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Geometry worksheet for calculating distance between two points using the distance formula.

Worksheet titled "Distance Formula" with 12 problems asking to find the distance between two points in the coordinate plane.

Worksheet titled "Distance Formula" with 12 problems asking to find the distance between two points in the coordinate plane.

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Show Answer Key & Explanations Step-by-step solution for: Distance Formula Worksheets 8.G.B.8 by The STEM Master worksheets library
I will solve this geometry problem by calculating the distance between each pair of points using the distance formula. The distance formula for two points $(x_1, y_1)$ and $(x_2, y_2)$ in a coordinate plane is:

$$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$$

I'll go through each problem one by one.

Problem 1: (4,3) and (6,5)
$d = \sqrt{(6-4)^2 + (5-3)^2} = \sqrt{2^2 + 2^2} = \sqrt{4 + 4} = \sqrt{8} = 2\sqrt{2}$

Problem 2: (5,2) and (3,4)
$d = \sqrt{(3-5)^2 + (4-2)^2} = \sqrt{(-2)^2 + 2^2} = \sqrt{4 + 4} = \sqrt{8} = 2\sqrt{2}$

Problem 3: (0,3) and (2,7)
$d = \sqrt{(2-0)^2 + (7-3)^2} = \sqrt{2^2 + 4^2} = \sqrt{4 + 16} = \sqrt{20} = 2\sqrt{5}$

Problem 4: (4,0) and (2,6)
$d = \sqrt{(2-4)^2 + (6-0)^2} = \sqrt{(-2)^2 + 6^2} = \sqrt{4 + 36} = \sqrt{40} = 2\sqrt{10}$

Problem 5: (0,0) and (6,2)
$d = \sqrt{(6-0)^2 + (2-0)^2} = \sqrt{6^2 + 2^2} = \sqrt{36 + 4} = \sqrt{40} = 2\sqrt{10}$

Problem 6: (-2,6) and (-4,8)
$d = \sqrt{(-4-(-2))^2 + (8-6)^2} = \sqrt{(-2)^2 + 2^2} = \sqrt{4 + 4} = \sqrt{8} = 2\sqrt{2}$

Problem 7: (1,6) and (3,8)
$d = \sqrt{(3-1)^2 + (8-6)^2} = \sqrt{2^2 + 2^2} = \sqrt{4 + 4} = \sqrt{8} = 2\sqrt{2}$

Problem 8: (-5,-2) and (-3,0)
$d = \sqrt{(-3-(-5))^2 + (0-(-2))^2} = \sqrt{2^2 + 2^2} = \sqrt{4 + 4} = \sqrt{8} = 2\sqrt{2}$

Problem 9: (1,6) and (4,0)
$d = \sqrt{(4-1)^2 + (0-6)^2} = \sqrt{3^2 + (-6)^2} = \sqrt{9 + 36} = \sqrt{45} = 3\sqrt{5}$

Problem 10: (6,1) and (-3,6)
$d = \sqrt{(-3-6)^2 + (6-1)^2} = \sqrt{(-9)^2 + 5^2} = \sqrt{81 + 25} = \sqrt{106}$

Problem 11: (-2,4) and (2,-4)
$d = \sqrt{(2-(-2))^2 + (-4-4)^2} = \sqrt{4^2 + (-8)^2} = \sqrt{16 + 64} = \sqrt{80} = 4\sqrt{5}$

Problem 12: (7,6) and (3,-8)
$d = \sqrt{(3-7)^2 + (-8-6)^2} = \sqrt{(-4)^2 + (-14)^2} = \sqrt{16 + 196} = \sqrt{212} = 2\sqrt{53}$

Here are the solutions for all 12 problems:
1. $2\sqrt{2}$
2. $2\sqrt{2}$
3. $2\sqrt{5}$
4. $2\sqrt{10}$
5. $2\sqrt{10}$
6. $2\sqrt{2}$
7. $2\sqrt{2}$
8. $2\sqrt{2}$
9. $3\sqrt{5}$
10. $\sqrt{106}$
11. $4\sqrt{5}$
12. $2\sqrt{53}$
Parent Tip: Review the logic above to help your child master the concept of geometry distance formula worksheet.
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