Integer Worksheet-Fill in the Sign (C) - Mr. R.s World of Math - Free Printable

Let’s solve each problem one by one. We need to place +, -, ×, or ÷ between the four digits on the left so that the equation equals the number on the right. Remember: follow order of operations (multiplication and division before addition and subtraction).

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A: 8 5 2 6 = 36

Try:
8 × 5 = 40 → too big?
What if we do: 8 + 5 × 2 + 6?
→ 5 × 2 = 10 → 8 + 10 + 6 = 24 ✘
Try: 8 × 5 - 2 - 6 = 40 - 2 - 6 = 32 ✘
Try: 8 + 5 + 2 × 6 = 8 + 5 + 12 = 25 ✘
Try: 8 × 2 + 5 + 6 = 16 + 5 + 6 = 27 ✘
Wait — what about: 8 × 5 - 2 - 6? Still 32.
Hmm… try: 8 + 5 × 6 - 2? But digits are 8,5,2,6 — must keep order!
So only between them: 8 _ 5 _ 2 _ 6

Try: 8 × 5 - 2 - 6 = 40 - 8 = 32 ✘
Try: 8 + 5 × 2 + 6 = 8+10+6=24 ✘
Try: 8 × 2 + 5 + 6 = 16+11=27 ✘
Wait — maybe: 8 + 5 + 2 × 6 = 8+5+12=25 ✘
What if: (8 + 5) × 2 + 6? But no parentheses allowed — just operators between.

Hold on — let’s try: 8 × 5 - 2 - 6 = 32 — close but not 36.

Wait — what about: 8 + 5 × 6 - 2? Again, wrong digit order.

Digits must stay in order: 8, then 5, then 2, then 6.

Try: 8 × 2 + 5 + 6 — again, skips order.

Actually — let me try: 8 + 5 + 2 × 6 = 8+5+12=25 ✘

Wait — here’s an idea: 8 × 5 - 2 - 6 is 32 — too low.

What if: 8 × 5 - (2 + 6)? No parentheses.

Maybe I’m missing something.

Try: 8 + 5 × 2 + 6 = 24 ✘

Wait — what if: 8 × 2 + 5 × 6? That would be 16 + 30 = 46 — too big, and also uses two multiplications — but allowed? Yes, as long as order of operations followed.

But digits are 8,5,2,6 — so 8 × 5 × 2 × 6 is way too big.

Wait — perhaps: 8 + 5 × 6 - 2 — but again, 6 comes after 2 — can’t rearrange.

I think I made a mistake — let’s list all possibilities systematically.

Possible combinations:

Option 1: 8 + 5 + 2 + 6 = 21 ✘
Option 2: 8 + 5 + 2 - 6 = 9 ✘
Option 3: 8 + 5 - 2 + 6 = 17 ✘
Option 4: 8 + 5 - 2 - 6 = 5 ✘
Option 5: 8 - 5 + 2 + 6 = 11 ✘
... this will take forever.

Better approach: since target is 36, which is fairly large, likely involves multiplication.

Try: 8 × 5 = 40 → then subtract 4 to get 36 → can we make 4 from 2 and 6? 6 - 2 = 4 → yes!

So: 8 × 5 - (6 - 2) — but again, no parentheses, and digits must be in order: 8,5,2,6 — so it would be 8 × 5 - 2 - 6 = 32, or 8 × 5 - 2 + 6 = 44.

Wait — what if: 8 × 5 - 2 - 6 = 32 — still not 36.

Another idea: 5 × 6 = 30, plus 8 - 2 = 6 → 36 — but again, order: 8,5,2,6 — so 8 _ 5 _ 2 _ 6.

What if: 8 + 5 × 6 - 2 — but 6 is last, 2 is third — so expression would be 8 + 5 × 2 × 6? Too big.

Wait — perhaps: 8 × 2 + 5 + 6 — but that’s using 8,2,5,6 — not in order.

I think I found it: 8 + 5 × 2 + 6 = 8 + 10 + 6 = 24 — no.

Wait — let's calculate 8 × 5 = 40, then 40 - 4 = 36, and 6 - 2 = 4, so if we could do 8 × 5 - (6 - 2), but we can't because 2 comes before 6.

Unless... what if we do: 8 × 5 - 6 + 2? That would be 40 - 6 + 2 = 36! And digits are 8,5,6,2 — but wait, the digits are given as 8,5,2,6 — so 2 comes before 6.

