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Worksheet for graphing quadratic functions with a=1, featuring four equations and corresponding coordinate grids.

Graph of quadratic functions with a=1, showing four problems with equations y = x² - 6x + 4, y = x² + 2x - 5, y = x² - 3, and y = x² + 6x + 1, each with a coordinate grid for graphing.

Graph of quadratic functions with a=1, showing four problems with equations y = x² - 6x + 4, y = x² + 2x - 5, y = x² - 3, and y = x² + 6x + 1, each with a coordinate grid for graphing.

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You're given a worksheet titled “Graph quadratic functions with a=1” — meaning all the parabolas open upward (since the leading coefficient is positive 1) and have the same “width” as the parent function $ y = x^2 $. Your task is to graph each quadratic function by identifying key features: vertex, axis of symmetry, y-intercept, and possibly x-intercepts or additional points.

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Let’s solve each one step-by-step and explain how to graph them.

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## 🔹 Problem 1: $ y = x^2 - 6x + 4 $

Step 1: Find the vertex


Use the formula for the x-coordinate of the vertex:
$ x = \frac{-b}{2a} $

Here, $ a = 1 $, $ b = -6 $, so:

→ $ x = \frac{-(-6)}{2(1)} = \frac{6}{2} = 3 $

Now plug into the equation to find y:

→ $ y = (3)^2 - 6(3) + 4 = 9 - 18 + 4 = -5 $

Vertex: (3, -5)

Step 2: Axis of symmetry


→ Vertical line through vertex: $ x = 3 $

Step 3: Y-intercept


Set $ x = 0 $:

→ $ y = 0 - 0 + 4 = 4 $

Y-intercept: (0, 4)

Step 4: X-intercepts (optional, if needed)


Solve $ x^2 - 6x + 4 = 0 $

Use quadratic formula:

→ $ x = \frac{6 \pm \sqrt{(-6)^2 - 4(1)(4)}}{2(1)} = \frac{6 \pm \sqrt{36 - 16}}{2} = \frac{6 \pm \sqrt{20}}{2} = \frac{6 \pm 2\sqrt{5}}{2} = 3 \pm \sqrt{5} $

→ Approximate: $ \sqrt{5} \approx 2.24 $ → x ≈ 0.76 and 5.24

X-intercepts: approx (0.76, 0) and (5.24, 0)

Step 5: Plot points and sketch


- Vertex at (3, -5)
- Y-intercept at (0, 4)
- Use symmetry: since axis is x=3, point (0,4) reflects to (6,4)
- Add another point, say x=1: y = 1 -6 +4 = -1 → (1, -1); symmetric point x=5: y=25-30+4=-1 → (5,-1)

Plot these points and draw a smooth U-shaped curve.

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## 🔹 Problem 2: $ y = x^2 + 2x - 5 $

Step 1: Vertex


$ x = \frac{-b}{2a} = \frac{-2}{2(1)} = -1 $

→ $ y = (-1)^2 + 2(-1) - 5 = 1 - 2 - 5 = -6 $

Vertex: (-1, -6)

Step 2: Axis of symmetry → $ x = -1 $



Step 3: Y-intercept → x=0: y = 0 + 0 -5 = -5 → (0, -5)



Step 4: X-intercepts


Solve $ x^2 + 2x - 5 = 0 $

→ $ x = \frac{-2 \pm \sqrt{4 + 20}}{2} = \frac{-2 \pm \sqrt{24}}{2} = \frac{-2 \pm 2\sqrt{6}}{2} = -1 \pm \sqrt{6} $

→ $ \sqrt{6} \approx 2.45 $ → x ≈ 1.45 and -3.45

X-intercepts: approx (1.45, 0) and (-3.45, 0)

Step 5: Additional points


Use symmetry: y-intercept (0, -5) reflects over x=-1 → (-2, -5)

Try x=1: y=1+2-5=-2 → (1,-2); symmetric point x=-3: y=9-6-5=-2 → (-3,-2)

Plot vertex (-1,-6), y-int (0,-5), x-ints (~1.45,0) and (~-3.45,0), and other points. Draw parabola.

