a) I-1: Aa, I-2: Aa, II-1: aa, II-2: A_, II-3: aa, II-4: A_, II-5: A_, II-6: A_, II-7: A_, II-8: A_, III-1: aa, III-2: A_, III-3: A_, III-4: A_, III-5: aa, III-6: A_
b) Rabbit II-2 is a carrier (Aa) because it has an affected offspring (III-1, aa). Rabbit II-4 is also a carrier (Aa) because it has an affected offspring (III-5, aa).
c) You cannot determine which allele is the actual genotype for rabbits II-2 and II-4 because they are both heterozygous (Aa) and phenotypically normal; without further testing or more offspring data, you cannot distinguish between the two alleles in their genotype.
d) If rabbit III-5 is albino (aa), her parents (II-4 and II-5) must each carry at least one recessive allele. Since they are both phenotypically normal, they must both be carriers (Aa). The probability that both parents are carriers is 100% given that they produced an albino offspring.
Parent Tip: Review the logic above to help your child master the concept of human pedigree worksheets.
