Inequalities Worksheet for solving algebraic inequalities.
Educational worksheet: Pre-Algebra Worksheets | Inequalities Worksheets. Download and print for classroom or home learning activities.
JPG
742×1050
84.3 KB
Free · Personal Use
Quality Assured by Worksheets Library Team
Reviewed for educational accuracy and age-appropriateness
ID: #184772
⭐
Show Answer Key & Explanations
Step-by-step solution for: Pre-Algebra Worksheets | Inequalities Worksheets
▼
Show Answer Key & Explanations
Step-by-step solution for: Pre-Algebra Worksheets | Inequalities Worksheets
Let’s solve each inequality step by step. I’ll go one at a time, showing all the work so you can follow along easily.
---
Problem 1: 6 - b < 8 - 4b
Step 1: Get all the variable terms on one side. Add 4b to both sides:
6 - b + 4b < 8 - 4b + 4b
→ 6 + 3b < 8
Step 2: Subtract 6 from both sides:
6 + 3b - 6 < 8 - 6
→ 3b < 2
Step 3: Divide both sides by 3:
b < 2/3
✔ Final answer for #1: b < 2/3
---
Problem 2: 4(x + 1/2) - 2(x + 3/2) ≤ 5
Step 1: Distribute the 4 and the -2:
4*x + 4*(1/2) = 4x + 2
-2*x -2*(3/2) = -2x - 3
So now:
4x + 2 - 2x - 3 ≤ 5
Step 2: Combine like terms:
(4x - 2x) + (2 - 3) ≤ 5
→ 2x - 1 ≤ 5
Step 3: Add 1 to both sides:
2x ≤ 6
Step 4: Divide by 2:
x ≤ 3
✔ Final answer for #2: x ≤ 3
---
Problem 3: -1 < x + 2 < 5
This is a compound inequality. We solve it by subtracting 2 from all three parts.
-1 - 2 < x + 2 - 2 < 5 - 2
→ -3 < x < 3
✔ Final answer for #3: -3 < x < 3
---
Problem 4: 3(y + 5) ≤ 2(y + 1)
Step 1: Distribute:
3y + 15 ≤ 2y + 2
Step 2: Subtract 2y from both sides:
y + 15 ≤ 2
Step 3: Subtract 15 from both sides:
y ≤ -13
✔ Final answer for #4: y ≤ -13
---
Problem 5: -5(u - 19) ≤ -6 + 2u
Step 1: Distribute the -5:
-5u + 95 ≤ -6 + 2u
Step 2: Subtract 2u from both sides:
-7u + 95 ≤ -6
Step 3: Subtract 95 from both sides:
-7u ≤ -101
Step 4: Divide by -7 → Remember! When dividing by a negative, flip the inequality sign!
u ≥ 101/7
✔ Final answer for #5: u ≥ 101/7
---
Problem 6: 3 - 2(n - 4) > -1
Step 1: Distribute the -2:
3 - 2n + 8 > -1
→ 11 - 2n > -1
Step 2: Subtract 11 from both sides:
-2n > -12
Step 3: Divide by -2 → Flip the inequality!
n < 6
✔ Final answer for #6: n < 6
---
Problem 7: 4r + 3 > 2r + 11
Step 1: Subtract 2r from both sides:
2r + 3 > 11
Step 2: Subtract 3:
2r > 8
Step 3: Divide by 2:
r > 4
✔ Final answer for #7: r > 4
---
Problem 8: (x - 5)(x - 2) ≤ 0
This is a quadratic inequality. First, find the roots: x = 5 and x = 2.
The expression changes sign at these points. Test intervals:
- For x < 2 (say x=0): (0-5)(0-2) = (-5)(-2) = 10 → positive → not ≤ 0
- For 2 < x < 5 (say x=3): (3-5)(3-2) = (-2)(1) = -2 → negative → satisfies ≤ 0
- For x > 5 (say x=6): (6-5)(6-2) = (1)(4) = 4 → positive → not ≤ 0
Also, since it’s ≤ 0, include the endpoints where it equals zero.
So solution: 2 ≤ x ≤ 5
✔ Final answer for #8: 2 ≤ x ≤ 5
---
Problem 9: x² + 7x + 10 < 10
Step 1: Subtract 10 from both sides:
x² + 7x < 0
Step 2: Factor:
x(x + 7) < 0
Roots are x = 0 and x = -7.
Test intervals:
- x < -7 (say x=-8): (-8)(-1) = 8 → positive → no
- -7 < x < 0 (say x=-1): (-1)(6) = -6 → negative → yes
- x > 0 (say x=1): (1)(8) = 8 → positive → no
Since it’s < 0, do NOT include endpoints.
