Ionic Bonding Worksheet Date - Fill and Sign Printable Template Online - Free Printable

The task involves drawing dot-and-cross diagrams for each chemical compound listed. A dot-and-cross diagram is a visual representation of the bonding in a molecule or ionic compound, showing how electrons are shared or transferred between atoms.

Steps to Solve:

1. Identify the type of bonding:
- Ionic Bonding: Electrons are transferred from one atom to another, forming ions.
- Covalent Bonding: Electrons are shared between atoms.

2. Determine the number of valence electrons:
- Use the periodic table to find the number of valence electrons for each element.

3. Draw the diagram:
- For ionic compounds, show the transfer of electrons to form ions.
- For covalent compounds, show the sharing of electrons to form bonds.

4. Label the diagram:
- Clearly indicate the atoms and their charges (for ionic compounds).

Solutions:

#### 1. NaCl
- Sodium (Na) has 1 valence electron.
- Chlorine (Cl) has 7 valence electrons.
- Sodium donates its 1 electron to chlorine, forming Na⁺ and Cl⁻.

Diagram:
```
Na: ●
Cl: ●●●●●●●

Na⁺: [●]
Cl⁻: [●●●●●●●●]
```

---

#### 2. CaO
- Calcium (Ca) has 2 valence electrons.
- Oxygen (O) has 6 valence electrons.
- Calcium donates its 2 electrons to oxygen, forming Ca²⁺ and O²⁻.

Diagram:
```
Ca: ●●
O: ●●●●●●

Ca²⁺: [●●]
O²⁻: [●●●●●●●●]
```

---

#### 3. AlN
- Aluminum (Al) has 3 valence electrons.
- Nitrogen (N) has 5 valence electrons.
- Aluminum donates its 3 electrons to nitrogen, forming Al³⁺ and N³⁻.

Diagram:
```
Al: ●●●
N: ●●●●●

Al³⁺: [●●●]
N³⁻: [●●●●●●●●●]
```

---

#### 4. MgBr₂
- Magnesium (Mg) has 2 valence electrons.
- Bromine (Br) has 7 valence electrons.
- Magnesium donates its 2 electrons to two bromine atoms, forming Mg²⁺ and 2 Br⁻.

Diagram:
```
Mg: ●●
Br: ●●●●●●●

Mg²⁺: [●●]
Br⁻: [●●●●●●●●] (for each Br)
```

---

#### 5. FeCl₃
- Iron (Fe) has 8 valence electrons (in this case, it uses 3 electrons for bonding).
- Chlorine (Cl) has 7 valence electrons.
- Iron donates 3 electrons to three chlorine atoms, forming Fe³⁺ and 3 Cl⁻.

Diagram:
```
Fe: ●●●●●●●●
Cl: ●●●●●●●

Fe³⁺: [●●●]
Cl⁻: [●●●●●●●●] (for each Cl)
```

---

#### 6. CuF₂
- Copper (Cu) has 11 valence electrons (in this case, it uses 2 electrons for bonding).
- Fluorine (F) has 7 valence electrons.
- Copper donates 2 electrons to two fluorine atoms, forming Cu²⁺ and 2 F⁻.

Diagram:
```
Cu: ●●●●●●●●●●●
F: ●●●●●●●

Cu²⁺: [●●]
F⁻: [●●●●●●●●] (for each F)
```

---

#### 7. Li₂O
- Lithium (Li) has 1 valence electron.
- Oxygen (O) has 6 valence electrons.
- Two lithium atoms donate their 2 electrons to oxygen, forming 2 Li⁺ and O²⁻.

Diagram:
```
Li: ●
O: ●●●●●●

Li⁺: [●] (for each Li)
O²⁻: [●●●●●●●●]
```

---

#### 8. AgI
- Silver (Ag) has 1 valence electron.
- Iodine (I) has 7 valence electrons.
- Silver donates its 1 electron to iodine, forming Ag⁺ and I⁻.

Diagram:
```
Ag: ●
I: ●●●●●●●

Ag⁺: [●]
I⁻: [●●●●●●●●]
```

---

#### 9. BaS
- Barium (Ba) has 2 valence electrons.
- Sulfur (S) has 6 valence electrons.
- Barium donates its 2 electrons to sulfur, forming Ba²⁺ and S²⁻.

Diagram:
```
Ba: ●●
S: ●●●●●●

Ba²⁺: [●●]
S²⁻: [●●●●●●●●]
```

---

#### 10. Al₂O₃
- Aluminum (Al) has 3 valence electrons.
- Oxygen (O) has 6 valence electrons.
- Two aluminum atoms donate 6 electrons to three oxygen atoms, forming 2 Al³⁺ and 3 O²⁻.

Diagram:
```
Al: ●●●
O: ●●●●●●

Al³⁺: [●●●] (for each Al)
O²⁻: [●●●●●●●●] (for each O)
```

---

#### 11. ZnS
- Zinc (Zn) has 2 valence electrons.
- Sulfur (S) has 6 valence electrons.
- Zinc donates its 2 electrons to sulfur, forming Zn²⁺ and S²⁻.

Diagram:
```
Zn: ●●
S: ●●●●●●

Zn²⁺: [●●]
S²⁻: [●●●●●●●●]
```

---

#### 12. AsH₃
- Arsenic (As) has 5 valence electrons.
- Hydrogen (H) has 1 valence electron.
- Arsenic shares its 3 electrons with 3 hydrogen atoms, forming covalent bonds.

Diagram:
```
As: ●●●●●
H: ●

As: :●●●●●:
H: ●
|
H: ●
|
H: ●
```

---

Final Answer:

Each compound's dot-and-cross diagram should be drawn according to the steps above. The final answer is:

\boxed{\text{See detailed explanations and diagrams above.}}