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Trigonometric Ratios Worksheet - Practice Finding Tangent, Sine, and Cosine for Right Triangles.

Worksheet with six right triangles, each labeled with angles and side lengths, asking to find indicated trigonometric ratios (tan, sin, cos).

Worksheet with six right triangles, each labeled with angles and side lengths, asking to find indicated trigonometric ratios (tan, sin, cos).

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Show Answer Key & Explanations Step-by-step solution for: Trig Ratio Worksheet Answer Key The trig. ratios, sine, cosine, and
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To solve these problems, we need to find the indicated trigonometric ratios for each triangle. We'll use the definitions of sine, cosine, and tangent:

- Sine (sin) = opposite / hypotenuse
- Cosine (cos) = adjacent / hypotenuse
- Tangent (tan) = opposite / adjacent

Let's go through each problem step by step.

Problem 1: tan θ


For this triangle:
- Opposite side to θ = 40
- Adjacent side to θ = 9

Using the formula for tangent:
\[ \tan \theta = \frac{\text{opposite}}{\text{adjacent}} = \frac{40}{9} \]

So, \(\tan \theta = \frac{40}{9}\).

Problem 2: sin θ


For this triangle:
- Opposite side to θ = 7.5
- Hypotenuse = 12.5

Using the formula for sine:
\[ \sin \theta = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{7.5}{12.5} \]

Simplify the fraction:
\[ \sin \theta = \frac{7.5 \div 2.5}{12.5 \div 2.5} = \frac{3}{5} \]

So, \(\sin \theta = \frac{3}{5}\).

Problem 3: cos θ


For this triangle:
- Adjacent side to θ = 8
- Hypotenuse = 17

Using the formula for cosine:
\[ \cos \theta = \frac{\text{adjacent}}{\text{hypotenuse}} = \frac{8}{17} \]

So, \(\cos \theta = \frac{8}{17}\).

Problem 4: tan θ


For this triangle:
- Opposite side to θ = 24
- Adjacent side to θ = 10

Using the formula for tangent:
\[ \tan \theta = \frac{\text{opposite}}{\text{adjacent}} = \frac{24}{10} \]

Simplify the fraction:
\[ \tan \theta = \frac{24 \div 2}{10 \div 2} = \frac{12}{5} \]

So, \(\tan \theta = \frac{12}{5}\).

Problem 5: sin θ


For this triangle:
- Opposite side to θ = 6
- Hypotenuse = 10

Using the formula for sine:
\[ \sin \theta = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{6}{10} \]

Simplify the fraction:
\[ \sin \theta = \frac{6 \div 2}{10 \div 2} = \frac{3}{5} \]

So, \(\sin \theta = \frac{3}{5}\).

Problem 6: cos θ


For this triangle:
- Adjacent side to θ = 16
- Hypotenuse = 20

Using the formula for cosine:
\[ \cos \theta = \frac{\text{adjacent}}{\text{hypotenuse}} = \frac{16}{20} \]

Simplify the fraction:
\[ \cos \theta = \frac{16 \div 4}{20 \div 4} = \frac{4}{5} \]

So, \(\cos \theta = \frac{4}{5}\).

Final Answer:
1. \(\tan \theta = \frac{40}{9}\)
2. \(\sin \theta = \frac{3}{5}\)
3. \(\cos \theta = \frac{8}{17}\)
4. \(\tan \theta = \frac{12}{5}\)
5. \(\sin \theta = \frac{3}{5}\)
6. \(\cos \theta = \frac{4}{5}\)
Parent Tip: Review the logic above to help your child master the concept of intro to trig worksheets.
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