So 8 _ 5 _ 2 _ 6 — so after 5 is 2, then 6.

So 8 × 5 - 2 + 6 = 40 - 2 + 6 = 44 ✘
8 × 5 + 2 - 6 = 40 +2 -6 = 36 ✔ YES!

Check: 8 × 5 = 40, then +2 = 42, then -6 = 36. Perfect.

And order of operations: multiplication first, then left to right for + and -.

So: 8 × 5 + 2 - 6 = 40 + 2 - 6 = 36.

Yes! So A is: 8 × 5 + 2 - 6 = 36

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B: 5 7 8 3 = 58

Target 58.

Try: 5 × 7 = 35, 8 × 3 = 24, 35+24=59 — close.

5 × 8 = 40, 7 × 3 = 21, 40+21=61 — too big.

5 + 7 × 8 + 3 = 5 + 56 + 3 = 64 ✘

5 × 7 + 8 × 3 = 35 + 24 = 59 ✘

5 × 7 + 8 + 3 = 35+8+3=46 ✘

5 + 7 + 8 × 3 = 5+7+24=36 ✘

What if: 5 × 8 + 7 + 3 = 40+10=50 ✘

Wait — 5 × 7 = 35, need 23 more — 8×3=24, too much.

Perhaps: 5 + 7 × 8 - 3 = 5 + 56 - 3 = 58 ✔ YES!

Check: 7 × 8 = 56, then 5 + 56 = 61, minus 3 = 58.

Order: 5 + 7 × 8 - 3 — multiplication first: 7×8=56, then 5+56=61, then 61-3=58.

Perfect. Digits in order: 5,7,8,3.

So B: 5 + 7 × 8 - 3 = 58

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C: 8 8 8 4 = 32

Target 32.

Try: 8 × 4 = 32, so maybe use that.

8 + 8 + 8 + 4 = 28 ✘

8 × 8 / 8 × 4 = ? 64 / 8 = 8, ×4=32 — but let's see: 8 × 8 ÷ 8 × 4

Order: left to right for same precedence: 8×8=64, ÷8=8, ×4=32 ✔

But is that allowed? Operators between: 8 _ 8 _ 8 _ 4

So: 8 × 8 ÷ 8 × 4 = 32

Yes.

Alternatively, simpler: 8 + 8 + 8 + 8? No, only three 8s and a 4.

8 × 4 = 32, and 8/8=1, but how to combine.

8 × (8 - 8/8)? No parentheses.

With order: 8 × 8 ÷ 8 × 4 = as above, works.

8 + 8 × 3? No 3.

Another way: 8 × 4 + 8 - 8 = 32 +0=32 — but digits are 8,8,8,4 — so 8 _ 8 _ 8 _ 4

If we do 8 × 4 + 8 - 8, but 4 is last, so it would be 8 _ 8 _ 8 _ 4 — so last operation with 4.

So 8 × 4 is not directly possible unless 4 is multiplied early.

In 8 × 8 ÷ 8 × 4, it works.

We can also do: 8 + 8 + 8 + 8? No.

Or: 8 × 8 - 8 × 4 = 64 - 32 = 32 — oh! That's better.

8 × 8 - 8 × 4

But order: multiplication first: 8×8=64, 8×4=32, then 64-32=32.

And digits: 8,8,8,4 — so positions: first 8, second 8, third 8, fourth 4.

So expression: 8 × 8 - 8 × 4

Is that valid? Between the digits: between first and second: ×, between second and third: -, between third and fourth: ×

So: 8 × 8 - 8 × 4

Yes, and by order of operations, both multiplications done before subtraction: 64 - 32 = 32.

Perfect.

So C: 8 × 8 - 8 × 4 = 32

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D: 5 7 6 3 = 10

Target 10.

Try: 5 + 7 - 6 + 3 = 9 ✘

5 + 7 - 6 - 3 = 3 ✘

5 × 2 = 10, but no 2.

7 + 3 = 10, so maybe 5 and 6 cancel.

5 - 5 =0, but no.

(5 + 7 + 6)/ something — no parentheses.

Try: 5 + 7 - 6 ÷ 3? 6÷3=2, 5+7-2=10 ✔

Check: 6 ÷ 3 = 2, then 5 + 7 = 12, minus 2 = 10.

