Line Plot of the Day: Analyze fudge amounts in pounds using a line plot with fraction data.

Let’s solve each question step by step.

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Question 1: How much fudge is in all the packages containing 1¼ and 1¾ pounds?

First, look at the line plot:

- At 1¼ pounds, there are 4 X’s → that means 4 packages of 1¼ pounds.
- At 1¾ pounds, there are 2 X’s → that means 2 packages of 1¾ pounds.

Now calculate total weight for each:

→ For 1¼ pounds:
4 × 1¼ = 4 × (5/4) = 20/4 = 5 pounds

→ For 1¾ pounds:
2 × 1¾ = 2 × (7/4) = 14/4 = 3½ pounds

Now add them together:
5 + 3½ = 8½ pounds

✔ So, total fudge in those packages is 8½ pounds.

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Question 2: What is the range of the data (maximum - minimum)?

Look at the line plot to find the smallest and largest values with X’s.

- The minimum value with an X is ¼ pound (there are 2 X’s there).
- The maximum value with an X is 2 pounds (there are 2 X’s there).

Range = Maximum – Minimum = 2 – ¼ = 1¾ pounds

✔ Range is 1¾ pounds.

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Question 3: If all the fudge was combined into one container and then redistributed into five equal containers, how many pounds of fudge would be in each container?

We need to find the total amount of fudge first.

List every package from the line plot:

- ¼ lb → 2 packages → 2 × ¼ = ½ lb
- ¾ lb → 2 packages → 2 × ¾ = 1½ lb
- 1 lb → 1 package → 1 × 1 = 1 lb
- 1¼ lb → 4 packages → 4 × 1¼ = 5 lb
- 1½ lb → 3 packages → 3 × 1½ = 4½ lb
- 1¾ lb → 2 packages → 2 × 1¾ = 3½ lb
- 2 lb → 2 packages → 2 × 2 = 4 lb

Now add them up:

Start adding step by step:

½ + 1½ = 2
2 + 1 = 3
3 + 5 = 8
8 + 4½ = 12½
12½ + 3½ = 16
16 + 4 = 20 pounds total

Now divide equally among 5 containers:

20 ÷ 5 = 4 pounds per container

✔ Each container would have 4 pounds.

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Final Answer:
1. 8½ pounds
2. 1¾ pounds
3. 4 pounds