Problem Analysis:
The image contains two sets of math puzzles, each involving different symbols (fruits and desserts). The goal is to determine the value of each symbol and then solve for the unknowns in the last equations.
####
Left Puzzle (Fruits):
1. Watermelon slices + Watermelon slices = 16
2. Kiwi + Watermelon slices = 18
3. Kiwi + Pear = 15
4. Watermelon slices + Pear = ?
####
Right Puzzle (Desserts):
1. Ice cream sandwich × Ice cream sandwich = 36
2. Popsicle + Ice cream sandwich = 36
3. Popsicle - Ice cream cone = 20
4. Ice cream cones + Ice cream sandwich = ?
---
Step-by-Step Solution:
####
Left Puzzle (Fruits):
1.
Watermelon slices + Watermelon slices = 16
- Let the value of one watermelon slice be \( W \).
- Then, \( 2W = 16 \).
- Solving for \( W \):
\[
W = \frac{16}{2} = 8
\]
- So, one watermelon slice is worth
8.
2.
Kiwi + Watermelon slices = 18
- Let the value of one kiwi be \( K \).
- From the first equation, we know \( W = 8 \).
- Substitute \( W \) into the equation:
\[
K + 8 = 18
\]
- Solving for \( K \):
\[
K = 18 - 8 = 10
\]
- So, one kiwi is worth
10.
3.
Kiwi + Pear = 15
- Let the value of one pear be \( P \).
- From the second equation, we know \( K = 10 \).
- Substitute \( K \) into the equation:
\[
10 + P = 15
\]
- Solving for \( P \):
\[
P = 15 - 10 = 5
\]
- So, one pear is worth
5.
4.
Watermelon slices + Pear = ?
- We know \( W = 8 \) and \( P = 5 \).
- Substitute these values into the equation:
\[
W + P = 8 + 5 = 13
\]
- So, the answer is
13.
---
####
Right Puzzle (Desserts):
1.
Ice cream sandwich × Ice cream sandwich = 36
- Let the value of one ice cream sandwich be \( S \).
- Then, \( S \times S = 36 \).
- Solving for \( S \):
\[
S^2 = 36 \implies S = \sqrt{36} = 6
\]
- So, one ice cream sandwich is worth
6.
2.
Popsicle + Ice cream sandwich = 36
- Let the value of one popsicle be \( P \).
- From the first equation, we know \( S = 6 \).
- Substitute \( S \) into the equation:
\[
P + 6 = 36
\]
- Solving for \( P \):
\[
P = 36 - 6 = 30
\]
- So, one popsicle is worth
30.
3.
Popsicle - Ice cream cone = 20
- Let the value of one ice cream cone be \( C \).
- From the second equation, we know \( P = 30 \).
- Substitute \( P \) into the equation:
\[
30 - C = 20
\]
- Solving for \( C \):
\[
C = 30 - 20 = 10
\]
- So, one ice cream cone is worth
10.
4.
Ice cream cones + Ice cream sandwich = ?
- We know \( C = 10 \) and \( S = 6 \).
- Substitute these values into the equation:
\[
C + S = 10 + 6 = 16
\]
- So, the answer is
16.
---
Final Answers:
- For the left puzzle:
13
- For the right puzzle:
16
\[
\boxed{13, 16}
\]
Parent Tip: Review the logic above to help your child master the concept of grade 3 math activities.