Order: division first, then left to right: 5 + 7 - (6÷3) = 12 - 2 = 10.

Digits: 5,7,6,3 — so 5 + 7 - 6 ÷ 3

Yes.

So D: 5 + 7 - 6 ÷ 3 = 10

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E: 6 6 7 8 = 56

Target 56.

56 is 7×8, so probably involve that.

6 + 6 + 7 × 8 = 6+6+56=68 ✘

6 × 6 + 7 + 8 = 36+15=51 ✘

6 × 7 + 6 + 8 = 42+14=56 ✔

Check: 6 × 7 = 42, then +6 = 48, +8=56.

Digits: 6,6,7,8 — so first 6, second 6, third 7, fourth 8.

Expression: 6 × 7 + 6 + 8 — but that would require skipping the second 6 or reordering.

No: the sequence is 6 _ 6 _ 7 _ 8

So if we do 6 × 6 + 7 + 8 = 36+15=51 ✘

6 + 6 × 7 + 8 = 6 + 42 + 8 = 56 ✔

Yes! Multiplication first: 6×7=42, then 6+42=48, +8=56.

Digits in order: 6,6,7,8 — so 6 + 6 × 7 + 8

Perfect.

So E: 6 + 6 × 7 + 8 = 56

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F: 4 4 4 9 = 6

Target 6.

Small number, so probably division or subtraction.

4 + 4 + 4 - 9 = 12 - 9 = 3 ✘

4 × 4 - 4 - 9 = 16-4-9=3 ✘

(4 + 4 + 4)/2 = 6, but no 2.

9 - 4 - 4/4 = 9-4-1=4 ✘

4 + 4/4 - 9? 4+1-9=-4 ✘

What if: 4 × 4 - 4 - 6? No 6.

Another idea: 9 - 4 + 4/4 = 9-4+1=6 ✔

Check: 4/4=1, then 9-4=5, +1=6? Order: if expression is 9 - 4 + 4 ÷ 4

But digits are 4,4,4,9 — so must start with 4.

So 4 _ 4 _ 4 _ 9

Try: 4 + 4 - 4 + 9? 4+4-4+9=13 ✘

4 × 4 ÷ 4 - 9? 16÷4=4, -9=-5 ✘

(4 + 4 + 4) ÷ 2, no.

What if: 4 - 4 + 4 + 9? 0+4+9=13 ✘

Perhaps division: 4 ÷ 4 =1, then 4 + 1 =5, not 6.

9 - 3 =6, and 4 - 4/4 = 4-1=3, so 9 - (4 - 4/4) — but no parentheses, and order.

Try: 4 ÷ 4 + 4 + 9? 1+4+9=14 ✘

Another thought: 4 × 9 - 4 × 4? 36 - 16 = 20 ✘

Too big.

What if: (4 + 4) ÷ 4 × 3, no.

Let's think differently.

Suppose: 4 + 4 ÷ 4 - 9? 4+1-9=-4 ✘

4 - 4 ÷ 4 + 9? 4-1+9=12 ✘

Perhaps: 9 - 4 - 4/4 = 9-4-1=4 ✘

Wait — what if we do: 4 × 4 - 4 - 6, no.

Another idea: 6 = 24 ÷ 4, and 4×6=24, but no 6.

4 + 4 + 4 = 12, 12 ÷ 2 =6, but no 2.

9 - 3 =6, and 3 = 4 - 1, and 1=4/4.

So: 9 - (4 - 4/4) — but again, no parentheses.

In order: if we write 4 ÷ 4 =1, then 4 - 1 =3, then 9 - 3 =6, but the expression would be 9 - 4 + 4 ÷ 4? Let's calculate: 4÷4=1, then 9-4=5, 5+1=6 — oh! 9 - 4 + 4 ÷ 4 = 5 + 1 =6.

But digits are 4,4,4,9 — so we need to start with 4.

So perhaps: 4 ÷ 4 + 9 - 4? That would be 1 + 9 - 4 = 6 ✔

Check: 4 ÷ 4 =1, then 1 + 9 =10, then 10 - 4 =6.

Digits: first 4, second 4, third 9, fourth 4? But the digits are 4,4,4,9 — so third is 4, fourth is 9.

In 4 ÷ 4 + 9 - 4, the digits used are 4,4,9,4 — which matches 4,4,4,9 if we consider the last 4 is the third 4, and 9 is fourth.

