Step function graph with defined intervals and discontinuities on a grid.

It looks like you've uploaded an image of a graph with points plotted on a coordinate plane. Let's analyze the image and solve the problem based on what we can see.

Observations from the Image:

The graph shows a set of points plotted on a coordinate grid with integer values from -3 to 3 on both axes. The points are marked with solid red dots and open circles, which typically indicate whether a point is included (closed dot) or excluded (open circle) in a relation or function.

Let’s list the coordinates of the points shown:

- At $ x = -2 $:
- A solid dot at $ (-2, -2) $
- An open circle at $ (-2, -1) $

- At $ x = -1 $:
- A solid dot at $ (-1, -1) $

- At $ x = 0 $:
- A solid dot at $ (0, 0) $

- At $ x = 1 $:
- A solid dot at $ (1, 1) $
- An open circle at $ (1, 2) $

- At $ x = 2 $:
- An open circle at $ (2, 1) $

Wait — actually, looking more carefully:

- There is a horizontal line segment from $ x = 0 $ to $ x = 1 $ at $ y = 0 $, but it's not clear if it's part of a function or just connecting points.

But upon closer inspection:

There are discrete points, not continuous lines. Let's list them clearly:

Points:

- $ (-2, -2) $ → solid dot (included)
- $ (-2, -1) $ → open circle (not included)
- $ (-1, -1) $ → solid dot
- $ (0, 0) $ → solid dot
- $ (1, 1) $ → solid dot
- $ (1, 2) $ → open circle (not included)
- $ (2, 1) $ → open circle (not included)

Also, there seems to be a horizontal segment from $ (0, 0) $ to $ (1, 0) $? But wait — no, that might be a misinterpretation.

Actually, the only solid dots are:
- $ (-2, -2) $
- $ (-1, -1) $
- $ (0, 0) $
- $ (1, 1) $

And open circles at:
- $ (-2, -1) $
- $ (1, 2) $
- $ (2, 1) $

Wait — let's re-express this properly.

Looking again:

- At $ x = -2 $: one solid dot at $ y = -2 $, and an open circle at $ y = -1 $
- At $ x = -1 $: one solid dot at $ y = -1 $
- At $ x = 0 $: one solid dot at $ y = 0 $
- At $ x = 1 $: one solid dot at $ y = 1 $, and an open circle at $ y = 2 $
- At $ x = 2 $: an open circle at $ y = 1 $

So the defined points (solid dots) are:
- $ (-2, -2) $
- $ (-1, -1) $
- $ (0, 0) $
- $ (1, 1) $

These look like they lie on the line $ y = x $. But we need to determine what the task is.

Since you said "I uploaded an image with a task", but didn't specify the question, I'll assume common tasks for such graphs.

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Possible Tasks & Solutions

#### Task 1: Determine if the relation is a function

A relation is a function if each input ($ x $) has only one output ($ y $).

Check the $ x $-values:
- $ x = -2 $: only one solid dot at $ y = -2 $ → OK
- $ x = -1 $: one point → OK
- $ x = 0 $: one point → OK
- $ x = 1 $: one solid dot at $ y = 1 $ → OK
- $ x = 2 $: only an open circle at $ y = 1 $ → not included, so no value

Even though there's an open circle at $ (2, 1) $, it's not included, so $ x = 2 $ is not in the domain.

Each $ x $ in the domain maps to exactly one $ y $.

✔ So, this relation is a function.

#### Task 2: Find the domain and range

Domain: all $ x $-values where there is a solid dot.
- $ x = -2, -1, 0, 1 $
- So, domain = { -2, -1, 0, 1 }

Range: all $ y $-values from solid dots.
- $ y = -2, -1, 0, 1 $
- So, range = { -2, -1, 0, 1 }

#### Task 3: Is the function increasing?

Yes. As $ x $ increases from $-2$ to $1$, $ y $ increases from $-2$ to $1$. Each step increases by 1.

So, the function is increasing.

#### Task 4: What is the equation?

The points $ (-2,-2), (-1,-1), (0,0), (1,1) $ lie on the line $ y = x $.

So, the function is:
$$
f(x) = x \quad \text{for} \quad x \in \{-2, -1, 0, 1\}
$$

Note: It's not defined at $ x = 2 $, even though $ (2,1) $ is near, because it's an open circle.

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Final Answer (assuming the task was to determine if it's a function and find domain/range):

✔ Yes, it is a function.

- Domain: $ \{-2, -1, 0, 1\} $
- Range: $ \{-2, -1, 0, 1\} $
- Function rule: $ f(x) = x $ for $ x \in \{-2, -1, 0, 1\} $

Let me know if the actual task was different (e.g., find slope, complete a table, etc.), and I can adjust accordingly.