First Grade Math Worksheets & Workbooks - Free Printable

Let’s solve this step by step.

We need to help Freddy Fish find his coral home by answering all the math problems in the maze. Then, we’ll create a path using only the odd-numbered answers.

---

First, let’s go row by row and calculate each sum.

Row 1:
- 9 + 8 = 17 → odd ✔
- 8 + 6 = 14 → even ✘
- 6 + 7 = 13 → odd ✔
- 2 + 1 = 3 → odd ✔
- 1 + 4 = 5 → odd ✔

Row 2:
- 2 + 1 = 3 → odd ✔
- 1 + 6 = 7 → odd ✔
- 9 + 2 = 11 → odd ✔
- 0 + 8 = 8 → even ✘
- 8 + 5 = 13 → odd ✔

Row 3:
- 0 + 8 = 8 → even ✘
- 7 + 0 = 7 → odd ✔
- 4 + 1 = 5 → odd ✔
- 5 + 8 = 13 → odd ✔
- 8 + 9 = 17 → odd ✔

Row 4:
- 8 + 7 = 15 → odd ✔
- 7 + 2 = 9 → odd ✔
- 2 + 7 = 9 → odd ✔
- 6 + 2 = 8 → even ✘
- 2 + 6 = 8 → even ✘

Row 5:
- 5 + 2 = 7 → odd ✔
- 9 + 2 = 11 → odd ✔
- 8 + 4 = 12 → even ✘
- 5 + 4 = 9 → odd ✔
- 3 + 4 = 7 → odd ✔

Now, let’s mark which cells have odd answers (we’ll use “O” for odd, “E” for even):

```
Row 1: O E O O O
Row 2: O O O E O
Row 3: E O O O O
Row 4: O O O E E
Row 5: O O E O O
```

Freddy starts at the top-left (row 1, col 1) — that’s an odd cell (17). He needs to reach the purple coral at bottom-right (row 5, col 5) — also odd (7).

We can only move to adjacent cells (up, down, left, right) that are also odd.

Let’s trace a possible path:

Start at (1,1) → 17 (odd)

From (1,1), possible moves:
- Right to (1,2): 14 → even → no
- Down to (2,1): 3 → odd → yes!

Go to (2,1)

From (2,1):
- Right to (2,2): 7 → odd → yes
- Down to (3,1): 8 → even → no

Go to (2,2)

From (2,2):
- Right to (2,3): 11 → odd → yes
- Down to (3,2): 7 → odd → yes (two options)

Let’s try going right to (2,3)

From (2,3):
- Right to (2,4): 8 → even → no
- Down to (3,3): 5 → odd → yes

Go to (3,3)

From (3,3):
- Right to (3,4): 13 → odd → yes
- Down to (4,3): 9 → odd → yes

Try right to (3,4)

From (3,4):
- Right to (3,5): 17 → odd → yes
- Down to (4,4): 8 → even → no

Go to (3,5)

From (3,5):
- Down to (4,5): 8 → even → no
- Left? Already came from there.
Wait — stuck? Let’s backtrack.

At (3,4), instead of going right, go down to (4,4)? But (4,4) is even → invalid.

Back to (3,3). Instead of going right, go down to (4,3)

(4,3) = 9 → odd → good

From (4,3):
- Left to (4,2): 9 → odd → yes
- Right to (4,4): 8 → even → no
- Down to (5,3): 12 → even → no

Go left to (4,2)

From (4,2):
- Left to (4,1): 15 → odd → yes
- Down to (5,2): 11 → odd → yes

Try down to (5,2)

From (5,2):
- Right to (5,3): 12 → even → no
- Down? Already at bottom.
- Left to (5,1): 7 → odd → yes

But we want to get to (5,5). From (5,2), can’t go right directly.

Back to (4,2), go left to (4,1)

From (4,1):
- Down to (5,1): 7 → odd → yes

From (5,1):
- Right to (5,2): 11 → odd → yes (already tried)
Still not reaching (5,5).

Alternative path:

After (3,3), go down to (4,3) → then left to (4,2) → then down to (5,2) → then right? (5,3) is even → blocked.

Wait — what about from (3,5)? We were stuck there.

Is there another way?

Let’s try from start:

(1,1) → (2,1) → (2,2) → (3,2) → (3,3) → (3,4) → (3,5) → stuck.

What if from (3,2) we go down to (4,2)?

(3,2) = 7 → odd

Down to (4,2) = 9 → odd → good

Then from (4,2) → (4,1) or (5,2)

Try (5,2) = 11 → odd

From (5,2) → (5,1) or (5,3) — (5,3) is even → only (5,1)

Not helping.

Wait — look at row 5, col 4 and 5:

(5,4) = 9 → odd
(5,5) = 7 → odd

How to get to (5,4)?

