Equation Word Problems Worksheets - Free Printable
Educational worksheet: Equation Word Problems Worksheets. Download and print for classroom or home learning activities.
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Step-by-step solution for: Equation Word Problems Worksheets
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Show Answer Key & Explanations
Step-by-step solution for: Equation Word Problems Worksheets
Let's solve each problem step by step.
---
Lily has 3 less than 4 times the amount of t-shirts as Bree. If Bree has 33 t-shirts, how many does Lily have?
#### Solution:
1. Let \( B \) be the number of t-shirts Bree has.
2. According to the problem, \( B = 33 \).
3. Lily has 3 less than 4 times the amount of t-shirts as Bree. This can be expressed as:
\[
L = 4B - 3
\]
4. Substitute \( B = 33 \) into the equation:
\[
L = 4(33) - 3
\]
5. Calculate:
\[
L = 132 - 3 = 129
\]
Answer:
\[
\boxed{129}
\]
---
4 times a number is equivalent to 8 more than 2 times the number. What is the number?
#### Solution:
1. Let \( x \) be the number.
2. According to the problem, 4 times the number is equal to 8 more than 2 times the number. This can be expressed as:
\[
4x = 2x + 8
\]
3. Solve for \( x \):
\[
4x - 2x = 8
\]
\[
2x = 8
\]
\[
x = \frac{8}{2} = 4
\]
Answer:
\[
\boxed{4}
\]
---
Pedro is 8 years older than twice the age of his cousin. If Pedro is 30, how old is his cousin?
#### Solution:
1. Let \( C \) be the age of Pedro's cousin.
2. According to the problem, Pedro is 8 years older than twice the age of his cousin. This can be expressed as:
\[
P = 2C + 8
\]
3. We are given that Pedro is 30 years old, so \( P = 30 \). Substitute this into the equation:
\[
30 = 2C + 8
\]
4. Solve for \( C \):
\[
30 - 8 = 2C
\]
\[
22 = 2C
\]
\[
C = \frac{22}{2} = 11
\]
Answer:
\[
\boxed{11}
\]
---
A car rental service charges a rental fee of $125 plus $30 per hour to rent a car. If Craig’s total bill is $305, how many hours did he have the rental car?
#### Solution:
1. Let \( h \) be the number of hours Craig rented the car.
2. The total cost is the sum of the rental fee and the hourly charge. This can be expressed as:
\[
\text{Total Cost} = 125 + 30h
\]
3. We are given that the total bill is $305. Substitute this into the equation:
\[
305 = 125 + 30h
\]
4. Solve for \( h \):
\[
305 - 125 = 30h
\]
\[
180 = 30h
\]
\[
h = \frac{180}{30} = 6
\]
Answer:
\[
\boxed{6}
\]
---
2 times a number increased by 10 is 24. Find the number.
#### Solution:
1. Let \( x \) be the number.
2. According to the problem, 2 times the number increased by 10 is 24. This can be expressed as:
\[
2x + 10 = 24
\]
3. Solve for \( x \):
\[
2x = 24 - 10
\]
\[
2x = 14
\]
\[
x = \frac{14}{2} = 7
\]
Answer:
\[
\boxed{7}
\]
---
Kyla spent 120 minutes reading this week. If this was 10 more than 2 times the amount of time she spent reading last week, how many minutes did she read last week?
#### Solution:
1. Let \( t \) be the number of minutes Kyla spent reading last week.
2. According to the problem, 120 minutes is 10 more than 2 times the amount of time she spent reading last week. This can be expressed as:
\[
120 = 2t + 10
\]
3. Solve for \( t \):
\[
120 - 10 = 2t
\]
\[
110 = 2t
\]
\[
t = \frac{110}{2} = 55
\]
Answer:
\[
\boxed{55}
\]
---
The sum of 3 consecutive even numbers is 18. What are the three numbers?
#### Solution:
1. Let the three consecutive even numbers be \( x \), \( x + 2 \), and \( x + 4 \).
2. According to the problem, their sum is 18. This can be expressed as:
\[
x + (x + 2) + (x + 4) = 18
\]
3. Simplify the equation:
\[
x + x + 2 + x + 4 = 18
\]
\[
3x + 6 = 18
\]
4. Solve for \( x \):
\[
3x = 18 - 6
\]
\[
3x = 12
\]
\[
x = \frac{12}{3} = 4
\]
5. The three consecutive even numbers are:
\[
x = 4, \quad x + 2 = 6, \quad x + 4 = 8
\]
Answer:
\[
\boxed{4, 6, 8}
\]
---
You give a third of your weekly allowance to a charity. Then you spend $8 at the mall. If you have $2 left to spend, how much is your weekly allowance?
#### Solution:
1. Let \( A \) be your weekly allowance.
2. You give a third of your allowance to charity, so you have:
\[
A - \frac{1}{3}A = \frac{2}{3}A
\]
3. After spending $8 at the mall, you have $2 left. This can be expressed as:
\[
\frac{2}{3}A - 8 = 2
\]
4. Solve for \( A \):
\[
\frac{2}{3}A = 2 + 8
\]
\[
\frac{2}{3}A = 10
\]
\[
A = 10 \times \frac{3}{2} = 15
\]
Answer:
\[
\boxed{15}
\]
---
1. \(\boxed{129}\)
2. \(\boxed{4}\)
3. \(\boxed{11}\)
4. \(\boxed{6}\)
5. \(\boxed{7}\)
6. \(\boxed{55}\)
7. \(\boxed{4, 6, 8}\)
8. \(\boxed{15}\)
---
Problem 1:
Lily has 3 less than 4 times the amount of t-shirts as Bree. If Bree has 33 t-shirts, how many does Lily have?
