Converting Hexadecimal to Decimal Color Worksheet by Aric Thomas - Free Printable

To solve this problem, we need to convert numbers from Hexadecimal (base 16) to Decimal (base 10).

How Hexadecimal Works

In our normal counting (Decimal), we use digits 0-9. In Hexadecimal, we use digits 0-9 and letters A-F to represent values 10-15.

Here is the value of each letter:
* A = 10
* B = 11
* C = 12
* D = 13
* E = 14
* F = 15

How to Convert

Hexadecimal is a "place value" system, just like decimal, but based on powers of 16 instead of 10.
* The rightmost digit is the 1s place ($16^0$).
* The next digit to the left is the 16s place ($16^1$).
* The next digit is the 256s place ($16^2$).

Formula:
$(\text{First Digit} \times 16) + (\text{Second Digit} \times 1)$

If there is a third digit:
$(\text{First Digit} \times 256) + (\text{Second Digit} \times 16) + (\text{Third Digit} \times 1)$

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Step-by-Step Solutions

#### Left Column Matches
1. 3: This is a single digit. It stays the same.
* Answer: 3
2. 10: The '1' is in the 16s place, '0' is in the 1s place.
* $(1 \times 16) + (0 \times 1) = 16 + 0 = 16$
* Answer: 16
3. C: C represents 12.
* Answer: 12
4. 1F: '1' is in the 16s place, 'F' (15) is in the 1s place.
* $(1 \times 16) + (15 \times 1) = 16 + 15 = 31$
* Answer: 31
5. 20: '2' is in the 16s place, '0' is in the 1s place.
* $(2 \times 16) + (0 \times 1) = 32 + 0 = 32$
* Answer: 32
6. 2E: '2' is in the 16s place, 'E' (14) is in the 1s place.
* $(2 \times 16) + (14 \times 1) = 32 + 14 = 46$
* Answer: 46
7. 59: '5' is in the 16s place, '9' is in the 1s place.
* $(5 \times 16) + (9 \times 1) = 80 + 9 = 89$
* Answer: 89
8. 2A: '2' is in the 16s place, 'A' (10) is in the 1s place.
* $(2 \times 16) + (10 \times 1) = 32 + 10 = 42$
* Answer: 42
9. 30: '3' is in the 16s place, '0' is in the 1s place.
* $(3 \times 16) + (0 \times 1) = 48 + 0 = 48$
* Answer: 48
10. 5A: '5' is in the 16s place, 'A' (10) is in the 1s place.
* $(5 \times 16) + (10 \times 1) = 80 + 10 = 90$
* Answer: 90
11. 4B: '4' is in the 16s place, 'B' (11) is in the 1s place.
* $(4 \times 16) + (11 \times 1) = 64 + 11 = 75$
* Answer: 75
12. 29: '2' is in the 16s place, '9' is in the 1s place.
* $(2 \times 16) + (9 \times 1) = 32 + 9 = 41$
* Answer: 41

#### Middle Column Matches
13. 19: '1' is in the 16s place, '9' is in the 1s place.
* $(1 \times 16) + (9 \times 1) = 16 + 9 = 25$
* Answer: 25
14. 3F: '3' is in the 16s place, 'F' (15) is in the 1s place.
* $(3 \times 16) + (15 \times 1) = 48 + 15 = 63$
* Answer: 63
15. 55: '5' is in the 16s place, '5' is in the 1s place.
* $(5 \times 16) + (5 \times 1) = 80 + 5 = 85$
* Answer: 85
16. 4F: '4' is in the 16s place, 'F' (15) is in the 1s place.
* $(4 \times 16) + (15 \times 1) = 64 + 15 = 79$
* Answer: 79
17. 70: '7' is in the 16s place, '0' is in the 1s place.
* $(7 \times 16) + (0 \times 1) = 112 + 0 = 112$
* Answer: 112
18. A0: 'A' (10) is in the 16s place, '0' is in the 1s place.
* $(10 \times 16) + (0 \times 1) = 160 + 0 = 160$
* Answer: 160

#### Right Column Matches
19. 7D: '7' is in the 16s place, 'D' (13) is in the 1s place.
* $(7 \times 16) + (13 \times 1) = 112 + 13 = 125$
* Answer: 125
20. A3: 'A' (10) is in the 16s place, '3' is in the 1s place.
* $(10 \times 16) + (3 \times 1) = 160 + 3 = 163$
* Answer: 163
21. AC: 'A' (10) is in the 16s place, 'C' (12) is in the 1s place.
* $(10 \times 16) + (12 \times 1) = 160 + 12 = 172$
* Answer: 172
22. BA: 'B' (11) is in the 16s place, 'A' (10) is in the 1s place.
* $(11 \times 16) + (10 \times 1) = 176 + 10 = 186$
* Answer: 186
23. F3: 'F' (15) is in the 16s place, '3' is in the 1s place.
* $(15 \times 16) + (3 \times 1) = 240 + 3 = 243$
* Answer: 243
24. CF: 'C' (12) is in the 16s place, 'F' (15) is in the 1s place.
* $(12 \times 16) + (15 \times 1) = 192 + 15 = 207$
* Answer: 207

Final Answer:
Left Column:
3 → 3
10 → 16
C → 12
1F → 31
20 → 32
2E → 46
59 → 89
2A → 42
30 → 48
5A → 90
4B → 75
29 → 41

Middle Column:
19 → 25
3F → 63
55 → 85
4F → 79
70 → 112
A0 → 160

Right Column:
7D → 125
A3 → 163
AC → 172
BA → 186
F3 → 243
CF → 207