Create the Kids - Genetics Activity Worksheet (6-8 Grade) - Free Printable

Let’s solve this genetics problem step by step using the Punnett Square provided.

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🧬 Step 1: Understand the Genotypes

We are told:

- Mom’s genotype: `FF bb hh`
→ This means she is homozygous dominant for freckles (F), homozygous recessive for blue eyes (b), and homozygous recessive for straight hair (h).

- Dad’s genotype: `ff BB HH`
→ Homozygous recessive for no freckles (f), homozygous dominant for brown eyes (B), and homozygous dominant for curly hair (H).

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🧬 Step 2: Determine Gametes

Each parent can only produce one type of gamete, because they are homozygous for all traits.

- Mom’s gamete: Since she is `FF bb hh`, she can only pass on `F b h` → written as Fbh

- Dad’s gamete: Since he is `ff BB HH`, he can only pass on `f B H` → written as fBH

The Punnett Square shows:

```
| Fbh | Fbh
--------|---------|---------
fBH | ? | ?
fBH | ? | ?
```

So, every box in the Punnett Square will be the combination of Fbh + fBH.

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🧬 Step 3: Fill in the Punnett Square

Each offspring gets one allele from each parent for each gene:

- Freckles: Mom gives `F`, Dad gives `f` → Offspring = `Ff`
- Eye color: Mom gives `b`, Dad gives `B` → Offspring = `Bb`
- Hair type: Mom gives `h`, Dad gives `H` → Offspring = `Hh`

✔ So, every child will have the genotype: Ff Bb Hh

Since both parents are homozygous, all 4 kids will be genetically identical!

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✔ Answer to “What are the kid’s genotypes?”

> All four kids have the genotype: Ff Bb Hh

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🧬 Step 4: Determine Phenotypes

Remember:
- Dominant traits are expressed if at least one dominant allele is present.
- Recessive traits are expressed only if both alleles are recessive.

From the key:

- Freckled Face (F) is dominant → `Ff` = Freckled face
- Brown Eyes (B) is dominant → `Bb` = Brown eyes
- Curly Hair (H) is dominant → `Hh` = Curly hair

✔ So, phenotype of all kids:
> Freckled face, Brown eyes, Curly hair

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✔ Final Answers:

#### ➤ What are the kid’s genotypes?
> All four kids have the genotype: Ff Bb Hh

#### ➤ What are the kid’s phenotypes?
> All four kids have the phenotype: Freckled face, Brown eyes, Curly hair

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💡 Extra Note:

Even though the worksheet says “4 possible kids,” in this specific case, because both parents are homozygous for all traits, there is only one possible genotype and phenotype for all offspring. The Punnett Square has 4 boxes, but all are identical — so it’s not 4 *different* kids, just 4 *identical* kids genetically.

This is a great example of how homozygous parents limit genetic variation in offspring!

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✔ Completed Worksheet Answers:

> Kid’s genotypes: Ff Bb Hh (all four kids)
> Kid’s phenotypes: Freckled face, Brown eyes, Curly hair (all four kids)

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Let me know if you’d like to explore what would happen if the parents were heterozygous! 😊