From above: (4,4) is even → can’t come from top.

From left: (5,3) is even → can’t come from left.

So (5,4) is isolated? No — wait, (4,4) is even, (5,3) is even — so how do we reach (5,4) and (5,5)?

Unless... did I miscalculate?

Check (5,4): 5 + 4 = 9 → odd → correct
(5,5): 3 + 4 = 7 → odd → correct

But neighbors:

Above (5,4) is (4,4): 6 + 2 = 8 → even → no
Left of (5,4) is (5,3): 8 + 4 = 12 → even → no

So (5,4) has no odd neighbors except (5,5)

Similarly, (5,5) has left neighbor (5,4) — which is odd, and above is (4,5): 2 + 6 = 8 → even → no

So (5,4) and (5,5) are connected to each other, but how to reach them?

This suggests maybe our initial assumption is wrong — perhaps we can start elsewhere? But the problem says "help Freddy Fish find his coral home" — and the fish is at top-left, coral at bottom-right.

Perhaps there’s a different path.

Let me list all odd cells with coordinates (row, col):

Odd cells:

(1,1), (1,3), (1,4), (1,5)
(2,1), (2,2), (2,3), (2,5)
(3,2), (3,3), (3,4), (3,5)
(4,1), (4,2), (4,3)
(5,1), (5,2), (5,4), (5,5)

Now, let’s see connectivity.

Start at (1,1)

Connected to: (2,1) — down

(2,1) connected to: (2,2) — right

(2,2) connected to: (2,3) — right, (3,2) — down

(2,3) connected to: (3,3) — down

(3,2) connected to: (3,3) — right, (4,2) — down

(3,3) connected to: (3,4) — right, (4,3) — down

(3,4) connected to: (3,5) — right

(3,5) — no down (4,5 even), no right — dead end

(4,1) connected to: (4,2) — right, (5,1) — down

(4,2) connected to: (4,3) — right, (5,2) — down

(4,3) — no down (5,3 even), no right (4,4 even) — dead end

(5,1) connected to: (5,2) — right

(5,2) — no right (5,3 even), no down — dead end

(5,4) connected to: (5,5) — right

(5,5) — only left

So the graph has two separate components:

Component 1: (1,1)-(2,1)-(2,2)-(2,3)-(3,3)-(3,4)-(3,5)
and (2,2)-(3,2)-(4,2)-(4,1)-(5,1)-(5,2)
and (3,3)-(4,3)

Component 2: (5,4)-(5,5)

They are not connected! That can’t be right — the maze should have a path.

Did I miss a connection?

What about (1,3)? How to reach it?

(1,3) is odd. Neighbors:

Left: (1,2) = 14 → even
Right: (1,4) = 13 → odd → yes
Down: (2,3) = 11 → odd → yes

So (1,3) is connected to (1,4) and (2,3)

Similarly, (1,4) connected to (1,3), (1,5), and down (2,4)=8 even → no

(1,5) connected to (1,4), and down (2,5)=13 → odd → yes

(2,5) connected to (1,5), and down (3,5)=17 → odd → yes

So actually, (1,3), (1,4), (1,5), (2,5), (3,5) are all connected to the main component via (2,3) or (3,5)

But still, (5,4) and (5,5) are isolated.

Unless... perhaps I made a mistake in (4,4) or (5,3)?

(4,4): 6 + 2 = 8 → even — correct
(5,3): 8 + 4 = 12 → even — correct

But let's double-check the original image description.

The user said: "Answer the problems then create a path using the odd-numbered answers."

And the coral is at bottom-right, fish at top-left.

Perhaps the path doesn't have to be contiguous? But that doesn't make sense for a maze.

Maybe I need to include cells that are odd, and the path is just the sequence of odd cells from start to end, even if not adjacent? But that would be unusual for a maze.

Another idea: perhaps "create a path" means to list the odd answers in order as you traverse, but you can jump? Unlikely.

Let's look back at the grid.

Perhaps I misread the positions.

Let me write the grid with answers:

Row 1: 17, 14, 13, 3, 5
Row 2: 3, 7, 11, 8, 13
Row 3: 8, 7, 5, 13, 17
Row 4: 15, 9, 9, 8, 8
Row 5: 7, 11, 12, 9, 7

Now, let's see if there's a path from (1,1) to (5,5) using only odd cells, moving to adjacent cells.

From (1,1)=17 → down to (2,1)=3 → right to (2,2)=7 → right to (2,3)=11 → down to (3,3)=5 → right to (3,4)=13 → right to (3,5)=17 → now stuck.

From (3,3)=5 → down to (4,3)=9 → left to (4,2)=9 → down to (5,2)=11 → left to (5,1)=7 → dead end.

From (4,2)=9 → right to (4,3)=9 → same as above.

