Simple Linear Equations (A) worksheet featuring 15 equations to solve for variables, ideal for math practice.
Worksheet titled "Simple Linear Equations (A)" with 15 algebraic equations to solve for variables, displayed in three columns on a white background.
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Step-by-step solution for: The Solving Linear Equations (Including Negative Values) -- Form ...
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Show Answer Key & Explanations
Step-by-step solution for: The Solving Linear Equations (Including Negative Values) -- Form ...
Problem: Solve each of the given simple linear equations for the variable.
#### Equations:
1. $\frac{a}{8} = -4$
2. $b - (-5) = 13$
3. $3 + \frac{18}{z} = 12$
4. $-9 + \frac{36}{a} = -5$
5. $u + 2 = -8$
6. $2z = 2$
7. $-1 - \frac{y}{8} = -7$
8. $\frac{8}{u} - (-2) = 6$
9. $a - 2 = -10$
10. $\frac{u}{6} = 3$
11. $10 - \frac{b}{2} = 3$
12. $\frac{y}{-7} = -7$
13. $\frac{b}{7} = -5$
14. $\frac{-2}{c} = 2$
15. $\frac{c}{5} + 3 = 8$
---
Solutions:
#### 1. $\frac{a}{8} = -4$
To solve for $a$, multiply both sides by 8:
$$
\frac{a}{8} \cdot 8 = -4 \cdot 8
$$
$$
a = -32
$$
Answer: $a = -32$
---
#### 2. $b - (-5) = 13$
Simplify the left side:
$$
b + 5 = 13
$$
Subtract 5 from both sides:
$$
b = 13 - 5
$$
$$
b = 8
$$
Answer: $b = 8$
---
#### 3. $3 + \frac{18}{z} = 12$
Subtract 3 from both sides:
$$
\frac{18}{z} = 12 - 3
$$
$$
\frac{18}{z} = 9
$$
Multiply both sides by $z$:
$$
18 = 9z
$$
Divide both sides by 9:
$$
z = \frac{18}{9}
$$
$$
z = 2
$$
Answer: $z = 2$
---
#### 4. $-9 + \frac{36}{a} = -5$
Add 9 to both sides:
$$
\frac{36}{a} = -5 + 9
$$
$$
\frac{36}{a} = 4
$$
Multiply both sides by $a$:
$$
36 = 4a
$$
Divide both sides by 4:
$$
a = \frac{36}{4}
$$
$$
a = 9
$$
Answer: $a = 9$
---
#### 5. $u + 2 = -8$
Subtract 2 from both sides:
$$
u = -8 - 2
$$
$$
u = -10
$$
Answer: $u = -10$
---
#### 6. $2z = 2$
Divide both sides by 2:
$$
z = \frac{2}{2}
$$
$$
z = 1
$$
Answer: $z = 1$
---
#### 7. $-1 - \frac{y}{8} = -7$
Add 1 to both sides:
$$
-\frac{y}{8} = -7 + 1
$$
$$
-\frac{y}{8} = -6
$$
Multiply both sides by $-8$:
$$
y = -6 \cdot (-8)
$$
$$
y = 48
$$
Answer: $y = 48$
---
#### 8. $\frac{8}{u} - (-2) = 6$
Simplify the left side:
$$
\frac{8}{u} + 2 = 6
$$
Subtract 2 from both sides:
$$
\frac{8}{u} = 6 - 2
$$
$$
\frac{8}{u} = 4
$$
Multiply both sides by $u$:
$$
8 = 4u
$$
Divide both sides by 4:
$$
u = \frac{8}{4}
$$
$$
u = 2
$$
Answer: $u = 2$
---
#### 9. $a - 2 = -10$
Add 2 to both sides:
$$
a = -10 + 2
$$
$$
a = -8
$$
Answer: $a = -8$
---
#### 10. $\frac{u}{6} = 3$
Multiply both sides by 6:
$$
u = 3 \cdot 6
$$
$$
u = 18
$$
Answer: $u = 18$
---
#### 11. $10 - \frac{b}{2} = 3$
Subtract 10 from both sides:
$$
-\frac{b}{2} = 3 - 10
$$
$$
-\frac{b}{2} = -7
$$
Multiply both sides by $-2$:
$$
b = -7 \cdot (-2)
$$
$$
b = 14
$$
Answer: $b = 14$
---
#### 12. $\frac{y}{-7} = -7$
Multiply both sides by $-7$:
$$
y = -7 \cdot (-7)
$$
$$
y = 49
$$
Answer: $y = 49$
---
#### 13. $\frac{b}{7} = -5$
Multiply both sides by 7:
$$
b = -5 \cdot 7
$$
$$
b = -35
$$
Answer: $b = -35$
---
#### 14. $\frac{-2}{c} = 2$
Multiply both sides by $c$:
$$
-2 = 2c
$$
Divide both sides by 2:
$$
c = \frac{-2}{2}
$$
$$
c = -1
$$
Answer: $c = -1$
---
#### 15. $\frac{c}{5} + 3 = 8$
Subtract 3 from both sides:
$$
\frac{c}{5} = 8 - 3
$$
$$
\frac{c}{5} = 5
$$
Multiply both sides by 5:
$$
c = 5 \cdot 5
$$
$$
c = 25
$$
Answer: $c = 25$
---
Final Answers:
$$
\boxed{
\begin{aligned}
1. & \ a = -32 \\
2. & \ b = 8 \\
3. & \ z = 2 \\
4. & \ a = 9 \\
5. & \ u = -10 \\
6. & \ z = 1 \\
7. & \ y = 48 \\
8. & \ u = 2 \\
9. & \ a = -8 \\
10. & \ u = 18 \\
11. & \ b = 14 \\
12. & \ y = 49 \\
13. & \ b = -35 \\
14. & \ c = -1 \\
15. & \ c = 25
\end{aligned}
}
$$
Parent Tip: Review the logic above to help your child master the concept of linear problems worksheet.