This worksheet provides 12 practice problems for evaluating functions, ranging from simple linear equations to more complex polynomials and exponents.
Evaluating Functions worksheet with 12 algebra problems asking students to substitute values into function equations.
PNG
612×792
5.9 KB
Free · Personal Use
Quality Assured by Worksheets Library Team
Reviewed for educational accuracy and age-appropriateness
ID: #531417
⭐
Show Answer Key & Explanations
Step-by-step solution for: Algebra 2 Worksheets | General Functions Worksheets
▼
Show Answer Key & Explanations
Step-by-step solution for: Algebra 2 Worksheets | General Functions Worksheets
Problem: Evaluate each function.
We are given a series of functions and need to evaluate them for specific inputs. Let's solve each problem step by step.
---
#### 1) \( q(m) = 10m \), Find \( q(2) \)
- The function is \( q(m) = 10m \).
- To find \( q(2) \), substitute \( m = 2 \) into the function:
\[
q(2) = 10 \cdot 2 = 20
\]
Answer: \( \boxed{20} \)
---
#### 2) \( b(w) = -2w^2 - 11 \), Find \( b(-10) \)
- The function is \( b(w) = -2w^2 - 11 \).
- To find \( b(-10) \), substitute \( w = -10 \) into the function:
\[
b(-10) = -2(-10)^2 - 11
\]
Calculate \( (-10)^2 \):
\[
(-10)^2 = 100
\]
Substitute back:
\[
b(-10) = -2(100) - 11 = -200 - 11 = -211
\]
Answer: \( \boxed{-211} \)
---
#### 3) \( x(g) = 2g^2 + 7g \), Find \( x(11) \)
- The function is \( x(g) = 2g^2 + 7g \).
- To find \( x(11) \), substitute \( g = 11 \) into the function:
\[
x(11) = 2(11)^2 + 7(11)
\]
Calculate \( (11)^2 \):
\[
(11)^2 = 121
\]
Substitute back:
\[
x(11) = 2(121) + 7(11) = 242 + 77 = 319
\]
Answer: \( \boxed{319} \)
---
#### 4) \( y(w) = w^3 + 8w^2 \), Find \( y(9) \)
- The function is \( y(w) = w^3 + 8w^2 \).
- To find \( y(9) \), substitute \( w = 9 \) into the function:
\[
y(9) = (9)^3 + 8(9)^2
\]
Calculate \( (9)^3 \) and \( (9)^2 \):
\[
(9)^3 = 729, \quad (9)^2 = 81
\]
Substitute back:
\[
y(9) = 729 + 8(81) = 729 + 648 = 1377
\]
Answer: \( \boxed{1377} \)
---
#### 5) \( z(n) = 3^{n+2} \), Find \( z(1) \)
- The function is \( z(n) = 3^{n+2} \).
- To find \( z(1) \), substitute \( n = 1 \) into the function:
\[
z(1) = 3^{1+2} = 3^3
\]
Calculate \( 3^3 \):
\[
3^3 = 27
\]
Answer: \( \boxed{27} \)
---
#### 6) \( b(n) = (-3)^{2n} \), Find \( b(1) \)
- The function is \( b(n) = (-3)^{2n} \).
- To find \( b(1) \), substitute \( n = 1 \) into the function:
\[
b(1) = (-3)^{2 \cdot 1} = (-3)^2
\]
Calculate \( (-3)^2 \):
\[
(-3)^2 = 9
\]
Answer: \( \boxed{9} \)
---
#### 7) \( b(s) = -10s \), Find \( b(s - 11) \)
- The function is \( b(s) = -10s \).
- To find \( b(s - 11) \), substitute \( s - 11 \) into the function:
\[
b(s - 11) = -10(s - 11)
\]
Distribute the \(-10\):
\[
b(s - 11) = -10s + 110
\]
Answer: \( \boxed{-10s + 110} \)
---
#### 8) \( k(z) = z^2 + 7 \), Find \( k(8z - 2) \)
- The function is \( k(z) = z^2 + 7 \).
- To find \( k(8z - 2) \), substitute \( 8z - 2 \) into the function:
\[
k(8z - 2) = (8z - 2)^2 + 7
\]
Expand \( (8z - 2)^2 \):
\[
(8z - 2)^2 = (8z)^2 - 2 \cdot 8z \cdot 2 + 2^2 = 64z^2 - 32z + 4
\]
Substitute back:
\[
k(8z - 2) = 64z^2 - 32z + 4 + 7 = 64z^2 - 32z + 11
\]
Answer: \( \boxed{64z^2 - 32z + 11} \)
---
#### 9) \( z(q) = -10q^2 - 5q \), Find \( z(q^3) \)
- The function is \( z(q) = -10q^2 - 5q \).
- To find \( z(q^3) \), substitute \( q^3 \) into the function:
\[
z(q^3) = -10(q^3)^2 - 5(q^3)
\]
Simplify \( (q^3)^2 \):
\[
(q^3)^2 = q^6
\]
Substitute back:
\[
z(q^3) = -10q^6 - 5q^3
\]
Answer: \( \boxed{-10q^6 - 5q^3} \)
---
#### 10) \( y(z) = z^3 - 11z^2 \), Find \( y(10z) \)
- The function is \( y(z) = z^3 - 11z^2 \).
- To find \( y(10z) \), substitute \( 10z \) into the function:
\[
y(10z) = (10z)^3 - 11(10z)^2
\]
Calculate \( (10z)^3 \) and \( (10z)^2 \):
\[
(10z)^3 = 1000z^3, \quad (10z)^2 = 100z^2
\]
Substitute back:
\[
y(10z) = 1000z^3 - 11(100z^2) = 1000z^3 - 1100z^2
\]
Answer: \( \boxed{1000z^3 - 1100z^2} \)
---
#### 11) \( p(d) = 3^{2d^2} \), Find \( p(d + 11) \)
- The function is \( p(d) = 3^{2d^2} \).
- To find \( p(d + 11) \), substitute \( d + 11 \) into the function:
\[
p(d + 11) = 3^{2(d + 11)^2}
\]
Expand \( (d + 11)^2 \):
\[
(d + 11)^2 = d^2 + 2 \cdot d \cdot 11 + 11^2 = d^2 + 22d + 121
\]
Substitute back:
\[
p(d + 11) = 3^{2(d^2 + 22d + 121)} = 3^{2d^2 + 44d + 242}
\]
Answer: \( \boxed{3^{2d^2 + 44d + 242}} \)
---
#### 12) \( q(p) = -3^{2p} \), Find \( q(9p) \)
- The function is \( q(p) = -3^{2p} \).
- To find \( q(9p) \), substitute \( 9p \) into the function:
\[
q(9p) = -3^{2(9p)}
\]
Simplify \( 2(9p) \):
\[
2(9p) = 18p
\]
Substitute back:
\[
q(9p) = -3^{18p}
\]
Answer: \( \boxed{-3^{18p}} \)
---
Final Answers:
\[
\boxed{
\begin{aligned}
1) & \ 20 \\
2) & \ -211 \\
3) & \ 319 \\
4) & \ 1377 \\
5) & \ 27 \\
6) & \ 9 \\
7) & \ -10s + 110 \\
8) & \ 64z^2 - 32z + 11 \\
9) & \ -10q^6 - 5q^3 \\
10) & \ 1000z^3 - 1100z^2 \\
11) & \ 3^{2d^2 + 44d + 242} \\
12) & \ -3^{18p}
\end{aligned}
}
\]
Parent Tip: Review the logic above to help your child master the concept of functions math worksheet.