Here are the solutions for each literal equation, solved step by step.
1. Solve $3y - x = 5$ for $y$
* Add $x$ to both sides: $3y = x + 5$
* Divide every term by 3: $y = \frac{x + 5}{3}$ or $y = \frac{x}{3} + \frac{5}{3}$
2. Solve $g = 4t - 5$ for $t$
* Add 5 to both sides: $g + 5 = 4t$
* Divide both sides by 4: $t = \frac{g + 5}{4}$
3. Solve $w = 2b - 4$ for $b$
* Add 4 to both sides: $w + 4 = 2b$
* Divide both sides by 2: $b = \frac{w + 4}{2}$ or $b = \frac{w}{2} + 2$
4. Solve $k = -2b + 1$ for $b$
* Subtract 1 from both sides: $k - 1 = -2b$
* Divide both sides by -2: $b = \frac{k - 1}{-2}$
* Simplify (optional): $b = \frac{1 - k}{2}$
5. Solve $m = -2p + 3$ for $p$
* Subtract 3 from both sides: $m - 3 = -2p$
* Divide both sides by -2: $p = \frac{m - 3}{-2}$
* Simplify (optional): $p = \frac{3 - m}{2}$
6. Solve $r = \frac{5v}{2}$ for $v$
* Multiply both sides by 2: $2r = 5v$
* Divide both sides by 5: $v = \frac{2r}{5}$
7. Solve $2w = 2n + 3$ for $n$
* Subtract 3 from both sides: $2w - 3 = 2n$
* Divide both sides by 2: $n = \frac{2w - 3}{2}$ or $n = w - \frac{3}{2}$
8. Solve $2p + 1 = h$ for $p$
* Subtract 1 from both sides: $2p = h - 1$
* Divide both sides by 2: $p = \frac{h - 1}{2}$
Final Answer:
1. $y = \frac{x + 5}{3}$
2. $t = \frac{g + 5}{4}$
3. $b = \frac{w + 4}{2}$
4. $b = \frac{1 - k}{2}$
5. $p = \frac{3 - m}{2}$
6. $v = \frac{2r}{5}$
7. $n = \frac{2w - 3}{2}$
8. $p = \frac{h - 1}{2}$
Parent Tip: Review the logic above to help your child master the concept of isolating variables worksheet.