Colorful wheel divided into red, blue, green, and yellow sections with labels and a central arrow.

Problem Description:

The image shows a spinner divided into 10 equal sections, each colored differently. The colors are as follows:
- Blue: 3 sections
- Red: 4 sections
- Green: 3 sections
- Yellow: 1 section

The task is to determine the probability of the spinner landing on a specific color when spun.

Solution:

#### Step 1: Understand the Total Number of Outcomes
The spinner is divided into 10 equal sections. Therefore, the total number of possible outcomes when the spinner is spun is:
\[
\text{Total outcomes} = 10
\]

#### Step 2: Determine the Number of Favorable Outcomes for Each Color
- Blue: There are 3 sections colored blue.
- Red: There are 4 sections colored red.
- Green: There are 3 sections colored green.
- Yellow: There is 1 section colored yellow.

#### Step 3: Calculate the Probability for Each Color
The probability \( P \) of the spinner landing on a specific color is given by the ratio of the number of favorable outcomes to the total number of outcomes. Mathematically:
\[
P(\text{Color}) = \frac{\text{Number of sections of that color}}{\text{Total number of sections}}
\]

- Probability of landing on Blue:
\[
P(\text{Blue}) = \frac{3}{10}
\]

- Probability of landing on Red:
\[
P(\text{Red}) = \frac{4}{10} = \frac{2}{5}
\]

- Probability of landing on Green:
\[
P(\text{Green}) = \frac{3}{10}
\]

- Probability of landing on Yellow:
\[
P(\text{Yellow}) = \frac{1}{10}
\]

#### Step 4: Verify the Probabilities
To ensure correctness, the sum of the probabilities of all possible outcomes should equal 1:
\[
P(\text{Blue}) + P(\text{Red}) + P(\text{Green}) + P(\text{Yellow}) = \frac{3}{10} + \frac{4}{10} + \frac{3}{10} + \frac{1}{10} = \frac{11}{10} = 1
\]
The probabilities are correct.

Final Answer:

The probabilities of the spinner landing on each color are:
\[
\boxed{\frac{3}{10} \text{ (Blue)}, \frac{2}{5} \text{ (Red)}, \frac{3}{10} \text{ (Green)}, \frac{1}{10} \text{ (Yellow)}}
\]