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Factoring Polynomials worksheet with 12 algebraic expressions for practice.

Worksheet titled "Factoring Polynomials" with 12 polynomial expressions to factor, including quadratic and higher-degree polynomials, from Math Monks.

Worksheet titled "Factoring Polynomials" with 12 polynomial expressions to factor, including quadratic and higher-degree polynomials, from Math Monks.

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Show Answer Key & Explanations Step-by-step solution for: Factoring Polynomials Worksheets with Answer Key
Let’s solve each problem one by one. We’ll factor each polynomial completely.

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Problem 1: 3x² - 2x - 5

We need two numbers that multiply to (3)(-5) = -15 and add to -2.
Those numbers are -5 and +3.

Rewrite middle term:
3x² - 5x + 3x - 5

Group:
(3x² - 5x) + (3x - 5)
= x(3x - 5) + 1(3x - 5)
= (x + 1)(3x - 5)

Final Answer for #1: (x + 1)(3x - 5)

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Problem 2: 10m² + 17m + 6

Multiply 10 × 6 = 60. Find two numbers that multiply to 60 and add to 17 → 12 and 5.

Rewrite:
10m² + 12m + 5m + 6

Group:
(10m² + 12m) + (5m + 6)
= 2m(5m + 6) + 1(5m + 6)
= (2m + 1)(5m + 6)

Final Answer for #2: (2m + 1)(5m + 6)

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Problem 3: 2m² + 63m + 145

Multiply 2 × 145 = 290. Need two numbers that multiply to 290 and add to 63.

Try factors of 290:
1×290, 2×145, 5×58, 10×29 → 10 + 29 = 39
Wait — 58 + 5 = 63

So rewrite:
2m² + 58m + 5m + 145

Group:
(2m² + 58m) + (5m + 145)
= 2m(m + 29) + 5(m + 29)
= (2m + 5)(m + 29)

Final Answer for #3: (2m + 5)(m + 29)

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Problem 4: 3x⁷ + 36x⁵ + 108x³

First, factor out GCF: all terms have 3x³.

= 3x³(x⁴ + 12x² + 36)

Now look at inside: x⁴ + 12x² + 36 → this is a perfect square trinomial!

Let u = x² → u² + 12u + 36 = (u + 6)²

So back: (x² + 6)²

Thus: 3x³(x² + 6)²

Final Answer for #4: 3x³(x² + 6)²

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Problem 5: 12v² - 4v - 16

Factor out GCF first: 4

= 4(3v² - v - 4)

Now factor 3v² - v - 4

Multiply 3 × (-4) = -12. Need two numbers that multiply to -12 and add to -1 → -4 and +3

Rewrite:
3v² - 4v + 3v - 4

Group:
(3v² - 4v) + (3v - 4)
= v(3v - 4) + 1(3v - 4)
= (v + 1)(3v - 4)

Don’t forget the 4 we factored out!

Final Answer for #5: 4(v + 1)(3v - 4)

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Problem 6: 3x² - 8x + 4

Multiply 3 × 4 = 12. Need two numbers that multiply to 12 and add to -8 → -6 and -2

Rewrite:
3x² - 6x - 2x + 4

Group:
(3x² - 6x) + (-2x + 4)
= 3x(x - 2) -2(x - 2)
= (3x - 2)(x - 2)

Final Answer for #6: (3x - 2)(x - 2)

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Problem 7: 10u³ - 130u² + 400u

Factor out GCF: 10u

= 10u(u² - 13u + 40)

Now factor u² - 13u + 40 → find two numbers that multiply to 40 and add to -13 → -8 and -5

= 10u(u - 8)(u - 5)

Final Answer for #7: 10u(u - 8)(u - 5)

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Problem 8: 121a² - 66ab + 9b²

This looks like a perfect square trinomial.

Check:
√(121a²) = 11a
√(9b²) = 3b
Middle term should be 2*(11a)*(3b) = 66ab → but here it’s -66ab → so sign is negative.

So: (11a - 3b)²

Check: (11a - 3b)² = 121a² - 66ab + 9b²

Final Answer for #8: (11a - 3b)²

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Problem 9: 4w² - 17w - 15

Multiply 4 × (-15) = -60. Need two numbers that multiply to -60 and add to -17 → -20 and +3

Rewrite:
4w² - 20w + 3w - 15

Group:
(4w² - 20w) + (3w - 15)
= 4w(w - 5) + 3(w - 5)
= (4w + 3)(w - 5)

Final Answer for #9: (4w + 3)(w - 5)

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Problem 10: 2k² + 19k - 10

Multiply 2 × (-10) = -20. Need two numbers that multiply to -20 and add to 19 → 20 and -1

Rewrite:
2k² + 20k - k - 10

Group:
(2k² + 20k) + (-k - 10)
= 2k(k + 10) -1(k + 10)
= (2k - 1)(k + 10)

Final Answer for #10: (2k - 1)(k + 10)

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Problem 11: 2m² + 63m + 145

Wait — this is identical to Problem #3! So same answer.

From #3: (2m + 5)(m + 29)

Final Answer for #11: (2m + 5)(m + 29)

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Problem 12: 15a² + 45ab + 60ab²

Wait — let’s check the expression again:
It says “15a² + 45ab + 60ab²”

But note: last term has ab² — different variable power. Let’s write clearly:

Terms:
15a²
+ 45ab
+ 60ab²

All terms have ‘a’ and coefficient divisible by 15? Let’s see GCF.

Coefficients: 15, 45, 60 → GCF = 15
Variables: all have at least one ‘a’ → so factor out 15a

= 15a(a + 3b + 4b²)

Wait — let’s divide each term:

15a² ÷ 15a = a
45ab ÷ 15a = 3b
60ab² ÷ 15a = 4b²

So: 15a(a + 3b + 4b²)

Can we factor inside? a + 3b + 4b² → not really, since ‘a’ is separate from b terms. No common grouping.

So final factored form is 15a(4b² + 3b + a) — usually we write in order of powers of b or alphabetically.

Better to write as: 15a(a + 3b + 4b²) or rearrange: 15a(4b² + 3b + a)

Either is acceptable, but let’s write in standard polynomial order by degree of b:

→ 15a(4b² + 3b + a)

Final Answer for #12: 15a(4b² + 3b + a)

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Final Answers:

1. (x + 1)(3x - 5)
2. (2m + 1)(5m + 6)
3. (2m + 5)(m + 29)
4. 3x³(x² + 6)²
5. 4(v + 1)(3v - 4)
6. (3x - 2)(x - 2)
7. 10u(u - 8)(u - 5)
8. (11a - 3b)²
9. (4w + 3)(w - 5)
10. (2k - 1)(k + 10)
11. (2m + 5)(m + 29)
12. 15a(4b² + 3b + a)
Parent Tip: Review the logic above to help your child master the concept of free factoring worksheet.
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