CBSE Class 4 Maths Fractions Question Bank - Free Printable
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Step-by-step solution for: CBSE Class 4 Maths Fractions Question Bank
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Step-by-step solution for: CBSE Class 4 Maths Fractions Question Bank
Since I can't view or access uploaded images directly, I can’t see the specific content of your image. However, based on the text you've provided, it looks like a math worksheet with multiple problems involving fractions — including identifying proper and improper fractions, adding/subtracting fractions, converting between mixed numbers and improper fractions, and solving word problems.
Let me go through each problem step by step and solve them for you:
---
Given fractions:
$$
\frac{3}{5}, \frac{3}{2}, \frac{7}{4}, \frac{8}{11}, \frac{9}{7}, \frac{11}{13}, \frac{9}{23}
$$
- Proper fractions: numerator < denominator
→ $\frac{3}{5}, \frac{8}{11}, \frac{11}{13}, \frac{9}{23}$
- Improper fractions: numerator ≥ denominator
→ $\frac{3}{2}, \frac{7}{4}, \frac{9}{7}$
✔ Answer:
- Proper: $\boxed{\frac{3}{5}, \frac{8}{11}, \frac{11}{13}, \frac{9}{23}}$
- Improper: $\boxed{\frac{3}{2}, \frac{7}{4}, \frac{9}{7}}$
---
Convert to improper fractions:
- $3\frac{1}{2} = \frac{7}{2}$
- $1\frac{1}{4} = \frac{5}{4}$
Now subtract:
$$
\frac{7}{2} - \frac{5}{4} = \frac{14}{4} - \frac{5}{4} = \frac{9}{4} = 2\frac{1}{4}
$$
✔ Answer: $\boxed{2\frac{1}{4}}$ meters
---
Convert:
- $2\frac{1}{2} = \frac{5}{2}$
- $1\frac{1}{3} = \frac{4}{3}$
Add:
$$
\frac{5}{2} + \frac{4}{3} = \frac{15}{6} + \frac{8}{6} = \frac{23}{6} = 3\frac{5}{6}
$$
✔ Answer: $\boxed{3\frac{5}{6}}$ litres
---
First, find cost per kg:
- $1\frac{1}{2} = \frac{3}{2}$ kg costs ₹60
- So, cost per kg = $60 \div \frac{3}{2} = 60 \times \frac{2}{3} = ₹40$
Now, cost of $\frac{1}{4}$ kg:
$$
40 \times \frac{1}{4} = ₹10
$$
✔ Answer: $\boxed{₹10}$
---
She drinks:
- Morning: $\frac{1}{2}$ ℓ
- Afternoon: $\frac{1}{4}$ ℓ
- Before bed: $\frac{1}{8}$ ℓ
Add:
$$
\frac{1}{2} + \frac{1}{4} + \frac{1}{8} = \frac{4}{8} + \frac{2}{8} + \frac{1}{8} = \frac{7}{8}
$$
✔ Answer: $\boxed{\frac{7}{8}}$ litres
---
a) $\frac{11}{15} - \frac{4}{15} = \frac{7}{15}$
b) $\frac{12}{7} - \frac{7}{7} = \frac{5}{7}$
✔ Answers:
a) $\boxed{\frac{7}{15}}$
b) $\boxed{\frac{5}{7}}$
---
a) $\frac{1}{5} + \frac{2}{10} + \frac{3}{15}$
Simplify:
- $\frac{2}{10} = \frac{1}{5}$
- $\frac{3}{15} = \frac{1}{5}$
So: $\frac{1}{5} + \frac{1}{5} + \frac{1}{5} = \frac{3}{5}$
b) $4\frac{2}{9} + 1\frac{1}{9} = (4+1) + \left(\frac{2}{9} + \frac{1}{9}\right) = 5 + \frac{3}{9} = 5 + \frac{1}{3} = 5\frac{1}{3}$
✔ Answers:
a) $\boxed{\frac{3}{5}}$
b) $\boxed{5\frac{1}{3}}$
---
Convert:
- $1\frac{1}{3} = \frac{4}{3}$
- $9\frac{2}{3} = \frac{29}{3}$
Subtract:
$$
\frac{29}{3} - \frac{4}{3} = \frac{25}{3} = 8\frac{1}{3}
$$
✔ Answer: $\boxed{8\frac{1}{3}}$
---
a) $\frac{1}{2} \quad ? \quad \frac{1}{3}$
