Grade 5- Final Test - Math Interactive Worksheet - Edform - Free Printable

$Grade 5- Final Test - Math Interactive Worksheet - Edform$

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Problem 28:

Question: $ 15.12 \div 2.4 = $

#### Solution:
1. To simplify the division, we can eliminate the decimal by multiplying both the numerator and the denominator by 10:
\[
15.12 \div 2.4 = \frac{15.12}{2.4} = \frac{15.12 \times 10}{2.4 \times 10} = \frac{151.2}{24}
\]
2. Now, perform the division $ 151.2 \div 24 $:
\[
151.2 \div 24 = 6.3
\]

#### Answer:
\[
\boxed{D}
\]

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Problem 29:

Question: $ 35,705 \div 37 = $

#### Solution:
1. Perform the long division of $ 35,705 $ by $ 37 $:
- $ 35 $ is less than $ 37 $, so consider $ 357 $.
- $ 357 \div 37 = 9 $ (since $ 37 \times 9 = 333 $).
- Subtract $ 333 $ from $ 357 $: $ 357 - 333 = 24 $.
- Bring down the next digit $ 0 $: $ 240 $.
- $ 240 \div 37 = 6 $ (since $ 37 \times 6 = 222 $).
- Subtract $ 222 $ from $ 240 $: $ 240 - 222 = 18 $.
- Bring down the next digit $ 5 $: $ 185 $.
- $ 185 \div 37 = 5 $ (since $ 37 \times 5 = 185 $).
- Subtract $ 185 $ from $ 185 $: $ 185 - 185 = 0 $.

The quotient is $ 965 $.

#### Answer:
\[
\boxed{D}
\]

---

Problem 30:

Question: At a school, there are 704 desks to place into 22 classrooms. If the same number of desks is placed in each classroom, how many desks will be in each room?

#### Solution:
1. Divide the total number of desks by the number of classrooms:
\[
704 \div 22
\]
2. Perform the division:
- $ 70 \div 22 = 3 $ (since $ 22 \times 3 = 66 $).
- Subtract $ 66 $ from $ 70 $: $ 70 - 66 = 4 $.
- Bring down the next digit $ 4 $: $ 44 $.
- $ 44 \div 22 = 2 $ (since $ 22 \times 2 = 44 $).
- Subtract $ 44 $ from $ 44 $: $ 44 - 44 = 0 $.

The quotient is $ 32 $.

#### Answer:
\[
\boxed{A}
\]

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Problem 31:

Question: What is the answer to this division problem? $ 12 \div 246 $

#### Solution:
1. Perform the division $ 246 \div 12 $:
- $ 24 \div 12 = 2 $ (since $ 12 \times 2 = 24 $).
- Subtract $ 24 $ from $ 24 $: $ 24 - 24 = 0 $.
- Bring down the next digit $ 6 $: $ 6 $.
- $ 6 \div 12 = 0 $ (since $ 12 \times 0 = 0 $).
- Subtract $ 0 $ from $ 6 $: $ 6 - 0 = 6 $.

The quotient is $ 20.5 $.

#### Answer:
\[
\boxed{C}
\]

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Problem 32:

Question: Maurice talked on the telephone to two friends. He talked to Sherry for $ \frac{1}{4} $ hour and to Gabriel for $ \frac{1}{3} $ hour. How much time did Maurice spend on the telephone?

#### Solution:
1. Add the fractions $ \frac{1}{4} $ and $ \frac{1}{3} $:
- Find the least common denominator (LCD) of 4 and 3, which is 12.
- Convert the fractions:
\[
\frac{1}{4} = \frac{1 \times 3}{4 \times 3} = \frac{3}{12}
\]
\[
\frac{1}{3} = \frac{1 \times 4}{3 \times 4} = \frac{4}{12}
\]
- Add the fractions:
\[
\frac{3}{12} + \frac{4}{12} = \frac{7}{12}
\]

#### Answer:
\[
\boxed{D}
\]

---

Problem 33:

Question: $ 2 \frac{1}{3} + 4 \frac{1}{2} = $

#### Solution:
1. Convert the mixed numbers to improper fractions:
- $ 2 \frac{1}{3} = 2 + \frac{1}{3} = \frac{6}{3} + \frac{1}{3} = \frac{7}{3} $
- $ 4 \frac{1}{2} = 4 + \frac{1}{2} = \frac{8}{2} + \frac{1}{2} = \frac{9}{2} $
2. Add the fractions:
- Find the least common denominator (LCD) of 3 and 2, which is 6.
- Convert the fractions:
\[
\frac{7}{3} = \frac{7 \times 2}{3 \times 2} = \frac{14}{6}
\]
\[
\frac{9}{2} = \frac{9 \times 3}{2 \times 3} = \frac{27}{6}
\]
- Add the fractions:
\[
\frac{14}{6} + \frac{27}{6} = \frac{41}{6}
\]
3. Convert the improper fraction back to a mixed number:
- $ \frac{41}{6} = 6 \frac{5}{6} $

#### Answer:
\[
\boxed{D}
\]

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