The sequence is position 1:4, pos2:4, pos3:4, pos4:9.

In expression 4 ÷ 4 + 9 - 4, we have: first 4, second 4, then 9, then 4 — but the third digit should be 4, not 9. Here we have 9 as third operand, but it should be the fourth digit.

Mistake.

The expression must use the digits in order: digit1 _ digit2 _ digit3 _ digit4

So for F: 4 _ 4 _ 4 _ 9

So options like 4 ÷ 4 + 4 - 9 = 1 + 4 - 9 = -4 ✘

4 + 4 ÷ 4 - 9 = 4 + 1 - 9 = -4 ✘

4 - 4 ÷ 4 + 9 = 4 - 1 + 9 = 12 ✘

4 × 4 ÷ 4 - 9 = 4 - 9 = -5 ✘

(4 + 4) ÷ 4 * 3, no.

Another idea: 9 - 4 - 4/4, but again, order.

Perhaps: 4 + 4 - 4 + 9? 4+4-4+9=13 ✘

Let's calculate 4 * 9 = 36, too big.

What if: (4 * 4 + 4) / 4 = 20/4=5, not 6.

4! / 4 = 24/4=6, but no factorial.

Perhaps I missed something.

Try: 4 ÷ 4 =1, then 4 + 1 =5, not 6.

9 - 3 =6, and 3 = 12/4, but no.

Another thought: 6 = 18 / 3, but no 3 or 18.

Let's list possible combinations.

Suppose we do division first.

4 ÷ 4 =1, then we have 1,4,9 to combine with operators.

But must be in sequence.

Expression: 4 op1 4 op2 4 op3 9

Try op1=+, op2=÷, op3=- : 4 + 4 ÷ 4 - 9 = 4 + 1 - 9 = -4 ✘

op1=-, op2=÷, op3=+ : 4 - 4 ÷ 4 + 9 = 4 - 1 + 9 = 12 ✘

op1=×, op2=÷, op3=- : 4 × 4 ÷ 4 - 9 = 4 - 9 = -5 ✘

op1=+, op2=+, op3=- : 4+4+4-9=3 ✘

op1=×, op2=-, op3=- : 4×4-4-9=16-4-9=3 ✘

op1=-, op2=+, op3=+ : 4-4+4+9=13 ✘

What if op2 is × or ÷.

Another idea: 4 + 4 + 4 = 12, 12 - 6 =6, but no 6.

9 - 3 =6, and 3 = 4 - 1, 1=4/4, so if we can do 9 - (4 - 4/4), but in linear order without parentheses, it might work if we arrange the operations properly.

Suppose: 4 ÷ 4 =1, then 4 - 1 =3, then 9 - 3 =6, but the expression would be 9 - 4 + 4 ÷ 4, which is 9 - 4 + 1 =6, but as before, the digits are not in order; we have 9 first, but it should be last.

Unless we do: 4 ÷ 4 + 9 - 4, but again, the third digit is 9, but it should be the third 4.

The digits are fixed: first 4, second 4, third 4, fourth 9.

So the expression is A op B op C op D with A=B=C=4, D=9.

So perhaps: 4 - 4 + 4 + 9? 0+4+9=13 ✘

4 * 4 - 4 - 6, no.

Let's try: (4 + 4) * 4 / 8, no.

Another thought: 6 = 24 / 4, and 4*6=24, but no 6.

4! =24, but not allowed.

Perhaps: 4 + 4/4 =5, then 5 +1=6, but no 1.

9/3=3, but no 3.

Let's calculate 4 * 9 = 36, 36 / 6 =6, but no 6.

36 / (4 + 2), no.

Perhaps: 4 * 9 - 4 * 7.5, no.

I recall that sometimes they use concatenation, but the instruction says place +,-,x,/ between digits, so probably not.

Another idea: 4 + 4 - 4/4 = 4+4-1=7 ✘

4 - 4/4 + 4 = 4-1+4=7 ✘

(4*4 + 8)/4 = 24/4=6, but no 8.

Let's think outside the box.

What if: 4 ÷ 4 =1, then 1 * 6 =6, but no 6.

9 - 3 =6, and 3 = 12/4, 12=4*3, circular.

Perhaps: 9 - 4 - 4/4 = 9-4-1=4 ✘

Wait — what if we do: 4 + 4 ÷ 4 = 5, then 5 +1=6, but no.

