Order of Operations with Positive Fractions (Three Steps) (A) - Free Printable

- $\frac{5}{6} + \frac{3}{4} \div \left(\frac{3}{5}\right)^2 = \frac{5}{6} + \frac{3}{4} \div \frac{9}{25} = \frac{5}{6} + \frac{3}{4} \times \frac{25}{9} = \frac{5}{6} + \frac{75}{36} = \frac{30}{36} + \frac{75}{36} = \frac{105}{36} = \frac{35}{12}$
- $\left(\frac{5}{6}\right)^2 + \left(\frac{5}{8} - \frac{4}{9}\right) = \frac{25}{36} + \left(\frac{45}{72} - \frac{32}{72}\right) = \frac{25}{36} + \frac{13}{72} = \frac{50}{72} + \frac{13}{72} = \frac{63}{72} = \frac{7}{8}$
- $\frac{1}{9} \times \frac{5}{8} + \left(\frac{1}{2}\right)^3 = \frac{5}{72} + \frac{1}{8} = \frac{5}{72} + \frac{9}{72} = \frac{14}{72} = \frac{7}{36}$
- $\frac{7}{8} \div \left(\frac{2}{3} - \left(\frac{1}{3}\right)^2\right) = \frac{7}{8} \div \left(\frac{2}{3} - \frac{1}{9}\right) = \frac{7}{8} \div \left(\frac{6}{9} - \frac{1}{9}\right) = \frac{7}{8} \div \frac{5}{9} = \frac{7}{8} \times \frac{9}{5} = \frac{63}{40}$
- $\left(\frac{3}{5} + \frac{2}{5}\right) \times \left(\frac{1}{9}\right)^2 = 1 \times \frac{1}{81} = \frac{1}{81}$
- $\left(\frac{5}{6} - \left(\frac{1}{3}\right)^3\right) \times \frac{1}{2} = \left(\frac{5}{6} - \frac{1}{27}\right) \times \frac{1}{2} = \left(\frac{45}{54} - \frac{2}{54}\right) \times \frac{1}{2} = \frac{43}{54} \times \frac{1}{2} = \frac{43}{108}$
- $\frac{3}{4} - \frac{1}{6} \div \left(\frac{4}{5}\right)^2 = \frac{3}{4} - \frac{1}{6} \div \frac{16}{25} = \frac{3}{4} - \frac{1}{6} \times \frac{25}{16} = \frac{3}{4} - \frac{25}{96} = \frac{72}{96} - \frac{25}{96} = \frac{47}{96}$
- $\left(\frac{1}{9}\right)^2 \div \frac{4}{9} + \frac{1}{6} = \frac{1}{81} \div \frac{4}{9} + \frac{1}{6} = \frac{1}{81} \times \frac{9}{4} + \frac{1}{6} = \frac{1}{36} + \frac{1}{6} = \frac{1}{36} + \frac{6}{36} = \frac{7}{36}$
- $\left(\frac{3}{4}\right)^2 \times \frac{3}{5} + \frac{1}{2} = \frac{9}{16} \times \frac{3}{5} + \frac{1}{2} = \frac{27}{80} + \frac{1}{2} = \frac{27}{80} + \frac{40}{80} = \frac{67}{80}$