How to get to (5,4)? Only from (5,5) or from above or left, but both are even.

Unless... is (4,4) really even? 6+2=8 — yes.

Perhaps the coral is not at (5,5)? But the image shows purple coral at bottom-right.

Another thought: maybe "path" means to go through the odd cells, and the path is defined by the sequence, and we can move diagonally? But typically mazes allow only orthogonal moves.

Let's try diagonal moves.

From (3,5)=17, down-right to (4,6) — out of bounds.

From (4,3)=9, down-right to (5,4)=9 — oh! If diagonal is allowed, then from (4,3) to (5,4) is diagonal.

Is diagonal allowed? The problem doesn't specify, but in many mazes, only up/down/left/right are allowed.

However, let's check if that works.

If diagonal is allowed, then:

From (4,3)=9 → down-right to (5,4)=9 → then right to (5,5)=7

Perfect!

And (4,3) is reachable from (3,3) or (4,2), etc.

So path could be:

(1,1) -> (2,1) -> (2,2) -> (2,3) -> (3,3) -> (4,3) -> (5,4) -> (5,5)

All these are odd:

(1,1):17, (2,1):3, (2,2):7, (2,3):11, (3,3):5, (4,3):9, (5,4):9, (5,5):7

And if diagonal is allowed, (4,3) to (5,4) is valid.

Perhaps the maze allows diagonal moves, or perhaps I missed a orthogonal path.

Another possibility: from (3,4)=13, down to (4,4)=8 even — no.

Or from (2,5)=13, down to (3,5)=17, then down to (4,5)=8 even — no.

So likely, diagonal move is intended, or perhaps there's a mistake.

Let's see the last row: (5,4) and (5,5) are both odd, and (4,4) is even, (5,3) is even, so only way is diagonal from (4,3) or from (4,5), but (4,5) is even.

(4,5) = 2+6=8 even.

So only from (4,3) diagonally to (5,4).

Perhaps in this maze, diagonal moves are allowed.

Maybe the path doesn't require adjacency, but that seems unlikely.

Another idea: perhaps "create a path" means to list the odd answers in the order they are encountered when solving, but that doesn't make sense.

Let's think differently. Maybe the student is to solve all problems, identify which are odd, and then draw a line connecting them from start to end, and if there's a gap, it's ok, but that seems poor design.

Perhaps I miscalculated (5,3) or (4,4).

Let's double-check the grid from the user's description.

The user provided the grid as:

Row 1: 9+8, 8+6, 6+7, 2+1, 1+4
Row 2: 2+1, 1+6, 9+2, 0+8, 8+5
Row 3: 0+8, 7+0, 4+1, 5+8, 8+9
Row 4: 8+7, 7+2, 2+7, 6+2, 2+6
Row 5: 5+2, 9+2, 8+4, 5+4, 3+4

Calculations:

Row 1: 17, 14, 13, 3, 5
Row 2: 3, 7, 11, 8, 13
Row 3: 8, 7, 5, 13, 17
Row 4: 15, 9, 9, 8, 8
Row 5: 7, 11, 12, 9, 7

Now, let's see if there's a path using only orthogonal moves.

From (1,1) to (5,5):

One possible path:

(1,1) -> (2,1) -> (2,2) -> (3,2) -> (3,3) -> (3,4) -> (3,5) -> then stuck.

From (3,3) -> (4,3) -> (4,2) -> (5,2) -> (5,1) -> stuck.

From (4,2) -> (4,1) -> (5,1) -> stuck.

Notice that (5,4) and (5,5) are not reachable orthogonally from the main group.

Unless... is (4,4) really 8? 6+2=8 — yes.

Perhaps the coral is at (5,4), but the image shows it at bottom-right, which is (5,5).

Another thought: perhaps "path" means to go through the odd cells, and the path is the sequence of answers, and we don't care about adjacency, but that would be strange.

Maybe the student is to circle the odd answers and connect them, and if there's a disconnect, it's ok, but the problem says "create a path", implying a continuous path.

Let's look for a different route.

What if we go from (1,1) -> (2,1) -> (2,2) -> (2,3) -> (1,3) -> (1,4) -> (1,5) -> (2,5) -> (3,5) -> then stuck.

Same issue.

From (3,5) , if we could go down, but (4,5) is even.

Perhaps (4,5) is not 8? 2+6=8 — yes.

Unless the grid is read differently.

Another idea: perhaps the path can go through even cells, but only use odd answers for the path? But the problem says "using the odd-numbered answers", implying only those cells are part of the path.

Let's read the problem again: "Answer the problems then create a path using the odd-numbered answers."

It doesn't say "only through odd-numbered answers", but "using" them, which might mean that the path consists of those cells.

In context, it's likely that the path is made of cells with odd answers, and you move between adjacent such cells.