Let's try: 4 * 4 = 16, 16 - 10 =6, 10=9+1, 1=4/4, so 4*4 - (9 + 4/4) — but no parentheses, and order.

In sequence: 4 * 4 - 9 + 4 ÷ 4? Let's calculate: 4*4=16, 4÷4=1, then 16 - 9 =7, +1=8 ✘

4 * 4 - 9 - 4 ÷ 4 = 16 - 9 - 1 =6 ✔

Check: multiplication and division first: 4*4=16, 4÷4=1, then 16 - 9 =7, then 7 - 1 =6.

Digits: 4,4,9,4 — but the digits are 4,4,4,9 — so third digit is 4, fourth is 9.

In this expression: 4 * 4 - 9 - 4 ÷ 4, we have five numbers: 4,4,9,4,4 — too many.

Mistake.

The expression has three operators, so four numbers: digit1 op1 digit2 op2 digit3 op3 digit4

So for F: 4 op1 4 op2 4 op3 9

So only four numbers.

So 4 * 4 - 9 - 4 ÷ 4 is invalid because it has five numbers.

Must be exactly four numbers with three operators between them.

So back to square one.

Try: 4 + 4 + 4 - 9 = 3 ✘

4 * 4 - 4 - 9 = 16-4-9=3 ✘

4 - 4 + 4 * 9 = 0 + 36 = 36 ✘

4 * 9 - 4 * 4 = 36 - 16 = 20 ✘

(4 + 4) * 4 / 8, no.

Another idea: 6 = 30 / 5, but no.

Perhaps division: 4 / 4 =1, then 4 + 1 =5, not 6.

9 / 1.5 =6, but no 1.5.

Let's calculate 4 + 4/4 =5, then if we had another 1, but we have 9.

9 - 3 =6, and 3 = 4 - 1, 1=4/4, so if we can do 9 - (4 - 4/4), but in linear order, if we write 4/4 first, then 4 - that, then 9 - that.

But the expression would be 9 - 4 + 4 ÷ 4, which is 9 - 4 + 1 =6, but as said, the digits are not in order; we have 9 first, but it should be the fourth digit.

Unless the expression is written as 4 ÷ 4 + 9 - 4, but then the third digit is 9, but it should be the third 4.

The only way is if we use the digits in the given order: first 4, second 4, third 4, fourth 9.

So perhaps: 4 - 4/4 + 9? 4 - 1 + 9 = 12 ✘

4 + 4/4 - 9 = 4+1-9= -4 ✘

4 * 4 / 4 * 9 = 4*9=36 ✘

4 + 4 - 4/9? Not integer.

Perhaps: (4 * 4 + 8) / 4, no.

I recall that in some puzzles, they allow the operations to be placed, and order of operations applies.

Let me try: 4 ÷ 4 =1, then 1 * 6 =6, but no 6.

Another thought: 6 = 2*3, but no.

Let's search online or think differently.

Perhaps: 4 + 4 - 4 + 9? 4+4-4+9=13 ✘

4 * 9 / 6 =6, but no 6.

36 / 6 =6, and 4*9=36, so if we can divide by 6, but we have two 4's left.

4*9 / (4 + 2), no.

(4*9) / (4 + 2), but no 2.

4/4 =1, so 4*9 / (4/4 + 5), complicated.

Perhaps: 4 + 4/4 =5, then 5 +1=6, but no 1.

9/3=3, but no 3.

Let's calculate the difference.

Target 6, current sum 4+4+4+9=21, too big.

Product 4*4*4*9=576, too big.

Perhaps subtraction and division.

Try: 9 - 4 - 4/4 = 9-4-1=4 ✘

4 - 4/4 =3, then 9 - 3 =6, so if the expression is 9 - (4 - 4/4), but to write it without parentheses, and in order, it might be 4/4 - 4 + 9 or something.

Let's try: 4 ÷ 4 - 4 + 9 = 1 - 4 + 9 = 6 ✔

Calculate: 4 ÷ 4 =1, then 1 - 4 = -3, then -3 + 9 =6.

Yes! And digits: first 4, second 4, third 4, fourth 9 — so 4 ÷ 4 - 4 + 9

Order of operations: division first: 4÷4=1, then left to right: 1 - 4 = -3, then -3 + 9 =6.

Perfect.

So F: 4 ÷ 4 - 4 + 9 = 6

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G: 8 2 9 5 = 180

Target 180.

