Addition of Fractions Grade 4 - Worksheet Digital - Free Printable

Problem: Addition of Fractions

The task is to solve the addition of fractions provided in the worksheet. Let's go through each problem step by step.

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#### Row 1:
1. $\frac{1}{3} + \frac{1}{3}$
- Both fractions have the same denominator (3).
- Add the numerators: $1 + 1 = 2$.
- The denominator remains the same.
- Result: $\frac{2}{3}$.

2. $\frac{2}{7} + \frac{3}{7}$
- Both fractions have the same denominator (7).
- Add the numerators: $2 + 3 = 5$.
- The denominator remains the same.
- Result: $\frac{5}{7}$.

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#### Row 2:
3. $\frac{1}{5} + \frac{3}{5}$
- Both fractions have the same denominator (5).
- Add the numerators: $1 + 3 = 4$.
- The denominator remains the same.
- Result: $\frac{4}{5}$.

4. $\frac{1}{9} + \frac{7}{9}$
- Both fractions have the same denominator (9).
- Add the numerators: $1 + 7 = 8$.
- The denominator remains the same.
- Result: $\frac{8}{9}$.

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#### Row 3:
5. $\frac{1}{5} + \frac{2}{5} + \frac{1}{5}$
- All fractions have the same denominator (5).
- Add the numerators: $1 + 2 + 1 = 4$.
- The denominator remains the same.
- Result: $\frac{4}{5}$.

6. $\frac{1}{4} + \frac{3}{4} + \frac{3}{4}$
- All fractions have the same denominator (4).
- Add the numerators: $1 + 3 + 3 = 7$.
- The denominator remains the same.
- Result: $\frac{7}{4}$ (which can also be written as $1\frac{3}{4}$).

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#### Row 4:
7. $\frac{7}{8} + \frac{1}{8} + \frac{3}{8}$
- All fractions have the same denominator (8).
- Add the numerators: $7 + 1 + 3 = 11$.
- The denominator remains the same.
- Result: $\frac{11}{8}$ (which can also be written as $1\frac{3}{8}$).

8. $\frac{2}{3} + \frac{1}{3} + \frac{2}{3}$
- All fractions have the same denominator (3).
- Add the numerators: $2 + 1 + 2 = 5$.
- The denominator remains the same.
- Result: $\frac{5}{3}$ (which can also be written as $1\frac{2}{3}$).

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#### Row 5:
9. $\frac{3}{5} + \frac{4}{5} + \frac{2}{5}$
- All fractions have the same denominator (5).
- Add the numerators: $3 + 4 + 2 = 9$.
- The denominator remains the same.
- Result: $\frac{9}{5}$ (which can also be written as $1\frac{4}{5}$).

10. $\frac{1}{4} + \frac{3}{4} + \frac{1}{4}$
- All fractions have the same denominator (4).
- Add the numerators: $1 + 3 + 1 = 5$.
- The denominator remains the same.
- Result: $\frac{5}{4}$ (which can also be written as $1\frac{1}{4}$).

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Final Answers:

\[
\begin{array}{|c|c|}
\hline
\frac{1}{3} + \frac{1}{3} = \frac{2}{3} & \frac{2}{7} + \frac{3}{7} = \frac{5}{7} \\
\hline
\frac{1}{5} + \frac{3}{5} = \frac{4}{5} & \frac{1}{9} + \frac{7}{9} = \frac{8}{9} \\
\hline
\frac{1}{5} + \frac{2}{5} + \frac{1}{5} = \frac{4}{5} & \frac{1}{4} + \frac{3}{4} + \frac{3}{4} = \frac{7}{4} \\
\hline
\frac{7}{8} + \frac{1}{8} + \frac{3}{8} = \frac{11}{8} & \frac{2}{3} + \frac{1}{3} + \frac{2}{3} = \frac{5}{3} \\
\hline
\frac{3}{5} + \frac{4}{5} + \frac{2}{5} = \frac{9}{5} & \frac{1}{4} + \frac{3}{4} + \frac{1}{4} = \frac{5}{4} \\
\hline
\end{array}
\]

Boxed Final Answer:

\[
\boxed{
\begin{array}{|c|c|}
\hline
\frac{2}{3} & \frac{5}{7} \\
\hline
\frac{4}{5} & \frac{8}{9} \\
\hline
\frac{4}{5} & \frac{7}{4} \\
\hline
\frac{11}{8} & \frac{5}{3} \\
\hline
\frac{9}{5} & \frac{5}{4} \\
\hline
\end{array}
}
\]