Students color blocks to represent hundreds, tens, and ones in a math exercise.

Let’s work through each problem step by step.

We are counting blocks that represent hundreds, tens, and ones.

Each big square = 100 (hundreds)
Each column of 10 small squares = 10 (tens)
Each single small square = 1 (ones)

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Problem 1:
- 4 hundreds → 4 big squares
- 2 tens → 2 columns of 10
- 6 ones → 6 single squares

So we add:
400 + 20 + 6 = 426

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Problem 2:
- 3 hundreds → 3 big squares
- 5 tens → 5 columns of 10
- 3 ones → 3 single squares

Add:
300 + 50 + 3 = 353

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Problem 3:
- 2 tens → 2 columns of 10
- 3 hundreds → 3 big squares
- 6 ones → 6 single squares

Add:
300 + 20 + 6 = 326

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Problem 4:
- 6 ones → 6 single squares
- 2 tens → 2 columns of 10
- 3 hundreds → 3 big squares

Add:
300 + 20 + 6 = 326

Wait — let’s double-check Problem 4. The order is listed as “6 ones, 2 tens, 3 hundreds” — but when adding, order doesn’t matter. Still:

3 hundreds = 300
2 tens = 20
6 ones = 6
Total = 300 + 20 + 6 = 326

But hold on — in Problem 3, it was also 3 hundreds, 2 tens, 6 ones → same total? Let me check the image again mentally.

Actually, looking back at the original problem descriptions:

Problem 3 says:
“2 tens, 3 hundreds, 6 ones” → still 300 + 20 + 6 = 326

Problem 4 says:
“6 ones, 2 tens, 3 hundreds” → same numbers → 326

That seems correct — just different order of listing.

But wait — maybe I misread? Let me recheck all:

Problem 1: 4 hundreds, 2 tens, 6 ones → 426 ✔
Problem 2: 3 hundreds, 5 tens, 3 ones → 353 ✔
Problem 3: 2 tens, 3 hundreds, 6 ones → 326 ✔
Problem 4: 6 ones, 2 tens, 3 hundreds → 326 ✔

Yes, Problems 3 and 4 have the same values, just listed in different order. That’s fine — place value doesn’t care about the order you list them; you still add them up.

Final answers:

1. 426
2. 353
3. 326
4. 326

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Final Answer:
1. 426
2. 353
3. 326
4. 326