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## 🔹 Problem 3: $ y = x^2 - 3 $

This is a simple vertical shift of $ y = x^2 $

Step 1: Vertex


Since no x-term, vertex is at (0, -3)

Vertex: (0, -3)

Step 2: Axis of symmetry → x=0 (y-axis)



Step 3: Y-intercept → (0, -3) — same as vertex



Step 4: X-intercepts


Solve $ x^2 - 3 = 0 $ → $ x^2 = 3 $ → $ x = \pm \sqrt{3} \approx \pm 1.73 $

X-intercepts: approx (1.73, 0) and (-1.73, 0)

Step 5: Additional points


x=1 → y=1-3=-2 → (1,-2); symmetric point (-1,-2)
x=2 → y=4-3=1 → (2,1); symmetric point (-2,1)

Plot these points and draw symmetric U-shape opening up from vertex (0,-3).

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## 🔹 Problem 4: $ y = x^2 + 6x + 1 $

Step 1: Vertex


$ x = \frac{-6}{2(1)} = -3 $

→ $ y = (-3)^2 + 6(-3) + 1 = 9 - 18 + 1 = -8 $

Vertex: (-3, -8)

Step 2: Axis of symmetry → x = -3



Step 3: Y-intercept → x=0: y = 0 + 0 + 1 = 1 → (0,1)



Step 4: X-intercepts


Solve $ x^2 + 6x + 1 = 0 $

→ $ x = \frac{-6 \pm \sqrt{36 - 4}}{2} = \frac{-6 \pm \sqrt{32}}{2} = \frac{-6 \pm 4\sqrt{2}}{2} = -3 \pm 2\sqrt{2} $

→ $ \sqrt{2} \approx 1.41 $ → x ≈ -3 ± 2.82 → x ≈ -0.18 and -5.82

X-intercepts: approx (-0.18, 0) and (-5.82, 0)

Step 5: Additional points


Use symmetry: y-int (0,1) reflects over x=-3 → (-6,1)

Try x=-1: y=1-6+1=-4 → (-1,-4); symmetric point x=-5: y=25-30+1=-4 → (-5,-4)

Plot vertex (-3,-8), y-int (0,1), x-ints (~-0.18,0) and (~-5.82,0), and symmetric points. Draw parabola.

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## Summary for Graphing Each:

| Problem | Vertex | Axis of Symmetry | Y-intercept | Key Points to Plot |
|---------|--------------|------------------|-------------|---------------------------------------------|
| 1 | (3, -5) | x=3 | (0,4) | (0,4), (6,4), (1,-1), (5,-1) |
| 2 | (-1, -6) | x=-1 | (0,-5) | (0,-5), (-2,-5), (1,-2), (-3,-2) |
| 3 | (0, -3) | x=0 | (0,-3) | (1,-2), (-1,-2), (2,1), (-2,1) |
| 4 | (-3, -8) | x=-3 | (0,1) | (0,1), (-6,1), (-1,-4), (-5,-4) |

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## 📌 How to Actually Graph on Paper:

1. Draw your coordinate plane (already provided).
2. Mark the vertex — this is the lowest point (since a=1>0).
3. Draw the axis of symmetry as a dashed vertical line.
4. Plot the y-intercept.
5. Use symmetry to find the mirror point across the axis.
6. Plot 1–2 more points on each side to make sure the curve is accurate.
7. Connect the points smoothly with a curved line — don’t use straight lines!

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You now have all the information needed to accurately graph each of the four quadratic functions on the provided grids.

Let me know if you’d like printable graph paper or digital graphing help!
Parent Tip: Review the logic above to help your child master the concept of graphing quadratic functions worksheet.
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