Multiplying Algebraic Fractions worksheet for simplifying expressions with variables and fractions.
Worksheet titled "Multiplying Algebraic Fractions" with 12 problems to simplify, including algebraic expressions with variables and fractions.
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Step-by-step solution for: Multiplying Fractions Worksheets with Answer Key
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Show Answer Key & Explanations
Step-by-step solution for: Multiplying Fractions Worksheets with Answer Key
To solve the problem of simplifying the given algebraic fractions, we will multiply the numerators together and the denominators together, then simplify the resulting expression by canceling out common factors. Let's go through each problem step by step.
---
$$
\frac{5x}{2} \times \frac{6}{x}
$$
1. Multiply the numerators: \( 5x \times 6 = 30x \).
2. Multiply the denominators: \( 2 \times x = 2x \).
3. Simplify the fraction:
$$
\frac{30x}{2x} = \frac{30}{2} = 15
$$
Answer:
$$
\boxed{15}
$$
---
$$
\frac{x}{3} \times \frac{21}{x+1}
$$
1. Multiply the numerators: \( x \times 21 = 21x \).
2. Multiply the denominators: \( 3 \times (x+1) = 3(x+1) \).
3. Simplify the fraction:
$$
\frac{21x}{3(x+1)} = \frac{7x}{x+1}
$$
Answer:
$$
\boxed{\frac{7x}{x+1}}
$$
---
$$
\frac{4x}{7} \times \frac{35}{6x}
$$
1. Multiply the numerators: \( 4x \times 35 = 140x \).
2. Multiply the denominators: \( 7 \times 6x = 42x \).
3. Simplify the fraction:
$$
\frac{140x}{42x} = \frac{140}{42} = \frac{10}{3}
$$
Answer:
$$
\boxed{\frac{10}{3}}
$$
---
$$
\frac{x+5}{8} \times \frac{4}{2x+10}
$$
1. Multiply the numerators: \( (x+5) \times 4 = 4(x+5) \).
2. Multiply the denominators: \( 8 \times (2x+10) = 8(2x+10) \).
3. Factorize \( 2x+10 \) as \( 2(x+5) \):
$$
\frac{4(x+5)}{8 \cdot 2(x+5)} = \frac{4(x+5)}{16(x+5)}
$$
4. Cancel out the common factor \( x+5 \):
$$
\frac{4}{16} = \frac{1}{4}
$$
Answer:
$$
\boxed{\frac{1}{4}}
$$
---
$$
\frac{x+3}{4} \times \frac{3}{2x+6}
$$
1. Multiply the numerators: \( (x+3) \times 3 = 3(x+3) \).
2. Multiply the denominators: \( 4 \times (2x+6) = 4(2x+6) \).
3. Factorize \( 2x+6 \) as \( 2(x+3) \):
$$
\frac{3(x+3)}{4 \cdot 2(x+3)} = \frac{3(x+3)}{8(x+3)}
$$
4. Cancel out the common factor \( x+3 \):
$$
\frac{3}{8}
$$
Answer:
$$
\boxed{\frac{3}{8}}
$$
---
$$
\frac{14x}{7} \times \frac{7}{2x}
$$
1. Multiply the numerators: \( 14x \times 7 = 98x \).
2. Multiply the denominators: \( 7 \times 2x = 14x \).
3. Simplify the fraction:
$$
\frac{98x}{14x} = \frac{98}{14} = 7
$$
Answer:
$$
\boxed{7}
$$
---
$$
\frac{3}{2x} \times \frac{x}{15}
$$
1. Multiply the numerators: \( 3 \times x = 3x \).
2. Multiply the denominators: \( 2x \times 15 = 30x \).
3. Simplify the fraction:
$$
\frac{3x}{30x} = \frac{3}{30} = \frac{1}{10}
$$
Answer:
$$
\boxed{\frac{1}{10}}
$$
---
$$
\frac{2x+4}{18} \times \frac{3}{5}
$$
1. Multiply the numerators: \( (2x+4) \times 3 = 3(2x+4) \).
2. Multiply the denominators: \( 18 \times 5 = 90 \).
3. Factorize \( 2x+4 \) as \( 2(x+2) \):
$$
\frac{3 \cdot 2(x+2)}{90} = \frac{6(x+2)}{90}
$$
4. Simplify the fraction:
$$
\frac{6(x+2)}{90} = \frac{x+2}{15}
$$
Answer:
$$
\boxed{\frac{x+2}{15}}
$$
---
$$
\frac{x}{4} \times \frac{16}{9x}
$$
1. Multiply the numerators: \( x \times 16 = 16x \).
2. Multiply the denominators: \( 4 \times 9x = 36x \).
3. Simplify the fraction:
$$
\frac{16x}{36x} = \frac{16}{36} = \frac{4}{9}
$$
Answer:
$$
\boxed{\frac{4}{9}}
$$
---
$$
\frac{6x}{3} \times \frac{7}{4x}
$$
1. Multiply the numerators: \( 6x \times 7 = 42x \).
2. Multiply the denominators: \( 3 \times 4x = 12x \).
3. Simplify the fraction:
$$
\frac{42x}{12x} = \frac{42}{12} = \frac{7}{2}
$$
Answer:
$$
\boxed{\frac{7}{2}}
$$
---
$$
\frac{2x}{x+5} \times \frac{3x+15}{4}
$$
1. Multiply the numerators: \( 2x \times (3x+15) = 2x(3x+15) \).
2. Multiply the denominators: \( (x+5) \times 4 = 4(x+5) \).
3. Factorize \( 3x+15 \) as \( 3(x+5) \):
$$
\frac{2x \cdot 3(x+5)}{4(x+5)} = \frac{6x(x+5)}{4(x+5)}
$$
4. Cancel out the common factor \( x+5 \):
$$
\frac{6x}{4} = \frac{3x}{2}
$$
Answer:
$$
\boxed{\frac{3x}{2}}
$$
---
$$
\frac{x}{x-4} \times \frac{2x-8}{3}
$$
1. Multiply the numerators: \( x \times (2x-8) = x(2x-8) \).
2. Multiply the denominators: \( (x-4) \times 3 = 3(x-4) \).
3. Factorize \( 2x-8 \) as \( 2(x-4) \):
$$
\frac{x \cdot 2(x-4)}{3(x-4)} = \frac{2x(x-4)}{3(x-4)}
$$
4. Cancel out the common factor \( x-4 \):
$$
\frac{2x}{3}
$$
Answer:
$$
\boxed{\frac{2x}{3}}
$$
---
1. \( \boxed{15} \)
2. \( \boxed{\frac{7x}{x+1}} \)
3. \( \boxed{\frac{10}{3}} \)
4. \( \boxed{\frac{1}{4}} \)
5. \( \boxed{\frac{3}{8}} \)
6. \( \boxed{7} \)
7. \( \boxed{\frac{1}{10}} \)
8. \( \boxed{\frac{x+2}{15}} \)
9. \( \boxed{\frac{4}{9}} \)
10. \( \boxed{\frac{7}{2}} \)
11. \( \boxed{\frac{3x}{2}} \)
12. \( \boxed{\frac{2x}{3}} \)
---
Problem 1:
$$
\frac{5x}{2} \times \frac{6}{x}
$$
1. Multiply the numerators: \( 5x \times 6 = 30x \).
2. Multiply the denominators: \( 2 \times x = 2x \).
3. Simplify the fraction:
$$
\frac{30x}{2x} = \frac{30}{2} = 15
$$
Answer:
$$
\boxed{15}
$$
---
Problem 2:
$$
\frac{x}{3} \times \frac{21}{x+1}
$$
1. Multiply the numerators: \( x \times 21 = 21x \).
2. Multiply the denominators: \( 3 \times (x+1) = 3(x+1) \).
3. Simplify the fraction:
$$
\frac{21x}{3(x+1)} = \frac{7x}{x+1}
$$
Answer:
$$
\boxed{\frac{7x}{x+1}}
$$
---
Problem 3:
$$
\frac{4x}{7} \times \frac{35}{6x}
$$
1. Multiply the numerators: \( 4x \times 35 = 140x \).
2. Multiply the denominators: \( 7 \times 6x = 42x \).
3. Simplify the fraction:
$$
\frac{140x}{42x} = \frac{140}{42} = \frac{10}{3}
$$
Answer:
$$
\boxed{\frac{10}{3}}
$$
---
Problem 4:
$$
\frac{x+5}{8} \times \frac{4}{2x+10}
$$
1. Multiply the numerators: \( (x+5) \times 4 = 4(x+5) \).
2. Multiply the denominators: \( 8 \times (2x+10) = 8(2x+10) \).
3. Factorize \( 2x+10 \) as \( 2(x+5) \):
$$
\frac{4(x+5)}{8 \cdot 2(x+5)} = \frac{4(x+5)}{16(x+5)}
$$
4. Cancel out the common factor \( x+5 \):
$$
\frac{4}{16} = \frac{1}{4}
$$
Answer:
$$
\boxed{\frac{1}{4}}
$$
---
Problem 5:
$$
\frac{x+3}{4} \times \frac{3}{2x+6}
$$
1. Multiply the numerators: \( (x+3) \times 3 = 3(x+3) \).
2. Multiply the denominators: \( 4 \times (2x+6) = 4(2x+6) \).
3. Factorize \( 2x+6 \) as \( 2(x+3) \):
$$
\frac{3(x+3)}{4 \cdot 2(x+3)} = \frac{3(x+3)}{8(x+3)}
$$
4. Cancel out the common factor \( x+3 \):
$$
\frac{3}{8}
$$
Answer:
$$
\boxed{\frac{3}{8}}
$$
---
Problem 6:
$$
\frac{14x}{7} \times \frac{7}{2x}
$$
1. Multiply the numerators: \( 14x \times 7 = 98x \).
2. Multiply the denominators: \( 7 \times 2x = 14x \).
3. Simplify the fraction:
$$
\frac{98x}{14x} = \frac{98}{14} = 7
$$
Answer:
$$
\boxed{7}
$$
---
Problem 7:
$$
\frac{3}{2x} \times \frac{x}{15}
$$
1. Multiply the numerators: \( 3 \times x = 3x \).
2. Multiply the denominators: \( 2x \times 15 = 30x \).
3. Simplify the fraction:
$$
\frac{3x}{30x} = \frac{3}{30} = \frac{1}{10}
$$
Answer:
$$
\boxed{\frac{1}{10}}
$$
---
Problem 8:
$$
\frac{2x+4}{18} \times \frac{3}{5}
$$
1. Multiply the numerators: \( (2x+4) \times 3 = 3(2x+4) \).
2. Multiply the denominators: \( 18 \times 5 = 90 \).
3. Factorize \( 2x+4 \) as \( 2(x+2) \):
$$
\frac{3 \cdot 2(x+2)}{90} = \frac{6(x+2)}{90}
$$
4. Simplify the fraction:
$$
\frac{6(x+2)}{90} = \frac{x+2}{15}
$$
Answer:
$$
\boxed{\frac{x+2}{15}}
$$
---
Problem 9:
$$
\frac{x}{4} \times \frac{16}{9x}
$$
1. Multiply the numerators: \( x \times 16 = 16x \).
2. Multiply the denominators: \( 4 \times 9x = 36x \).
3. Simplify the fraction:
$$
\frac{16x}{36x} = \frac{16}{36} = \frac{4}{9}
$$
Answer:
$$
\boxed{\frac{4}{9}}
$$
---
Problem 10:
$$
\frac{6x}{3} \times \frac{7}{4x}
$$
1. Multiply the numerators: \( 6x \times 7 = 42x \).
2. Multiply the denominators: \( 3 \times 4x = 12x \).
3. Simplify the fraction:
$$
\frac{42x}{12x} = \frac{42}{12} = \frac{7}{2}
$$
Answer:
$$
\boxed{\frac{7}{2}}
$$
---
Problem 11:
$$
\frac{2x}{x+5} \times \frac{3x+15}{4}
$$
1. Multiply the numerators: \( 2x \times (3x+15) = 2x(3x+15) \).
2. Multiply the denominators: \( (x+5) \times 4 = 4(x+5) \).
3. Factorize \( 3x+15 \) as \( 3(x+5) \):
$$
\frac{2x \cdot 3(x+5)}{4(x+5)} = \frac{6x(x+5)}{4(x+5)}
$$
4. Cancel out the common factor \( x+5 \):
$$
\frac{6x}{4} = \frac{3x}{2}
$$
Answer:
$$
\boxed{\frac{3x}{2}}
$$
---
Problem 12:
$$
\frac{x}{x-4} \times \frac{2x-8}{3}
$$
1. Multiply the numerators: \( x \times (2x-8) = x(2x-8) \).
2. Multiply the denominators: \( (x-4) \times 3 = 3(x-4) \).
3. Factorize \( 2x-8 \) as \( 2(x-4) \):
$$
\frac{x \cdot 2(x-4)}{3(x-4)} = \frac{2x(x-4)}{3(x-4)}
$$
4. Cancel out the common factor \( x-4 \):
$$
\frac{2x}{3}
$$
Answer:
$$
\boxed{\frac{2x}{3}}
$$
---
Final Answers:
1. \( \boxed{15} \)
2. \( \boxed{\frac{7x}{x+1}} \)
3. \( \boxed{\frac{10}{3}} \)
4. \( \boxed{\frac{1}{4}} \)
5. \( \boxed{\frac{3}{8}} \)
6. \( \boxed{7} \)
7. \( \boxed{\frac{1}{10}} \)
8. \( \boxed{\frac{x+2}{15}} \)
9. \( \boxed{\frac{4}{9}} \)
10. \( \boxed{\frac{7}{2}} \)
11. \( \boxed{\frac{3x}{2}} \)
12. \( \boxed{\frac{2x}{3}} \)
Parent Tip: Review the logic above to help your child master the concept of fraction multiplication worksheet.