Copy of Copy of Genetics Practice Problems - Easy Mode - Name ... - Free Printable

I'll solve this genetics problem step by step.

This is a Punnett square exercise about guinea pig traits. Let me work through each part:

Part 1:
The question asks to cross two heterozygous parents (Bb x Bb).

The Punnett square shows:
- Top row: B and b (from one parent)
- Left column: B and b (from the other parent)
- Four boxes filled in: BB, Bb, Bb, bb

For offspring that are homozygous dominant (BB): 1 out of 4 = 25% or 1/4

Part 2:
Cross between Bb x BB

The Punnett square shows:
- Top row: B and B (from BB parent)
- Left column: B and b (from Bb parent)
- Four boxes: BB, BB, Bb, Bb

All offspring will have at least one B allele, so all will show the dominant trait.
Offspring with genotype BB: 2 out of 4 = 50% or 2/4 = 1/2
Offspring with genotype Bb: 2 out of 4 = 50% or 2/4 = 1/2

Part 3:
Cross between Bb x bb

The Punnett square needs to be completed:
- Top row: b and b (from bb parent)
- Left column: B and b (from Bb parent)

Filling in the squares:
- Top left: Bb
- Top right: Bb
- Bottom left: bb
- Bottom right: bb

Results:
- 2 out of 4 = 50% will be Bb (heterozygous)
- 2 out of 4 = 50% will be bb (homozygous recessive)

Final Answer:
Part 1: 25% (or 1/4)
Part 2: 50% BB and 50% Bb (or 1/2 BB and 1/2 Bb)
Part 3: The completed Punnett square should show: Bb, Bb, bb, bb - resulting in 50% Bb and 50% bb