Let’s solve each problem step by step using the same method shown in example #1: prime factorization with a division table, then multiply all the divisors and remaining numbers to get the LCM.
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Problem 3: (12, 30)
We’ll divide both numbers by common prime factors until we can’t anymore.
Start with 2:
- 12 ÷ 2 = 6
- 30 ÷ 2 = 15
→ Write down 2 on the left.
Now try 2 again? 6 is divisible by 2, but 15 is not → skip.
Try 3:
- 6 ÷ 3 = 2
- 15 ÷ 3 = 5
→ Write down 3 on the left.
Now we have 2 and 5 — no more common factors.
So the divisors used: 2, 3
Remaining numbers: 2, 5
LCM = 2 × 3 × 2 × 5 =
60
✔ Check: Multiples of 12: 12, 24, 36, 48, 60...
Multiples of 30: 30, 60... → Yes, 60 is the least common multiple.
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Problem 4: (15, 25)
Start with smallest prime that divides both: 5
- 15 ÷ 5 = 3
- 25 ÷ 5 = 5
→ Write down 5.
Now we have 3 and 5 — no common factors.
Divisors: 5
Remaining: 3, 5
LCM = 5 × 3 × 5 =
75
✔ Check: Multiples of 15: 15, 30, 45, 60, 75...
Multiples of 25: 25, 50, 75... → Correct.
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Problem 5: (30, 10)
Note: 10 divides into 30 evenly. So LCM should be 30.
But let’s do it properly:
Start with 2:
- 30 ÷ 2 = 15
- 10 ÷ 2 = 5
→ Write 2.
Now 15 and 5 — try 5:
- 15 ÷ 5 = 3
- 5 ÷ 5 = 1
→ Write 5.
Left with 3 and 1.
Divisors: 2, 5
Remaining: 3, 1
LCM = 2 × 5 × 3 × 1 =
30
✔ Makes sense — since 30 is a multiple of 10, LCM is 30.
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Problem 6: (25, 45)
Start with 5:
- 25 ÷ 5 = 5
- 45 ÷ 5 = 9
→ Write 5.
Again, 5 and 9 — 5 doesn’t divide 9, so stop dividing by 5.
No other common primes.
Divisors: 5
Remaining: 5, 9
LCM = 5 × 5 × 9 =
225
✔ Check:
Multiples of 25: 25, 50, 75, 100, 125, 150, 175, 200, 225...
Multiples of 45: 45, 90, 135, 180, 225... → Yes, 225 is correct.
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Final Answer:
3. 60
4. 75
5. 30
6. 225
Parent Tip: Review the logic above to help your child master the concept of least common multiple worksheet 6th grade.