Large number, so likely multiplication.

8 × 2 = 16, 9 × 5 = 45, 16×45=720, too big.

8 × 9 = 72, 2 × 5 = 10, 72×10=720, still big.

8 × 5 = 40, 2 × 9 = 18, 40×18=720.

180 = 18 × 10, or 9 × 20, etc.

8 × 2 × 9 × 5 = 720, too big.

Perhaps (8 + 2) × (9 + 9), no.

8 × 2 = 16, 16 × 11.25 = 180, not integer.

9 × 20 = 180, and 20 = 8 + 2 + 10, no.

5 × 36 = 180, 36 = 8 × 4.5, no.

Another idea: 8 × 9 = 72, 72 × 2.5 = 180, 2.5 = 5/2, so 8 × 9 × 5 / 2

Check: 8 × 9 = 72, ×5 = 360, /2 = 180.

Digits: 8,2,9,5 — so 8 × 9 × 5 / 2

But order: 8 _ 2 _ 9 _ 5

So if we do 8 × 9 × 5 / 2, but 2 is second digit, 9 is third, 5 is fourth.

So expression: 8 × 2 × 9 × 5 / something, too many.

With three operators: 8 op1 2 op2 9 op3 5

Try: 8 × 2 × 9 × 5 = 720, too big.

8 × 9 × 5 / 2 = 360 / 2 = 180, but how to arrange with digits in order.

If we do 8 × 9 × 5 / 2, but 2 is before 9 and 5 in the sequence.

Sequence is 8,2,9,5 — so after 8 is 2, then 9, then 5.

So perhaps: 8 × 2 × 9 × 5 / 2, but extra 2.

No.

Another way: 180 = 90 × 2, 90 = 9 × 10, 10 = 5 × 2, but duplicate.

8 + 2 = 10, 9 × 5 = 45, 10 × 45 = 450, too big.

(8 + 2) × 9 × 2, no.

Let's try: 8 × 5 = 40, 40 × 4.5 = 180, 4.5 = 9/2, so 8 × 5 × 9 / 2

Same as before.

So 8 × 5 × 9 / 2 = 360 / 2 = 180.

Now, with digits 8,2,9,5 — so if we can do 8 × 5 × 9 / 2, but 2 is second, 5 is fourth.

So perhaps: 8 / 2 × 9 × 5

Calculate: 8 / 2 = 4, then 4 × 9 = 36, then 36 × 5 = 180 ✔

Yes! And digits in order: 8,2,9,5 — so 8 ÷ 2 × 9 × 5

Order: division and multiplication left to right: 8÷2=4, 4×9=36, 36×5=180.

Perfect.

So G: 8 ÷ 2 × 9 × 5 = 180

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H: 4 3 8 2 = 3

Target 3.

Small number.

Try: 4 + 3 - 8 + 2 = 1 ✘

4 - 3 + 8 - 2 = 7 ✘

4 × 3 - 8 - 2 = 12-8-2=2 ✘

4 + 3 - 8 ÷ 2 = 4+3-4=3 ✔

Check: 8 ÷ 2 = 4, then 4 + 3 = 7, then 7 - 4 = 3.

Digits: 4,3,8,2 — so 4 + 3 - 8 ÷ 2

Order: division first: 8÷2=4, then 4+3=7, then 7-4=3.

Yes.

So H: 4 + 3 - 8 ÷ 2 = 3

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Now, summarize all answers:

A: 8 × 5 + 2 - 6 = 36
B: 5 + 7 × 8 - 3 = 58
C: 8 × 8 - 8 × 4 = 32
D: 5 + 7 - 6 ÷ 3 = 10
E: 6 + 6 × 7 + 8 = 56
F: 4 ÷ 4 - 4 + 9 = 6
G: 8 ÷ 2 × 9 × 5 = 180
H: 4 + 3 - 8 ÷ 2 = 3

All verified.

Final Answer:
A: 8 × 5 + 2 - 6 = 36
B: 5 + 7 × 8 - 3 = 58
C: 8 × 8 - 8 × 4 = 32
D: 5 + 7 - 6 ÷ 3 = 10
E: 6 + 6 × 7 + 8 = 56
F: 4 ÷ 4 - 4 + 9 = 6
G: 8 ÷ 2 × 9 × 5 = 180
H: 4 + 3 - 8 ÷ 2 = 3