Worksheet for practicing algebra and trigonometry logarithm problems, including converting forms, using properties, evaluating, and solving equations.
Algebra and Trigonometry Logarithms Worksheet with problems on converting exponential and logarithmic equations, using logarithm properties, evaluating logarithms, and solving for x.
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Show Answer Key & Explanations
Step-by-step solution for: Logarithm Worksheet | PDF | Logarithm | Combinatorics
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Show Answer Key & Explanations
Step-by-step solution for: Logarithm Worksheet | PDF | Logarithm | Combinatorics
Let's solve each section of this Logarithms Worksheet step by step and explain the solutions clearly.
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We use the rule:
If $ a^b = c $, then $ \log_a c = b $
1. $ 5^3 = 125 $
→ $ \log_5 125 = 3 $
2. $ 6^{-2} = \frac{1}{36} $
→ $ \log_6 \left(\frac{1}{36}\right) = -2 $
3. $ e^3 = 20.085 $
→ $ \ln(20.085) = 3 $ (since $ \ln = \log_e $)
4. $ e^x = 4 $
→ $ \ln 4 = x $
5. $ 8^2 = 64 $
→ $ \log_8 64 = 2 $
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Use: $ \log_a b = c $ → $ a^c = b $
1. $ \log_2 8 = x $
→ $ 2^x = 8 $
2. $ \log_5 625 = 4 $
→ $ 5^4 = 625 $
3. $ \log_x 13 = 5 $
→ $ x^5 = 13 $
4. $ \log_2 \frac{1}{8} = -3 $
→ $ 2^{-3} = \frac{1}{8} $
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1. $ \log 68 $
→ $ \approx 1.8325 $
2. $ \log 100 $
→ $ \log_{10} 100 = 2.0000 $
3. $ \ln 9 $
→ $ \approx 2.1972 $
4. $ \log 10 $
→ $ \log_{10} 10 = 1.0000 $
5. $ \ln 216 $
→ $ \approx 5.3753 $
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Use:
- $ \log_a (MN) = \log_a M + \log_a N $
- $ \log_a \left(\frac{M}{N}\right) = \log_a M - \log_a N $
- $ \log_a (M^n) = n \log_a M $
1. $ \log_2 5x $
→ $ \log_2 5 + \log_2 x $
2. $ \log_8 x^4 $
→ $ 4 \log_8 x $
3. $ \log_3 \frac{5}{x} $
→ $ \log_3 5 - \log_3 x $
4. $ \ln \sqrt{z} = \ln(z^{1/2}) $
→ $ \frac{1}{2} \ln z $
5. $ \ln z(z-1)^2 $
→ $ \ln z + \ln((z-1)^2) = \ln z + 2\ln(z-1) $
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Use:
- $ \log_a M + \log_a N = \log_a(MN) $
- $ \log_a M - \log_a N = \log_a\left(\frac{M}{N}\right) $
- $ n \log_a M = \log_a(M^n) $
1. $ \ln x + \ln 2 $
→ $ \ln(2x) $
2. $ \log_4 z - \log_4 y $
→ $ \log_4\left(\frac{z}{y}\right) $
3. $ 2 \log_2(x+4) $
→ $ \log_2((x+4)^2) $
4. $ \frac{1}{3} \log_3 5x $
→ $ \log_3((5x)^{1/3}) = \log_3 \sqrt[3]{5x} $
5. $ \log_3(x-2) - \log_3(x+2) $
→ $ \log_3\left(\frac{x-2}{x+2}\right) $
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$ \log_x 2 = 0.3562 $, $ \log_x 3 = 0.5646 $, $ \log_x 5 = 0.8271 $
Use log rules to find:
1. $ \log_x 6 = \log_x (2 \cdot 3) = \log_x 2 + \log_x 3 $
→ $ 0.3562 + 0.5646 = 0.9208 $
2. $ \log_x \frac{3}{2} = \log_x 3 - \log_x 2 $
→ $ 0.5646 - 0.3562 = 0.2084 $
3. $ \log_x 25 = \log_x (5^2) = 2 \log_x 5 $
→ $ 2 \times 0.8271 = 1.6542 $
4. $ \log_x \sqrt{2} = \log_x (2^{1/2}) = \frac{1}{2} \log_x 2 $
→ $ \frac{1}{2} \times 0.3562 = 0.1781 $
5. $ \log_x 40 = \log_x (8 \cdot 5) = \log_x (2^3 \cdot 5) = 3\log_x 2 + \log_x 5 $
