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Solve linear equations in one variable with this printable worksheet from Math Monks.

Linear Equation in One Variable Worksheet with ten algebraic equations to solve for the unknown variable, including variables x, y, n, and z, from Math Monks.

Linear Equation in One Variable Worksheet with ten algebraic equations to solve for the unknown variable, including variables x, y, n, and z, from Math Monks.

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Show Answer Key & Explanations Step-by-step solution for: Linear Equations Worksheets with Answer Key

Problem: Solve the given linear equations to find the unknown variable.



We will solve each equation step by step.

---

#### Equation 1: \( 12 - x = 7 \)

1. Start with the equation:
\[
12 - x = 7
\]

2. Subtract 12 from both sides to isolate the term with \( x \):
\[
-x = 7 - 12
\]
\[
-x = -5
\]

3. Multiply both sides by \(-1\) to solve for \( x \):
\[
x = 5
\]

Solution: \( x = 5 \)

---

#### Equation 2: \( 9 + 6x = 3x + 13 \)

1. Start with the equation:
\[
9 + 6x = 3x + 13
\]

2. Subtract \( 3x \) from both sides to get all \( x \)-terms on one side:
\[
9 + 6x - 3x = 13
\]
\[
9 + 3x = 13
\]

3. Subtract 9 from both sides to isolate the term with \( x \):
\[
3x = 13 - 9
\]
\[
3x = 4
\]

4. Divide both sides by 3 to solve for \( x \):
\[
x = \frac{4}{3}
\]

Solution: \( x = \frac{4}{3} \)

---

#### Equation 3: \( 10x + 3 + 10x = 13x - 3 \)

1. Start with the equation:
\[
10x + 3 + 10x = 13x - 3
\]

2. Combine like terms on the left-hand side:
\[
20x + 3 = 13x - 3
\]

3. Subtract \( 13x \) from both sides to get all \( x \)-terms on one side:
\[
20x - 13x + 3 = -3
\]
\[
7x + 3 = -3
\]

4. Subtract 3 from both sides to isolate the term with \( x \):
\[
7x = -3 - 3
\]
\[
7x = -6
\]

5. Divide both sides by 7 to solve for \( x \):
\[
x = -\frac{6}{7}
\]

Solution: \( x = -\frac{6}{7} \)

---

#### Equation 4: \( 0.25(60) + 0.10x = 0.15(60 + x) \)

1. Start with the equation:
\[
0.25(60) + 0.10x = 0.15(60 + x)
\]

2. Simplify both sides:
\[
0.25 \cdot 60 = 15 \quad \text{and} \quad 0.15(60 + x) = 0.15 \cdot 60 + 0.15x = 9 + 0.15x
\]
So the equation becomes:
\[
15 + 0.10x = 9 + 0.15x
\]

3. Subtract \( 0.10x \) from both sides:
\[
15 = 9 + 0.05x
\]

4. Subtract 9 from both sides to isolate the term with \( x \):
\[
15 - 9 = 0.05x
\]
\[
6 = 0.05x
\]

5. Divide both sides by 0.05 to solve for \( x \):
\[
x = \frac{6}{0.05} = 120
\]

Solution: \( x = 120 \)

---

#### Equation 5: \( 3 = 4(x - 2) + 5 - 4x \)

1. Start with the equation:
\[
3 = 4(x - 2) + 5 - 4x
\]

2. Distribute the 4 in the term \( 4(x - 2) \):
\[
3 = 4x - 8 + 5 - 4x
\]

3. Combine like terms:
\[
3 = (4x - 4x) + (-8 + 5)
\]
\[
3 = 0x - 3
\]
\[
3 = -3
\]

This is a contradiction, so there is no solution.

Solution: No solution

---

#### Equation 6: \( \frac{5y}{9} - 3 = 6 \)

1. Start with the equation:
\[
\frac{5y}{9} - 3 = 6
\]

2. Add 3 to both sides to isolate the term with \( y \):
\[
\frac{5y}{9} = 6 + 3
\]
\[
\frac{5y}{9} = 9
\]

3. Multiply both sides by 9 to eliminate the denominator:
\[
5y = 9 \cdot 9
\]
\[
5y = 81
\]

4. Divide both sides by 5 to solve for \( y \):
\[
y = \frac{81}{5}
\]

Solution: \( y = \frac{81}{5} \)

---

#### Equation 7: \( \frac{n}{10} = 9 - \frac{n}{4} \)

1. Start with the equation:
\[
\frac{n}{10} = 9 - \frac{n}{4}
\]

2. Eliminate the fractions by finding a common denominator (LCM of 10 and 4 is 20). Multiply every term by 20:
\[
20 \cdot \frac{n}{10} = 20 \cdot 9 - 20 \cdot \frac{n}{4}
\]
\[
2n = 180 - 5n
\]

3. Add \( 5n \) to both sides to get all \( n \)-terms on one side:
\[
2n + 5n = 180
\]
\[
7n = 180
\]

4. Divide both sides by 7 to solve for \( n \):
\[
n = \frac{180}{7}
\]

Solution: \( n = \frac{180}{7} \)

---

#### Equation 8: \( 21.1w + 4.6 = 10.9w \)

1. Start with the equation:
\[
21.1w + 4.6 = 10.9w
\]

2. Subtract \( 10.9w \) from both sides to get all \( w \)-terms on one side:
\[
21.1w - 10.9w + 4.6 = 0
\]
\[
10.2w + 4.6 = 0
\]

3. Subtract 4.6 from both sides to isolate the term with \( w \):
\[
10.2w = -4.6
\]

4. Divide both sides by 10.2 to solve for \( w \):
\[
w = \frac{-4.6}{10.2}
\]
\[
w = -\frac{23}{51}
\]

Solution: \( w = -\frac{23}{51} \)

---

#### Equation 9: \( -5(3 - 4x) = -6 + 20x \)

1. Start with the equation:
\[
-5(3 - 4x) = -6 + 20x
\]

2. Distribute the \(-5\) on the left-hand side:
\[
-5 \cdot 3 + (-5) \cdot (-4x) = -6 + 20x
\]
\[
-15 + 20x = -6 + 20x
\]

3. Subtract \( 20x \) from both sides:
\[
-15 = -6
\]

This is a contradiction, so there is no solution.

Solution: No solution

---

#### Equation 10: \( 9.2z - 4.3 = 50.8 \)

1. Start with the equation:
\[
9.2z - 4.3 = 50.8
\]

2. Add 4.3 to both sides to isolate the term with \( z \):
\[
9.2z = 50.8 + 4.3
\]
\[
9.2z = 55.1
\]

3. Divide both sides by 9.2 to solve for \( z \):
\[
z = \frac{55.1}{9.2}
\]
\[
z = 6
\]

Solution: \( z = 6 \)

---

Final Answers:


\[
\boxed{
\begin{aligned}
1. & \ x = 5 \\
2. & \ x = \frac{4}{3} \\
3. & \ x = -\frac{6}{7} \\
4. & \ x = 120 \\
5. & \ \text{No solution} \\
6. & \ y = \frac{81}{5} \\
7. & \ n = \frac{180}{7} \\
8. & \ w = -\frac{23}{51} \\
9. & \ \text{No solution} \\
10. & \ z = 6
\end{aligned}
}
\]
Parent Tip: Review the logic above to help your child master the concept of linear equation practice worksheet.
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