To find the slope each tank must use, we need to calculate the "rise over run" between the tank's position and the alien it is targeting.
The formula for slope ($m$) is:
$$m = \frac{y_2 - y_1}{x_2 - x_1}$$
Where $(x_1, y_1)$ is the starting point (the tank) and $(x_2, y_2)$ is the ending point (the alien).
Let's break down each tank one by one.
Tank 1
*
Target: The red multi-eyed alien.
*
Tank Position: Looking at the bottom of the grid, Tank 1 is at $x = 3$, $y = -7$. So, $(3, -7)$.
*
Alien Position: The red alien is at $x = 4$, $y = 4$. So, $(4, 4)$.
*
Calculation:
* Change in $y$ (Rise): $4 - (-7) = 4 + 7 = 11$
* Change in $x$ (Run): $4 - 3 = 1$
* Slope: $\frac{11}{1} = 11$
Tank 2
*
Target: The green one-eyed alien.
*
Tank Position: Tank 2 is at $x = 6$, $y = -7$. So, $(6, -7)$.
*
Alien Position: The green alien is at $x = 2$, $y = 1$. So, $(2, 1)$.
*
Calculation:
* Change in $y$ (Rise): $1 - (-7) = 1 + 7 = 8$
* Change in $x$ (Run): $2 - 6 = -4$
* Slope: $\frac{8}{-4} = -2$
Tank 3
*
Target: The pink octopus alien.
*
Tank Position: Tank 3 is at $x = -6$, $y = -7$. So, $(-6, -7)$.
*
Alien Position: The pink alien is at $x = -6$, $y = -2$. So, $(-6, -2)$.
*
Calculation:
* Change in $y$ (Rise): $-2 - (-7) = -2 + 7 = 5$
* Change in $x$ (Run): $-6 - (-6) = -6 + 6 = 0$
* Slope: $\frac{5}{0}$
* Division by zero is undefined. This means the line is vertical. The slope is
Undefined.
Tank 4
*
Target: The purple one-eyed alien.
*
Tank Position: Tank 4 is at $x = -4$, $y = -7$. So, $(-4, -7)$.
*
Alien Position: The purple alien is at $x = -5$, $y = 5$. So, $(-5, 5)$.
*
Calculation:
* Change in $y$ (Rise): $5 - (-7) = 5 + 7 = 12$
* Change in $x$ (Run): $-5 - (-4) = -5 + 4 = -1$
* Slope: $\frac{12}{-1} = -12$
Final Answer:
Tank 1: 11
Tank 2: -2
Tank 3: Undefined
Tank 4: -12
Parent Tip: Review the logic above to help your child master the concept of fun slope worksheet.