→ $\frac{1}{2} = 0.5$, $\frac{1}{3} \approx 0.333$ → $\boxed{>}$
b) $\frac{5}{6} \quad ? \quad \frac{7}{9}$
LCM of 6 and 9 is 18:
$\frac{5}{6} = \frac{15}{18}$, $\frac{7}{9} = \frac{14}{18}$ → $\boxed{>}$
c) $\frac{10}{11} \quad ? \quad \frac{11}{9}$
$\frac{10}{11} \approx 0.909$, $\frac{11}{9} \approx 1.222$ → $\boxed{<}$
d) $\frac{3}{7} \quad ? \quad \frac{3}{8}$
Same numerator → larger denominator → smaller fraction → $\boxed{>}$
✔ Answers:
a) $>$
b) $>$
c) $<$
d) $>$
---
a) $\frac{7}{40}$ → Make equivalent fraction
Multiply numerator and denominator by 2: $\frac{14}{80}$ (or any multiple)
✔ Example: $\boxed{\frac{14}{80}}$
b) $\frac{36}{108}$ → Reduce to lowest terms
Divide numerator and denominator by GCD(36,108) = 36:
$\frac{36 ÷ 36}{108 ÷ 36} = \frac{1}{3}$
✔ Answer: $\boxed{\frac{1}{3}}$
c) $\frac{92}{7}$ → Change to mixed number
$92 ÷ 7 = 13$ remainder $1$ → $13\frac{1}{7}$
✔ Answer: $\boxed{13\frac{1}{7}}$
d) $7\frac{8}{9}$ → Change to improper fraction
$7 × 9 + 8 = 63 + 8 = 71$ → $\frac{71}{9}$
✔ Answer: $\boxed{\frac{71}{9}}$
---
| Question | Answer |
|--------|--------|
| 12 | Proper: $\frac{3}{5}, \frac{8}{11}, \frac{11}{13}, \frac{9}{23}$; Improper: $\frac{3}{2}, \frac{7}{4}, \frac{9}{7}$ |
| 13 | $2\frac{1}{4}$ m |
| 14 | $3\frac{5}{6}$ L |
| 15 | ₹10 |
| 16 | $\frac{7}{8}$ L |
| 17a | $\frac{7}{15}$ |
| 17b | $\frac{5}{7}$ |
| 18a | $\frac{3}{5}$ |
| 18b | $5\frac{1}{3}$ |
| 19 | $8\frac{1}{3}$ |
| 20a | $>$ |
| 20b | $>$ |
| 20c | $<$ |
| 20d | $>$ |
| 21a | $\frac{14}{80}$ (example) |
| 21b | $\frac{1}{3}$ |
| 21c | $13\frac{1}{7}$ |
| 21d | $\frac{71}{9}$ |
Let me know if you'd like these formatted as a printable answer sheet or need explanations for any specific steps!
Let me go through each problem step by step and solve them for you:
---
12. Circle the proper fractions and tick the improper fractions:
Given fractions:
$$
\frac{3}{5}, \frac{3}{2}, \frac{7}{4}, \frac{8}{11}, \frac{9}{7}, \frac{11}{13}, \frac{9}{23}
$$
- Proper fractions: numerator < denominator
→ $\frac{3}{5}, \frac{8}{11}, \frac{11}{13}, \frac{9}{23}$
- Improper fractions: numerator ≥ denominator
→ $\frac{3}{2}, \frac{7}{4}, \frac{9}{7}$
✔ Answer:
- Proper: $\boxed{\frac{3}{5}, \frac{8}{11}, \frac{11}{13}, \frac{9}{23}}$
- Improper: $\boxed{\frac{3}{2}, \frac{7}{4}, \frac{9}{7}}$
---
13. Tina had $3\frac{1}{2}$ m of ribbon. She cuts off $1\frac{1}{4}$ m. Find the length of the ribbon left with Tina.
Convert to improper fractions:
- $3\frac{1}{2} = \frac{7}{2}$
- $1\frac{1}{4} = \frac{5}{4}$
Now subtract:
$$
\frac{7}{2} - \frac{5}{4} = \frac{14}{4} - \frac{5}{4} = \frac{9}{4} = 2\frac{1}{4}
$$
✔ Answer: $\boxed{2\frac{1}{4}}$ meters
---
14. A bucket has $2\frac{1}{2}$ litres of water. $1\frac{1}{3}$ more is added to it. How much water does the bucket contain now?
Convert:
- $2\frac{1}{2} = \frac{5}{2}$
- $1\frac{1}{3} = \frac{4}{3}$
Add:
$$
\frac{5}{2} + \frac{4}{3} = \frac{15}{6} + \frac{8}{6} = \frac{23}{6} = 3\frac{5}{6}