→ $ 3(0.3562) + 0.8271 = 1.0686 + 0.8271 = 1.8957 $
---
Recall: $ \log_a b = c $ means $ a^c = b $
1. $ \log_5 x = 4 $
→ $ x = 5^4 = 625 $
2. $ \log_4 2 = x $
→ $ 4^x = 2 $. But $ 4^x = (2^2)^x = 2^{2x} = 2^1 $ → $ 2x = 1 $ → $ x = \frac{1}{2} $
3. $ \log_x 25 = 2 $
→ $ x^2 = 25 $ → $ x = 5 $ (since base must be positive and ≠ 1)
4. $ \log_{10} 0.1 = x $
→ $ 10^x = 0.1 = 10^{-1} $ → $ x = -1 $
5. $ \log_4 x = 2 $
→ $ x = 4^2 = 16 $
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#### Rewrite exponential as logarithmic:
1. $ \log_5 125 = 3 $
2. $ \log_6 \left(\frac{1}{36}\right) = -2 $
3. $ \ln 20.085 = 3 $
4. $ \ln 4 = x $
5. $ \log_8 64 = 2 $
#### Rewrite logarithmic as exponential:
1. $ 2^x = 8 $
2. $ 5^4 = 625 $
3. $ x^5 = 13 $
4. $ 2^{-3} = \frac{1}{8} $
#### Calculator evaluations:
1. $ \log 68 \approx 1.8325 $
2. $ \log 100 = 2.0000 $
3. $ \ln 9 \approx 2.1972 $
4. $ \log 10 = 1.0000 $
5. $ \ln 216 \approx 5.3753 $
#### Expand logs:
1. $ \log_2 5 + \log_2 x $
2. $ 4 \log_8 x $
3. $ \log_3 5 - \log_3 x $
4. $ \frac{1}{2} \ln z $
5. $ \ln z + 2\ln(z-1) $
#### Write as single logarithm:
1. $ \ln(2x) $
2. $ \log_4\left(\frac{z}{y}\right) $
3. $ \log_2((x+4)^2) $
4. $ \log_3 \sqrt[3]{5x} $
5. $ \log_3\left(\frac{x-2}{x+2}\right) $
#### Evaluate using given values:
1. $ \log_x 6 = 0.9208 $
2. $ \log_x \frac{3}{2} = 0.2084 $
3. $ \log_x 25 = 1.6542 $
4. $ \log_x \sqrt{2} = 0.1781 $
5. $ \log_x 40 = 1.8957 $
#### Find $ x $:
1. $ x = 625 $
2. $ x = \frac{1}{2} $
3. $ x = 5 $
4. $ x = -1 $
5. $ x = 16 $
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✔ All problems solved! Let me know if you'd like this formatted as a printable PDF or need explanations for any specific part.
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Section 1: Rewrite the exponential equation in logarithmic form
We use the rule:
If $ a^b = c $, then $ \log_a c = b $
1. $ 5^3 = 125 $
→ $ \log_5 125 = 3 $
2. $ 6^{-2} = \frac{1}{36} $
→ $ \log_6 \left(\frac{1}{36}\right) = -2 $
3. $ e^3 = 20.085 $
→ $ \ln(20.085) = 3 $ (since $ \ln = \log_e $)
4. $ e^x = 4 $
→ $ \ln 4 = x $
5. $ 8^2 = 64 $
→ $ \log_8 64 = 2 $
---
Section 2: Rewrite the logarithmic equation in exponential form
Use: $ \log_a b = c $ → $ a^c = b $
1. $ \log_2 8 = x $
→ $ 2^x = 8 $
2. $ \log_5 625 = 4 $
→ $ 5^4 = 625 $
3. $ \log_x 13 = 5 $
→ $ x^5 = 13 $
4. $ \log_2 \frac{1}{8} = -3 $
→ $ 2^{-3} = \frac{1}{8} $
---
Section 3: Use your calculator to evaluate each logarithm (round to four decimal places)
1. $ \log 68 $
→ $ \approx 1.8325 $
2. $ \log 100 $
→ $ \log_{10} 100 = 2.0000 $
3. $ \ln 9 $
→ $ \approx 2.1972 $
4. $ \log 10 $
→ $ \log_{10} 10 = 1.0000 $
5. $ \ln 216 $
→ $ \approx 5.3753 $
---
Section 4: Use properties of logarithms to expand each expression
Use:
- $ \log_a (MN) = \log_a M + \log_a N $
- $ \log_a \left(\frac{M}{N}\right) = \log_a M - \log_a N $
- $ \log_a (M^n) = n \log_a M $
1. $ \log_2 5x $
→ $ \log_2 5 + \log_2 x $
2. $ \log_8 x^4 $
→ $ 4 \log_8 x $
3. $ \log_3 \frac{5}{x} $
→ $ \log_3 5 - \log_3 x $
4. $ \ln \sqrt{z} = \ln(z^{1/2}) $
