Worksheet featuring fraction word problems for educational practice.

The image contains two sets of word problems involving fractions. Below, I will solve the problems step by step.

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Fractions of Amounts Word Problems (Left Side)

#### Problem 1:
Sarah entered a 100-word story competition. She wrote her story over two evenings. On the first evening, she wrote $\frac{3}{5}$ of the story, and on the second evening, she wrote the rest.
1. How many words did she write on the first evening?
2. How many words did she write on the second evening and what fraction was this?

Solution:
- Total words in the story = 100
- Fraction written on the first evening = $\frac{3}{5}$
- Words written on the first evening:
$$
\text{Words on first evening} = \frac{3}{5} \times 100 = 60
$$
- Words written on the second evening:
$$
\text{Words on second evening} = 100 - 60 = 40
$$
- Fraction of the story written on the second evening:
$$
\text{Fraction on second evening} = \frac{40}{100} = \frac{2}{5}
$$

Answer:
1. 60 words
2. 40 words, $\frac{2}{5}$

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#### Problem 2:
Two families, the Smiths and the Taylors, went to a restaurant for a meal. At the end of the night, when they paid their $100 bill, they used a 50% off coupon, which they split equally between the two families.
1. How much does the bill come to after using the coupon?
2. How much money does each family pay?

Solution:
- Original bill = $100
- Discount = 50% off
- Bill after discount:
$$
\text{Discounted bill} = 100 \times \left(1 - \frac{50}{100}\right) = 100 \times \frac{1}{2} = 50
$$
- Each family pays half of the discounted bill:
$$
\text{Amount per family} = \frac{50}{2} = 25
$$

Answer:
1. $50
2. $25

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#### Problem 3:
There were 120 school children on a school field trip. There were 2 buses carrying $\frac{4}{5}$ of the children on bus A and $\frac{1}{5}$ of the children on bus B.
1. How many children were on each bus?
2. How many children had sweaters on bus B if $\frac{3}{4}$ of the children on bus B had sweaters with them?

Solution:
- Total children = 120
- Children on bus A:
$$
\text{Children on bus A} = \frac{4}{5} \times 120 = 96
$$
- Children on bus B:
$$
\text{Children on bus B} = \frac{1}{5} \times 120 = 24
$$
- Children with sweaters on bus B:
$$
\text{Children with sweaters on bus B} = \frac{3}{4} \times 24 = 18
$$

Answer:
1. Bus A: 96 children, Bus B: 24 children
2. 18 children

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#### Problem 4:
A retired couple won $1000 on the lottery. They decided to give $\frac{3}{5}$ of it to their family and spend $\frac{1}{5}$ of it on an outing for themselves.
1. How much money did they give to their family?
2. How much money did they spend on their outing?

Solution:
- Total winnings = $1000
- Money given to family:
$$
\text{Money to family} = \frac{3}{5} \times 1000 = 600
$$
- Money spent on outing:
$$
\text{Money for outing} = \frac{1}{5} \times 1000 = 200
$$

Answer:
1. $600
2. $200

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#### Problem 5:
Jane watched a movie that was 1 hour long. She paused the movie to use the bathroom. She watched $\frac{3}{4}$ of the movie before the pause and $\frac{1}{4}$ of the movie after the pause.
1. How many minutes of the movie had she watched before the pause?

Solution:
- Total movie length = 1 hour = 60 minutes
- Minutes watched before the pause:
$$
\text{Minutes before pause} = \frac{3}{4} \times 60 = 45
$$

Answer:
1. 45 minutes

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Final Answers:

1. Problem 1:
- 60 words, 40 words, $\frac{2}{5}$
Boxed Answer: $\boxed{60, 40, \frac{2}{5}}$

2. Problem 2:
- $50, $25
Boxed Answer: $\boxed{50, 25}$

3. Problem 3:
- 96 children, 24 children, 18 children
Boxed Answer: $\boxed{96, 24, 18}$

4. Problem 4:
- $600, $200
Boxed Answer: $\boxed{600, 200}$

5. Problem 5:
- 45 minutes
Boxed Answer: $\boxed{45}$

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If you have any further questions or need additional clarification, feel free to ask!