Genetics practice worksheet focusing on pedigree tables for colorblindness, with a chart and related questions.

- The mother at 3 must be a carrier (X^C X^c) because her son (8) is colorblind (X^c Y), and he inherited the X^c allele from her.
- Son 8 got his colorblindness allele (X^c) from his mother (3), since males inherit their X chromosome from their mother.
- Parents 1 and 2 are not colorblind, but they had a colorblind son (6) because the mother (1) is a carrier (X^C X^c) and passed the recessive X^c allele to her son.
- For a daughter to be colorblind (X^c X^c), she must inherit an X^c allele from both parents; thus, her father must be colorblind (X^c Y) and her mother must be either colorblind (X^c X^c) or a carrier (X^C X^c).
- If number 13 (a carrier, X^C X^c) marries a normal man (X^C Y), the probability that their sons will be colorblind is 50%, as each son has a 50% chance of inheriting the X^c allele from his mother.