This worksheet demonstrates how to solve limiting reagent problems using dimensional analysis and balanced chemical equations.

- The balanced equation is C₃H₈ + 5O₂ → 3CO₂ + 4H₂O.
- For part (a), using 14.8 g of C₃H₈ and 3.44 g of O₂, the limiting reagent is O₂ because it produces less H₂O (1.55 g) compared to C₃H₈ (24.2 g).
- For part (b), using the limiting reagent O₂, the mass of CO₂ produced is 2.84 g.
- For part (c), the mass of H₂O produced is 1.55 g.
- For part (d), the mass of excess C₃H₈ remaining is 13.9 g.
- For problem 2, using 10.0 g of Al₂(SO₃)₃ and 10.0 g of NaOH, the limiting reagent is Al₂(SO₃)₃ because it produces less Na₂SO₄ (12.9 g) compared to NaOH (15.8 g).