Grade 12 Graphing Sine and Cosine Functions Worksheets 2024 - Free Printable
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Step-by-step solution for: Grade 12 Graphing Sine and Cosine Functions Worksheets 2024
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Show Answer Key & Explanations
Step-by-step solution for: Grade 12 Graphing Sine and Cosine Functions Worksheets 2024
Absolutely! Let’s solve each of the four problems step by step. For each, we’ll find the amplitude and period, then describe how to graph the function using radians.
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## 🔷 General Form Reminder:
For functions of the form:
- `y = A·cos(Bθ)` or `y = A·sin(Bθ)`
→ Amplitude = |A|
→ Period = `2π / |B|`
---
## ✔ Problem 1: `y = 3 cos(2θ)`
A = 3 → Amplitude = |3| = 3
B = 2 → Period = 2π / 2 = π
- The cosine wave starts at its maximum (since no phase shift).
- Key points over one period (from θ = 0 to θ = π):
- At θ = 0 → y = 3·cos(0) = 3
- At θ = π/4 → y = 3·cos(π/2) = 0
- At θ = π/2 → y = 3·cos(π) = -3
- At θ = 3π/4 → y = 3·cos(3π/2) = 0
- At θ = π → y = 3·cos(2π) = 3
So, plot these 5 key points and connect them smoothly in a cosine wave shape.
✔ Answer for #1:
Amplitude = 3, Period = π
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## ✔ Problem 2: `y = cos(3θ)`
A = 1 → Amplitude = |1| = 1
B = 3 → Period = 2π / 3
- Starts at max (cosine), so at θ=0, y=1.
- One full cycle from θ = 0 to θ = 2π/3.
- Divide the period into 4 equal parts for key points:
- θ = 0 → y = cos(0) = 1
- θ = (2π/3)/4 = π/6 → y = cos(π/2) = 0
- θ = 2π/6 = π/3 → y = cos(π) = -1
- θ = π/2 → y = cos(3π/2) = 0
- θ = 2π/3 → y = cos(2π) = 1
Plot these points and draw the wave.
✔ Answer for #2:
Amplitude = 1, Period = 2π/3
---
## ✔ Problem 3: `y = 2 sin(θ/2)`
A = 2 → Amplitude = |2| = 2
B = 1/2 → Period = 2π / (1/2) = 4π
- Sine wave starts at origin (0,0).
- One full cycle from θ = 0 to θ = 4π.
- Key points (divide period into 4 parts → each part = π):
- θ = 0 → y = 2·sin(0) = 0
- θ = π → y = 2·sin(π/2) = 2
- θ = 2π → y = 2·sin(π) = 0
- θ = 3π → y = 2·sin(3π/2) = -2
- θ = 4π → y = 2·sin(2π) = 0
Plot these and connect with a smooth sine curve.
✔ Answer for #3:
Amplitude = 2, Period = 4π
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## ✔ Problem 4: `y = (1/2)·cos(2θ)`
A = 1/2 → Amplitude = |1/2| = 0.5
B = 2 → Period = 2π / 2 = π
- Cosine wave, starts at max: θ=0 → y=0.5
- One period from 0 to π.
- Key points (each quarter-period = π/4):
- θ = 0 → y = 0.5·cos(0) = 0.5
- θ = π/4 → y = 0.5·cos(π/2) = 0
- θ = π/2 → y = 0.5·cos(π) = -0.5
- θ = 3π/4 → y = 0.5·cos(3π/2) = 0
- θ = π → y = 0.5·cos(2π) = 0.5
Plot and connect.
✔ Answer for #4:
Amplitude = 0.5, Period = π
---
## 📊 Summary Table:
| Problem | Function | Amplitude | Period |
|---------|-------------------|-----------|--------|
| 1 | `y = 3 cos(2θ)` | 3 | π |
| 2 | `y = cos(3θ)` | 1 | 2π/3 |
| 3 | `y = 2 sin(θ/2)` | 2 | 4π |
| 4 | `y = (1/2) cos(2θ)` | 0.5 | π |
---
## 🖍️ How to Graph Each (Quick Tips):
- Use the x-axis labeled in radians as given on each grid.
- Mark the amplitude on the y-axis (positive and negative).
- Mark the period on the x-axis — that’s how long one full wave takes.
- Plot 5 key points per cycle: start, 1/4, 1/2, 3/4, end.
- Connect with smooth curves (no sharp corners!).