→ $ \frac{1}{2} \ln z $
5. $ \ln z(z-1)^2 $
→ $ \ln z + \ln((z-1)^2) = \ln z + 2\ln(z-1) $
---
Section 5: Use properties of logarithms to write as a single logarithm
Use:
- $ \log_a M + \log_a N = \log_a(MN) $
- $ \log_a M - \log_a N = \log_a\left(\frac{M}{N}\right) $
- $ n \log_a M = \log_a(M^n) $
1. $ \ln x + \ln 2 $
→ $ \ln(2x) $
2. $ \log_4 z - \log_4 y $
→ $ \log_4\left(\frac{z}{y}\right) $
3. $ 2 \log_2(x+4) $
→ $ \log_2((x+4)^2) $
4. $ \frac{1}{3} \log_3 5x $
→ $ \log_3((5x)^{1/3}) = \log_3 \sqrt[3]{5x} $
5. $ \log_3(x-2) - \log_3(x+2) $
→ $ \log_3\left(\frac{x-2}{x+2}\right) $
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Section 6: Given:
$ \log_x 2 = 0.3562 $, $ \log_x 3 = 0.5646 $, $ \log_x 5 = 0.8271 $
Use log rules to find:
1. $ \log_x 6 = \log_x (2 \cdot 3) = \log_x 2 + \log_x 3 $
→ $ 0.3562 + 0.5646 = 0.9208 $
2. $ \log_x \frac{3}{2} = \log_x 3 - \log_x 2 $
→ $ 0.5646 - 0.3562 = 0.2084 $
3. $ \log_x 25 = \log_x (5^2) = 2 \log_x 5 $
→ $ 2 \times 0.8271 = 1.6542 $
4. $ \log_x \sqrt{2} = \log_x (2^{1/2}) = \frac{1}{2} \log_x 2 $
→ $ \frac{1}{2} \times 0.3562 = 0.1781 $
5. $ \log_x 40 = \log_x (8 \cdot 5) = \log_x (2^3 \cdot 5) = 3\log_x 2 + \log_x 5 $
→ $ 3(0.3562) + 0.8271 = 1.0686 + 0.8271 = 1.8957 $
---
Section 7: Use the definition of the logarithmic function to find $ x $
Recall: $ \log_a b = c $ means $ a^c = b $
1. $ \log_5 x = 4 $
→ $ x = 5^4 = 625 $
2. $ \log_4 2 = x $
→ $ 4^x = 2 $. But $ 4^x = (2^2)^x = 2^{2x} = 2^1 $ → $ 2x = 1 $ → $ x = \frac{1}{2} $
3. $ \log_x 25 = 2 $
→ $ x^2 = 25 $ → $ x = 5 $ (since base must be positive and ≠ 1)
4. $ \log_{10} 0.1 = x $
→ $ 10^x = 0.1 = 10^{-1} $ → $ x = -1 $
5. $ \log_4 x = 2 $
→ $ x = 4^2 = 16 $
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✔ Final Answers Summary:
#### Rewrite exponential as logarithmic:
1. $ \log_5 125 = 3 $
2. $ \log_6 \left(\frac{1}{36}\right) = -2 $
3. $ \ln 20.085 = 3 $
4. $ \ln 4 = x $
5. $ \log_8 64 = 2 $
#### Rewrite logarithmic as exponential:
1. $ 2^x = 8 $
2. $ 5^4 = 625 $
3. $ x^5 = 13 $
4. $ 2^{-3} = \frac{1}{8} $
#### Calculator evaluations:
1. $ \log 68 \approx 1.8325 $
2. $ \log 100 = 2.0000 $
3. $ \ln 9 \approx 2.1972 $
4. $ \log 10 = 1.0000 $
5. $ \ln 216 \approx 5.3753 $
#### Expand logs:
1. $ \log_2 5 + \log_2 x $
2. $ 4 \log_8 x $
3. $ \log_3 5 - \log_3 x $
4. $ \frac{1}{2} \ln z $
5. $ \ln z + 2\ln(z-1) $
#### Write as single logarithm:
1. $ \ln(2x) $
2. $ \log_4\left(\frac{z}{y}\right) $
3. $ \log_2((x+4)^2) $
4. $ \log_3 \sqrt[3]{5x} $
5. $ \log_3\left(\frac{x-2}{x+2}\right) $
#### Evaluate using given values:
1. $ \log_x 6 = 0.9208 $
2. $ \log_x \frac{3}{2} = 0.2084 $
3. $ \log_x 25 = 1.6542 $
4. $ \log_x \sqrt{2} = 0.1781 $
5. $ \log_x 40 = 1.8957 $
#### Find $ x $:
1. $ x = 625 $
2. $ x = \frac{1}{2} $
3. $ x = 5 $
4. $ x = -1 $
5. $ x = 16 $
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✔ All problems solved! Let me know if you'd like this formatted as a printable PDF or need explanations for any specific part.
Parent Tip: Review the logic above to help your child master the concept of logarithm worksheet with answers.