#### Solution:
1. Let \( B \) be the number of t-shirts Bree has.
2. According to the problem, \( B = 33 \).
3. Lily has 3 less than 4 times the amount of t-shirts as Bree. This can be expressed as:
\[
L = 4B - 3
\]
4. Substitute \( B = 33 \) into the equation:
\[
L = 4(33) - 3
\]
5. Calculate:
\[
L = 132 - 3 = 129
\]
Answer:
\[
\boxed{129}
\]
---
Problem 2:
4 times a number is equivalent to 8 more than 2 times the number. What is the number?
#### Solution:
1. Let \( x \) be the number.
2. According to the problem, 4 times the number is equal to 8 more than 2 times the number. This can be expressed as:
\[
4x = 2x + 8
\]
3. Solve for \( x \):
\[
4x - 2x = 8
\]
\[
2x = 8
\]
\[
x = \frac{8}{2} = 4
\]
Answer:
\[
\boxed{4}
\]
---
Problem 3:
Pedro is 8 years older than twice the age of his cousin. If Pedro is 30, how old is his cousin?
#### Solution:
1. Let \( C \) be the age of Pedro's cousin.
2. According to the problem, Pedro is 8 years older than twice the age of his cousin. This can be expressed as:
\[
P = 2C + 8
\]
3. We are given that Pedro is 30 years old, so \( P = 30 \). Substitute this into the equation:
\[
30 = 2C + 8
\]
4. Solve for \( C \):
\[
30 - 8 = 2C
\]
\[
22 = 2C
\]
\[
C = \frac{22}{2} = 11
\]
Answer:
\[
\boxed{11}
\]
---
Problem 4:
A car rental service charges a rental fee of $125 plus $30 per hour to rent a car. If Craig’s total bill is $305, how many hours did he have the rental car?
#### Solution:
1. Let \( h \) be the number of hours Craig rented the car.
2. The total cost is the sum of the rental fee and the hourly charge. This can be expressed as:
\[
\text{Total Cost} = 125 + 30h
\]
3. We are given that the total bill is $305. Substitute this into the equation:
\[
305 = 125 + 30h
\]
4. Solve for \( h \):
\[
305 - 125 = 30h
\]
\[
180 = 30h
\]
\[
h = \frac{180}{30} = 6
\]
Answer:
\[
\boxed{6}
\]
---
Problem 5:
2 times a number increased by 10 is 24. Find the number.
#### Solution:
1. Let \( x \) be the number.
2. According to the problem, 2 times the number increased by 10 is 24. This can be expressed as:
\[
2x + 10 = 24
\]
3. Solve for \( x \):
\[
2x = 24 - 10
\]
\[
2x = 14
\]
\[
x = \frac{14}{2} = 7
\]
Answer:
\[
\boxed{7}
\]
---
Problem 6:
Kyla spent 120 minutes reading this week. If this was 10 more than 2 times the amount of time she spent reading last week, how many minutes did she read last week?
#### Solution:
1. Let \( t \) be the number of minutes Kyla spent reading last week.
2. According to the problem, 120 minutes is 10 more than 2 times the amount of time she spent reading last week. This can be expressed as:
\[
120 = 2t + 10
\]
3. Solve for \( t \):
\[
120 - 10 = 2t
\]
\[
110 = 2t
\]
\[
t = \frac{110}{2} = 55
\]
Answer:
\[
\boxed{55}
\]
---
Problem 7:
The sum of 3 consecutive even numbers is 18. What are the three numbers?
#### Solution:
1. Let the three consecutive even numbers be \( x \), \( x + 2 \), and \( x + 4 \).
2. According to the problem, their sum is 18. This can be expressed as:
\[
x + (x + 2) + (x + 4) = 18
\]
3. Simplify the equation:
\[
x + x + 2 + x + 4 = 18
\]
\[
3x + 6 = 18
\]
4. Solve for \( x \):
\[
3x = 18 - 6
\]
\[
3x = 12
\]
\[
x = \frac{12}{3} = 4
\]
5. The three consecutive even numbers are:
\[
x = 4, \quad x + 2 = 6, \quad x + 4 = 8
\]
Answer:
\[
\boxed{4, 6, 8}
\]
---
Problem 8:
You give a third of your weekly allowance to a charity. Then you spend $8 at the mall. If you have $2 left to spend, how much is your weekly allowance?
#### Solution:
1. Let \( A \) be your weekly allowance.
2. You give a third of your allowance to charity, so you have:
\[
A - \frac{1}{3}A = \frac{2}{3}A
\]
3. After spending $8 at the mall, you have $2 left. This can be expressed as:
\[
\frac{2}{3}A - 8 = 2
\]
4. Solve for \( A \):
\[
\frac{2}{3}A = 2 + 8
\]
\[
\frac{2}{3}A = 10
\]
\[
A = 10 \times \frac{3}{2} = 15
\]
Answer:
\[
\boxed{15}
\]
---
Final Answers:
1. \(\boxed{129}\)
2. \(\boxed{4}\)
3. \(\boxed{11}\)
4. \(\boxed{6}\)
5. \(\boxed{7}\)
6. \(\boxed{55}\)
7. \(\boxed{4, 6, 8}\)
8. \(\boxed{15}\)
Parent Tip: Review the logic above to help your child master the concept of linear word problems worksheets.