---
Let me know if you’d like me to sketch the graphs for you or provide printable answer keys! 😊
---
## 🔷 General Form Reminder:
For functions of the form:
- `y = A·cos(Bθ)` or `y = A·sin(Bθ)`
→ Amplitude = |A|
→ Period = `2π / |B|`
---
## ✔ Problem 1: `y = 3 cos(2θ)`
➤ Amplitude:
A = 3 → Amplitude = |3| = 3
➤ Period:
B = 2 → Period = 2π / 2 = π
➤ Graphing Instructions:
- The cosine wave starts at its maximum (since no phase shift).
- Key points over one period (from θ = 0 to θ = π):
- At θ = 0 → y = 3·cos(0) = 3
- At θ = π/4 → y = 3·cos(π/2) = 0
- At θ = π/2 → y = 3·cos(π) = -3
- At θ = 3π/4 → y = 3·cos(3π/2) = 0
- At θ = π → y = 3·cos(2π) = 3
So, plot these 5 key points and connect them smoothly in a cosine wave shape.
✔ Answer for #1:
Amplitude = 3, Period = π
---
## ✔ Problem 2: `y = cos(3θ)`
➤ Amplitude:
A = 1 → Amplitude = |1| = 1
➤ Period:
B = 3 → Period = 2π / 3
➤ Graphing Instructions:
- Starts at max (cosine), so at θ=0, y=1.
- One full cycle from θ = 0 to θ = 2π/3.
- Divide the period into 4 equal parts for key points:
- θ = 0 → y = cos(0) = 1
- θ = (2π/3)/4 = π/6 → y = cos(π/2) = 0
- θ = 2π/6 = π/3 → y = cos(π) = -1
- θ = π/2 → y = cos(3π/2) = 0
- θ = 2π/3 → y = cos(2π) = 1
Plot these points and draw the wave.
✔ Answer for #2:
Amplitude = 1, Period = 2π/3
---
## ✔ Problem 3: `y = 2 sin(θ/2)`
➤ Amplitude:
A = 2 → Amplitude = |2| = 2
➤ Period:
B = 1/2 → Period = 2π / (1/2) = 4π
➤ Graphing Instructions:
- Sine wave starts at origin (0,0).
- One full cycle from θ = 0 to θ = 4π.
- Key points (divide period into 4 parts → each part = π):
- θ = 0 → y = 2·sin(0) = 0
- θ = π → y = 2·sin(π/2) = 2
- θ = 2π → y = 2·sin(π) = 0
- θ = 3π → y = 2·sin(3π/2) = -2
- θ = 4π → y = 2·sin(2π) = 0
Plot these and connect with a smooth sine curve.
✔ Answer for #3:
Amplitude = 2, Period = 4π
---
## ✔ Problem 4: `y = (1/2)·cos(2θ)`
➤ Amplitude:
A = 1/2 → Amplitude = |1/2| = 0.5
➤ Period:
B = 2 → Period = 2π / 2 = π
➤ Graphing Instructions:
- Cosine wave, starts at max: θ=0 → y=0.5
- One period from 0 to π.
- Key points (each quarter-period = π/4):
- θ = 0 → y = 0.5·cos(0) = 0.5
- θ = π/4 → y = 0.5·cos(π/2) = 0
- θ = π/2 → y = 0.5·cos(π) = -0.5
- θ = 3π/4 → y = 0.5·cos(3π/2) = 0
- θ = π → y = 0.5·cos(2π) = 0.5
Plot and connect.
✔ Answer for #4:
Amplitude = 0.5, Period = π
---
## 📊 Summary Table:
| Problem | Function | Amplitude | Period |
|---------|-------------------|-----------|--------|
| 1 | `y = 3 cos(2θ)` | 3 | π |
| 2 | `y = cos(3θ)` | 1 | 2π/3 |
| 3 | `y = 2 sin(θ/2)` | 2 | 4π |
| 4 | `y = (1/2) cos(2θ)` | 0.5 | π |
---
## 🖍️ How to Graph Each (Quick Tips):
- Use the x-axis labeled in radians as given on each grid.
- Mark the amplitude on the y-axis (positive and negative).
- Mark the period on the x-axis — that’s how long one full wave takes.
- Plot 5 key points per cycle: start, 1/4, 1/2, 3/4, end.
- Connect with smooth curves (no sharp corners!).
---
Let me know if you’d like me to sketch the graphs for you or provide printable answer keys! 😊
Parent Tip: Review the logic above to help your child master the concept of graphing sine and cosine worksheet.