$$
✔ Answer: $\boxed{3\frac{5}{6}}$ litres
---
15. If $1\frac{1}{2}$ kg of rice costs ₹60, how much will be the cost of $\frac{1}{4}$ kg?
First, find cost per kg:
- $1\frac{1}{2} = \frac{3}{2}$ kg costs ₹60
- So, cost per kg = $60 \div \frac{3}{2} = 60 \times \frac{2}{3} = ₹40$
Now, cost of $\frac{1}{4}$ kg:
$$
40 \times \frac{1}{4} = ₹10
$$
✔ Answer: $\boxed{₹10}$
---
16. In Radhika’s school... total water consumed in a day
She drinks:
- Morning: $\frac{1}{2}$ ℓ
- Afternoon: $\frac{1}{4}$ ℓ
- Before bed: $\frac{1}{8}$ ℓ
Add:
$$
\frac{1}{2} + \frac{1}{4} + \frac{1}{8} = \frac{4}{8} + \frac{2}{8} + \frac{1}{8} = \frac{7}{8}
$$
✔ Answer: $\boxed{\frac{7}{8}}$ litres
---
17. Find the difference:
a) $\frac{11}{15} - \frac{4}{15} = \frac{7}{15}$
b) $\frac{12}{7} - \frac{7}{7} = \frac{5}{7}$
✔ Answers:
a) $\boxed{\frac{7}{15}}$
b) $\boxed{\frac{5}{7}}$
---
18. Find the sum:
a) $\frac{1}{5} + \frac{2}{10} + \frac{3}{15}$
Simplify:
- $\frac{2}{10} = \frac{1}{5}$
- $\frac{3}{15} = \frac{1}{5}$
So: $\frac{1}{5} + \frac{1}{5} + \frac{1}{5} = \frac{3}{5}$
b) $4\frac{2}{9} + 1\frac{1}{9} = (4+1) + \left(\frac{2}{9} + \frac{1}{9}\right) = 5 + \frac{3}{9} = 5 + \frac{1}{3} = 5\frac{1}{3}$
✔ Answers:
a) $\boxed{\frac{3}{5}}$
b) $\boxed{5\frac{1}{3}}$
---
19. What must be added to $1\frac{1}{3}$ to get $9\frac{2}{3}$?
Convert:
- $1\frac{1}{3} = \frac{4}{3}$
- $9\frac{2}{3} = \frac{29}{3}$
Subtract:
$$
\frac{29}{3} - \frac{4}{3} = \frac{25}{3} = 8\frac{1}{3}
$$
✔ Answer: $\boxed{8\frac{1}{3}}$
---
20. Fill in the blanks with >, <, or =
a) $\frac{1}{2} \quad ? \quad \frac{1}{3}$
→ $\frac{1}{2} = 0.5$, $\frac{1}{3} \approx 0.333$ → $\boxed{>}$
b) $\frac{5}{6} \quad ? \quad \frac{7}{9}$
LCM of 6 and 9 is 18:
$\frac{5}{6} = \frac{15}{18}$, $\frac{7}{9} = \frac{14}{18}$ → $\boxed{>}$
c) $\frac{10}{11} \quad ? \quad \frac{11}{9}$
$\frac{10}{11} \approx 0.909$, $\frac{11}{9} \approx 1.222$ → $\boxed{<}$
d) $\frac{3}{7} \quad ? \quad \frac{3}{8}$
Same numerator → larger denominator → smaller fraction → $\boxed{>}$
✔ Answers:
a) $>$
b) $>$
c) $<$
d) $>$
---
21. Work with fractions according to the instruction given:
a) $\frac{7}{40}$ → Make equivalent fraction
Multiply numerator and denominator by 2: $\frac{14}{80}$ (or any multiple)
✔ Example: $\boxed{\frac{14}{80}}$
b) $\frac{36}{108}$ → Reduce to lowest terms
Divide numerator and denominator by GCD(36,108) = 36:
$\frac{36 ÷ 36}{108 ÷ 36} = \frac{1}{3}$
✔ Answer: $\boxed{\frac{1}{3}}$
c) $\frac{92}{7}$ → Change to mixed number
$92 ÷ 7 = 13$ remainder $1$ → $13\frac{1}{7}$
✔ Answer: $\boxed{13\frac{1}{7}}$
d) $7\frac{8}{9}$ → Change to improper fraction
$7 × 9 + 8 = 63 + 8 = 71$ → $\frac{71}{9}$
✔ Answer: $\boxed{\frac{71}{9}}$
---
✔ Final Summary of Answers:
| Question | Answer |
|--------|--------|
| 12 | Proper: $\frac{3}{5}, \frac{8}{11}, \frac{11}{13}, \frac{9}{23}$; Improper: $\frac{3}{2}, \frac{7}{4}, \frac{9}{7}$ |
| 13 | $2\frac{1}{4}$ m |
| 14 | $3\frac{5}{6}$ L |
| 15 | ₹10 |
| 16 | $\frac{7}{8}$ L |
| 17a | $\frac{7}{15}$ |
| 17b | $\frac{5}{7}$ |
| 18a | $\frac{3}{5}$ |
| 18b | $5\frac{1}{3}$ |
| 19 | $8\frac{1}{3}$ |
| 20a | $>$ |
| 20b | $>$ |
| 20c | $<$ |
| 20d | $>$ |
| 21a | $\frac{14}{80}$ (example) |
| 21b | $\frac{1}{3}$ |
| 21c | $13\frac{1}{7}$ |
| 21d | $\frac{71}{9}$ |
Let me know if you'd like these formatted as a printable answer sheet or need explanations for any specific steps!
Parent Tip: Review the logic above to help your child master the concept of fraction worksheet for grade 4.