) Tin(II) sulfite
- Sn²⁺ and SO₃²⁻ (sulfite ion) → SnSO₃
✔ SnSO₃

11) Vanadium(V) fluoride
- V⁵⁺ and F⁻ → VF₅
✔ VF₅

12) Ammonium nitrate
- NH₄⁺ and NO₃⁻ → NH₄NO₃
✔ NH₄NO₃

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✔ Final Answers for Part 2:

1) CuCl₂
2) LiCH₃COO or LiC₂H₃O₂
3) V₂Se₃
4) Mn₃N₄
5) BeO
6) Na₂SO₄
7) AlAs
8) KMnO₄
9) Cr(CN)₆
10) SnSO₃
11) VF₅
12) NH₄NO₃

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