Perimeter of Kites Worksheets - Free Printable

To solve the problem of finding the perimeter of each kite, we need to use the definition of the perimeter of a kite. The perimeter of a kite is the sum of the lengths of all its sides.

Key Points:

1. A kite has two pairs of adjacent sides that are equal in length.
2. To find the perimeter, add up the lengths of all four sides.

Let's solve each problem step by step.

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Problem 1:

- Sides: \(6 \, \text{yd}\) and \(4 \, \text{yd}\)
- Since it's a kite, the two pairs of adjacent sides are equal:
- One pair: \(6 \, \text{yd}, 6 \, \text{yd}\)
- Other pair: \(4 \, \text{yd}, 4 \, \text{yd}\)
- Perimeter = \(6 + 6 + 4 + 4 = 20 \, \text{yd}\)

Answer: \( \boxed{20 \, \text{yd}} \)

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Problem 2:

- Sides: \(11 \, \text{ft}\) and \(19 \, \text{ft}\)
- Since it's a kite, the two pairs of adjacent sides are equal:
- One pair: \(11 \, \text{ft}, 11 \, \text{ft}\)
- Other pair: \(19 \, \text{ft}, 19 \, \text{ft}\)
- Perimeter = \(11 + 11 + 19 + 19 = 60 \, \text{ft}\)

Answer: \( \boxed{60 \, \text{ft}} \)

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Problem 3:

- Sides: \(10 \, \text{in}\) and \(7 \, \text{in}\)
- Since it's a kite, the two pairs of adjacent sides are equal:
- One pair: \(10 \, \text{in}, 10 \, \text{in}\)
- Other pair: \(7 \, \text{in}, 7 \, \text{in}\)
- Perimeter = \(10 + 10 + 7 + 7 = 34 \, \text{in}\)

Answer: \( \boxed{34 \, \text{in}} \)

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Problem 4:

- Sides: \(8 \, \text{ft}\) and \(5.5 \, \text{ft}\)
- Since it's a kite, the two pairs of adjacent sides are equal:
- One pair: \(8 \, \text{ft}, 8 \, \text{ft}\)
- Other pair: \(5.5 \, \text{ft}, 5.5 \, \text{ft}\)
- Perimeter = \(8 + 8 + 5.5 + 5.5 = 27 \, \text{ft}\)

Answer: \( \boxed{27 \, \text{ft}} \)

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Problem 5:

- Sides: \(9 \, \text{in}\) and \(20 \, \text{in}\)
- Since it's a kite, the two pairs of adjacent sides are equal:
- One pair: \(9 \, \text{in}, 9 \, \text{in}\)
- Other pair: \(20 \, \text{in}, 20 \, \text{in}\)
- Perimeter = \(9 + 9 + 20 + 20 = 58 \, \text{in}\)

Answer: \( \boxed{58 \, \text{in}} \)

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Problem 6:

- Sides: \(17 \, \text{yd}\) and \(3 \, \text{yd}\)
- Since it's a kite, the two pairs of adjacent sides are equal:
- One pair: \(17 \, \text{yd}, 17 \, \text{yd}\)
- Other pair: \(3 \, \text{yd}, 3 \, \text{yd}\)
- Perimeter = \(17 + 17 + 3 + 3 = 40 \, \text{yd}\)

Answer: \( \boxed{40 \, \text{yd}} \)

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Problem 7:

- Sides: \(16 \, \text{in}\) and \(8 \, \text{in}\)
- Since it's a kite, the two pairs of adjacent sides are equal:
- One pair: \(16 \, \text{in}, 16 \, \text{in}\)
- Other pair: \(8 \, \text{in}, 8 \, \text{in}\)
- Perimeter = \(16 + 16 + 8 + 8 = 48 \, \text{in}\)

Answer: \( \boxed{48 \, \text{in}} \)

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Problem 8:

- Sides: \(7 \, \text{yd}\) and \(12 \, \text{yd}\)
- Since it's a kite, the two pairs of adjacent sides are equal:
- One pair: \(7 \, \text{yd}, 7 \, \text{yd}\)
- Other pair: \(12 \, \text{yd}, 12 \, \text{yd}\)
- Perimeter = \(7 + 7 + 12 + 12 = 38 \, \text{yd}\)

Answer: \( \boxed{38 \, \text{yd}} \)

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Problem 9:

- Sides: \(13 \, \text{ft}\) and \(4 \, \text{ft}\)
- Since it's a kite, the two pairs of adjacent sides are equal:
- One pair: \(13 \, \text{ft}, 13 \, \text{ft}\)
- Other pair: \(4 \, \text{ft}, 4 \, \text{ft}\)
- Perimeter = \(13 + 13 + 4 + 4 = 34 \, \text{ft}\)

Answer: \( \boxed{34 \, \text{ft}} \)

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Final Answers:

1. \( \boxed{20 \, \text{yd}} \)
2. \( \boxed{60 \, \text{ft}} \)
3. \( \boxed{34 \, \text{in}} \)
4. \( \boxed{27 \, \text{ft}} \)
5. \( \boxed{58 \, \text{in}} \)
6. \( \boxed{40 \, \text{yd}} \)
7. \( \boxed{48 \, \text{in}} \)
8. \( \boxed{38 \, \text{yd}} \)
9. \( \boxed{34 \, \text{ft}} \)