Let's solve each of these division problems step by step. These are basic long division problems where we divide a two-digit number by a single-digit number.
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Row 1
1. $ 2 \div 18 $ → $ 18 \div 2 = 9 $
2. $ 4 \div 24 $ → $ 24 \div 4 = 6 $
3. $ 4 \div 32 $ → $ 32 \div 4 = 8 $
4. $ 3 \div 27 $ → $ 27 \div 3 = 9 $
Row 2
5. $ 4 \div 36 $ → $ 36 \div 4 = 9 $
6. $ 2 \div 14 $ → $ 14 \div 2 = 7 $
7. $ 3 \div 21 $ → $ 21 \div 3 = 7 $
8. $ 4 \div 28 $ → $ 28 \div 4 = 7 $
Row 3
9. $ 4 \div 20 $ → $ 20 \div 4 = 5 $
10. $ 3 \div 24 $ → $ 24 \div 3 = 8 $
11. $ 2 \div 12 $ → $ 12 \div 2 = 6 $
12. $ 4 \div 16 $ → $ 16 \div 4 = 4 $
Row 4
13. $ 3 \div 18 $ → $ 18 \div 3 = 6 $
14. $ 5 \div 45 $ → $ 45 \div 5 = 9 $
15. $ 5 \div 35 $ → $ 35 \div 5 = 7 $
16. $ 2 \div 16 $ → $ 16 \div 2 = 8 $
Row 5
17. $ 6 \div 48 $ → $ 48 \div 6 = 8 $
18. $ 7 \div 63 $ → $ 63 \div 7 = 9 $
19. $ 6 \div 42 $ → $ 42 \div 6 = 7 $
20. $ 6 \div 54 $ → $ 54 \div 6 = 9 $
Row 6
21. $ 7 \div 49 $ → $ 49 \div 7 = 7 $
22. $ 5 \div 30 $ → $ 30 \div 5 = 6 $
23. $ 5 \div 40 $ → $ 40 \div 5 = 8 $
24. $ 7 \div 56 $ → $ 56 \div 7 = 8 $
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✔ Final Answers:
```
2)18 → 9
4)24 → 6
4)32 → 8
3)27 → 9
4)36 → 9
2)14 → 7
3)21 → 7
4)28 → 7
4)20 → 5
3)24 → 8
2)12 → 6
4)16 → 4
3)18 → 6
5)45 → 9
5)35 → 7
2)16 → 8
6)48 → 8
7)63 → 9
6)42 → 7
6)54 → 9
7)49 → 7
5)30 → 6
5)40 → 8
7)56 → 8
```
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🔍 Explanation:
Each problem is in the form:
Divisor) Dividend, meaning:
Dividend ÷ Divisor
We're finding how many times the divisor fits into the dividend evenly (no remainder in these cases).
For example:
- $ 24 \div 4 = 6 $ because $ 4 \times 6 = 24 $
- $ 35 \div 5 = 7 $ because $ 5 \times 7 = 35 $
All answers are whole numbers, so no remainders are needed.
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✔ All problems are solved! Let me know if you'd like this formatted as a printable answer sheet.
Parent Tip: Review the logic above to help your child master the concept of long division grade 3.