Given that, and since (5,4) and (5,5) are isolated, perhaps there's a mistake in the problem or in my calculation.

Let's check (5,3): 8+4=12 — even, correct.

(4,4): 6+2=8 — even.

But what about (4,5): 2+6=8 — even.

Perhaps from (3,4) to (4,4) is not allowed, but (3,4) to (4,5) diagonal? (4,5) is even, so not part of path.

I think the only way is to allow diagonal move from (4,3) to (5,4).

Perhaps in this maze, diagonal moves are permitted.

Maybe the coral is at (5,4), but the image shows it at (5,5).

Let's assume that diagonal moves are allowed, as it's common in some mazes.

So path: start at (1,1) -> down to (2,1) -> right to (2,2) -> right to (2,3) -> down to (3,3) -> down to (4,3) -> down-right to (5,4) -> right to (5,5)

All cells have odd answers.

The path is: (1,1), (2,1), (2,2), (2,3), (3,3), (4,3), (5,4), (5,5)

Or alternatively, from (3,3) to (3,4) to (3,5) , but then how to get to (5,4)? Only if diagonal from (3,5) to (4,4) but (4,4) is even, not allowed.

So the first path is better.

To confirm, let's see if there's a shorter path.

From (1,1) -> (2,1) -> (2,2) -> (3,2) -> (4,2) -> (4,3) -> (5,4) -> (5,5)

Also works.

Both are valid if diagonal is allowed.

Since the problem is for a school student, and to make it solvable, likely diagonal moves are intended, or perhaps I missed something.

Another possibility: perhaps "create a path" means to list the odd answers in the order of the cells as you go from start to end, and the path is defined by the sequence, and you can skip even cells, but still need adjacency.

I think for the sake of solving, I'll assume that diagonal moves are allowed, as otherwise it's impossible.

So the path includes the cells with odd answers from start to end, and we can use diagonal moves to connect.

So the final answer is the sequence of odd answers along the path.

But the problem asks to "create a path", so perhaps list the cells or the answers.

Looking at the format, probably they want the path described or the answers listed.

Since it's a maze, likely they want the route taken.

But for the final answer, perhaps list the odd answers in order.

Maybe just state that the path is possible with the given odd cells.

But the instruction is to provide the final answer.

Perhaps the final answer is the path of answers.

Let's see the user's request: "Solve the problem accurately." and "provide the final correct answer".

In such mazes, often the answer is the path or the sequence.

Perhaps for this, since it's a maze, the final answer is the list of odd answers that form the path.

To be safe, I'll provide the path as the sequence of answers.

So one possible path: 17, 3, 7, 11, 5, 9, 9, 7

Corresponding to cells: (1,1), (2,1), (2,2), (2,3), (3,3), (4,3), (5,4), (5,5)

With values: 17, 3, 7, 11, 5, 9, 9, 7

All odd, and if diagonal from (4,3) to (5,4) is allowed, it works.

If not, then it's impossible, but that can't be.

Perhaps from (3,4) to (4,4) is not, but (3,4) to (4,5) diagonal, but (4,5) is even.

I think we have to go with diagonal.

So I'll box the path as the sequence.

But the problem might expect just the final answer as the path description.

Since the user said "Final Answer: [Provide only the final correct answer]", and for a maze, perhaps it's the route.

Maybe they want the list of odd answers that are on the path.

Another idea: perhaps "create a path" means to draw it, but since it's text, maybe list the cells.

I think for this context, the final answer is the sequence of odd numbers along the path from start to end.

So I'll go with that.

Final Answer: 17, 3, 7, 11, 5, 9, 9, 7

To make it clear, perhaps write the path.

But the instruction is to provide only the final correct answer, so likely the sequence.

Perhaps the answer is the path in terms of directions, but that's complicated.

I think listing the answers is fine.

So \boxed{17, 3, 7, 11, 5, 9, 9, 7}

But let's verify if there's a path without diagonal.

Suppose we go: (1,1) -> (2,1) -> (2,2) -> (3,2) -> (3,3) -> (3,4) -> (3,5) -> then from (3,5) , if we could go to (4,5) but it's even, or to (2,5) but already visited.

No.

From (3,3) -> (4,3) -> (4,2) -> (5,2) -> (5,1) -> dead end.

So only with diagonal.

Perhaps the coral is at (5,4), but the image shows it at (5,5).

In the user's description, it says "purple coral" at bottom-right, which is (5,5).

So I think diagonal is intended.

So I'll go with that.

Final Answer: \boxed{17, 3, 7, 11, 5, 9, 9, 7}

To be precise, this is the sequence of answers along the path.

Perhaps they want the path as the cells, but I think this is fine.

Another common way is to list the answers in order.

So I'll box that.

Final Answer

\boxed{17, 3, 7, 11, 5, 9, 9, 7}