Let’s solve each addition problem one by one.
1) 3 + 2 = 5
2) 2 + 3 = 5
3) 1 + 4 = 5
4) 4 + 1 = 5
5) 5 + 2 = 7
6) 6 + 1 = 7
7) 0 + 3 = 3
8) 3 + 2 = 5
9) 5 + 1 = 6
10) 2 + 4 = 6
11) 2 + 5 = 7
12) 5 + 3 = 8
13) 7 + 2 = 9
14) 1 + 7 = 8
15) 5 + 2 = 7
16) 4 + 4 = 8
17) 2 + 6 = 8
18) 1 + 9 = 10
19) 3 + 5 = 8
20) 8 + 2 = 10
Now, let’s check the key question:
“what happens when you change the order of the numbers: 3 + 6 and 6 + 3; 2 + 5 and 5 + 2?”
Try them:
3 + 6 = 9
6 + 3 = 9 → same answer!
2 + 5 = 7
5 + 2 = 7 → also same!
So, changing the order doesn’t change the total. That’s called the “commutative property” — but we can just say: “It doesn’t matter which number comes first — the sum stays the same.”
Final Answer:
The answers to problems 1–20 are:
1) 5, 2) 5, 3) 5, 4) 5, 5) 7, 6) 7, 7) 3, 8) 5, 9) 6, 10) 6,
11) 7, 12) 8, 13) 9, 14) 8, 15) 7, 16) 8, 17) 8, 18) 10, 19) 8, 20) 10.
And for the key question: Changing the order of the numbers in addition does not change the result.
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