✔ Final answer for #9: -7 < x < 0
---
Problem 10: (x² + 6)/2 ≥ 53
Step 1: Multiply both sides by 2:
x² + 6 ≥ 106
Step 2: Subtract 6:
x² ≥ 100
Step 3: Take square root → remember, this gives two cases:
x ≥ 10 OR x ≤ -10
✔ Final answer for #10: x ≤ -10 or x ≥ 10
---
Final Answers:
1. b < 2/3
2. x ≤ 3
3. -3 < x < 3
4. y ≤ -13
5. u ≥ 101/7
6. n < 6
7. r > 4
8. 2 ≤ x ≤ 5
9. -7 < x < 0
10. x ≤ -10 or x ≥ 10
---
Problem 1: 6 - b < 8 - 4b
Step 1: Get all the variable terms on one side. Add 4b to both sides:
6 - b + 4b < 8 - 4b + 4b
→ 6 + 3b < 8
Step 2: Subtract 6 from both sides:
6 + 3b - 6 < 8 - 6
→ 3b < 2
Step 3: Divide both sides by 3:
b < 2/3
✔ Final answer for #1: b < 2/3
---
Problem 2: 4(x + 1/2) - 2(x + 3/2) ≤ 5
Step 1: Distribute the 4 and the -2:
4*x + 4*(1/2) = 4x + 2
-2*x -2*(3/2) = -2x - 3
So now:
4x + 2 - 2x - 3 ≤ 5
Step 2: Combine like terms:
(4x - 2x) + (2 - 3) ≤ 5
→ 2x - 1 ≤ 5
Step 3: Add 1 to both sides:
2x ≤ 6
Step 4: Divide by 2:
x ≤ 3
✔ Final answer for #2: x ≤ 3
---
Problem 3: -1 < x + 2 < 5
This is a compound inequality. We solve it by subtracting 2 from all three parts.
-1 - 2 < x + 2 - 2 < 5 - 2
→ -3 < x < 3
✔ Final answer for #3: -3 < x < 3
---
Problem 4: 3(y + 5) ≤ 2(y + 1)
Step 1: Distribute:
3y + 15 ≤ 2y + 2
Step 2: Subtract 2y from both sides:
y + 15 ≤ 2
Step 3: Subtract 15 from both sides:
y ≤ -13
✔ Final answer for #4: y ≤ -13
---
Problem 5: -5(u - 19) ≤ -6 + 2u
Step 1: Distribute the -5:
-5u + 95 ≤ -6 + 2u
Step 2: Subtract 2u from both sides:
-7u + 95 ≤ -6
Step 3: Subtract 95 from both sides:
-7u ≤ -101
Step 4: Divide by -7 → Remember! When dividing by a negative, flip the inequality sign!
u ≥ 101/7
✔ Final answer for #5: u ≥ 101/7
---
Problem 6: 3 - 2(n - 4) > -1
Step 1: Distribute the -2:
3 - 2n + 8 > -1
→ 11 - 2n > -1
Step 2: Subtract 11 from both sides:
-2n > -12
Step 3: Divide by -2 → Flip the inequality!
n < 6
✔ Final answer for #6: n < 6
---
Problem 7: 4r + 3 > 2r + 11
Step 1: Subtract 2r from both sides:
2r + 3 > 11
Step 2: Subtract 3:
2r > 8
Step 3: Divide by 2:
r > 4
✔ Final answer for #7: r > 4
---
Problem 8: (x - 5)(x - 2) ≤ 0
This is a quadratic inequality. First, find the roots: x = 5 and x = 2.
The expression changes sign at these points. Test intervals:
- For x < 2 (say x=0): (0-5)(0-2) = (-5)(-2) = 10 → positive → not ≤ 0
- For 2 < x < 5 (say x=3): (3-5)(3-2) = (-2)(1) = -2 → negative → satisfies ≤ 0
- For x > 5 (say x=6): (6-5)(6-2) = (1)(4) = 4 → positive → not ≤ 0
Also, since it’s ≤ 0, include the endpoints where it equals zero.
So solution: 2 ≤ x ≤ 5
✔ Final answer for #8: 2 ≤ x ≤ 5
---
Problem 9: x² + 7x + 10 < 10
Step 1: Subtract 10 from both sides:
x² + 7x < 0
Step 2: Factor:
x(x + 7) < 0
Roots are x = 0 and x = -7.
Test intervals:
- x < -7 (say x=-8): (-8)(-1) = 8 → positive → no
- -7 < x < 0 (say x=-1): (-1)(6) = -6 → negative → yes
- x > 0 (say x=1): (1)(8) = 8 → positive → no
Since it’s < 0, do NOT include endpoints.
✔ Final answer for #9: -7 < x < 0
---
Problem 10: (x² + 6)/2 ≥ 53
Step 1: Multiply both sides by 2:
x² + 6 ≥ 106
Step 2: Subtract 6:
x² ≥ 100
Step 3: Take square root → remember, this gives two cases:
x ≥ 10 OR x ≤ -10
✔ Final answer for #10: x ≤ -10 or x ≥ 10
---
Final Answers:
1. b < 2/3
2. x ≤ 3
3. -3 < x < 3
4. y ≤ -13
5. u ≥ 101/7
6. n < 6
7. r > 4
8. 2 ≤ x ≤ 5
9. -7 < x < 0
10. x ≤ -10 or x ≥ 10
Parent Tip: Review the logic above to help your child master the concept of inequality worksheets.