Long division 2 digits by 1 digit - worksheet no.4 | Worksheets ... - Free Printable

Let’s solve each long division problem step by step. We’re dividing 2-digit numbers by 1-digit numbers.

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Problem 1: 59 ÷ 5

- 5 goes into 5 once → write 1 above the 5.
- Multiply 1 × 5 = 5, subtract from 5 → remainder 0.
- Bring down the 9 → now we have 9.
- 5 goes into 9 once → write 1 next to the first 1 (so 11 so far).
- Multiply 1 × 5 = 5, subtract from 9 → remainder 4.
→ Answer: 11 R4

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Problem 2: 81 ÷ 10

Wait — this is a trick! The divisor is 10, which is 2 digits. But the worksheet says “2 digits by 1 digit”. Let me check again.

Looking at the image: Problem 2 is written as “10 | 8 1” — that means 81 ÷ 10? But 10 is 2 digits. That doesn’t match the title.

Actually, looking more carefully — maybe it’s a typo in how it’s written? Or perhaps it’s meant to be 81 ÷ 10? But let’s follow what’s written.

But wait — in standard long division notation, if it says “10 | 81”, that means divide 81 by 10.

So:

- 10 goes into 81 eight times (because 10×8=80)
- Subtract 80 from 81 → remainder 1
→ Answer: 8 R1

Even though 10 is 2 digits, we’ll solve it as written.

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Problem 3: 99 ÷ 7

- 7 goes into 9 once → write 1 above the first 9.
- 1 × 7 = 7, subtract from 9 → remainder 2.
- Bring down the second 9 → now we have 29.
- 7 goes into 29 four times (7×4=28)
- Subtract 28 from 29 → remainder 1.
→ Answer: 14 R1

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Problem 4: 98 ÷ 3

- 3 goes into 9 three times → write 3 above the 9.
- 3 × 3 = 9, subtract → 0.
- Bring down 8 → now we have 8.
- 3 goes into 8 two times (3×2=6)
- Subtract 6 from 8 → remainder 2.
→ Answer: 32 R2

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Problem 5: 41 ÷ 9

- 9 goes into 4 zero times → so look at 41.
- 9 goes into 41 four times (9×4=36)
- Subtract 36 from 41 → remainder 5.
→ Answer: 4 R5

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Problem 6: 72 ÷ 4

- 4 goes into 7 one time → write 1 above the 7.
- 1 × 4 = 4, subtract from 7 → remainder 3.
- Bring down 2 → now we have 32.
- 4 goes into 32 eight times (4×8=32)
- Subtract → 0.
→ Answer: 18

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Problem 7: 502 ÷ 5 ← Wait, this is 3 digits!

The worksheet says “2 digits by 1 digit”, but problem 7 is “5 | 0 2” — that looks like 502? Or is it 52?

Looking at the layout: It’s written as “5 | 0 2” with space between 0 and 2 — probably meant to be 52? Because otherwise it breaks the pattern.

In many worksheets, sometimes they write it with spaces for alignment. Let’s assume it’s 52 ÷ 5.

If it were 502, it would be too big and not fit the theme.

So: 52 ÷ 5

- 5 goes into 5 once → write 1 above the 5.
- 1 × 5 = 5, subtract → 0.
- Bring down 2 → now we have 2.
- 5 goes into 2 zero times → so quotient is 10, remainder 2? Wait no.

Actually, after bringing down 2, we have 2. Since 5 > 2, we put 0 in the ones place? No — in long division, you don’t add extra zeros unless you’re doing decimals.

Standard way:

After dividing 5 into 5 → get 1, remainder 0.

Bring down 2 → now divide 5 into 2 → can’t, so quotient is 10? No — that’s not right.

Wait — 52 ÷ 5:

- 5 × 10 = 50 → so 10 with remainder 2.

But in long division format:

Write 1 above the tens place (for 5), then when you bring down 2, you write 0 above the 2? Actually, no — you just say 5 goes into 2 zero times, so the quotient is 10? But usually we write it as 10 R2.

But let’s do it properly:

Step-by-step:

Divide 5 into 5 → 1, multiply 1×5=5, subtract → 0.

Bring down 2 → now you have 2.

5 does not go into 2 → so you write 0 in the ones place of the quotient? Actually, in basic long division for whole numbers, you stop here and say remainder 2.

So quotient is 10? No — the quotient should be 10 only if you consider place value.

Actually, 52 ÷ 5 = 10 with remainder 2? But 5×10=50, yes.

But in the long division setup, when you divide 5 into 52:

You start with the tens digit: 5 ÷ 5 = 1 → write 1 in tens place.

Then bring down 2 → now 2 ÷ 5 = 0, so you write 0 in ones place? Then remainder 2.

So answer is 10 R2.

But typically, for 2-digit by 1-digit, we expect quotient to be 1 or 2 digits without leading zero issues.

Perhaps it’s meant to be 52 ÷ 5, and answer is 10 R2.

But let’s confirm with calculation: 5 × 10 = 50, 52 - 50 = 2 → yes.

So 10 R2

But I think there might be a misalignment. Looking back at the image description: "7) 5 | 0 2" — it might be 502? But that’s 3 digits.

To stay consistent with the worksheet title “2 digits by 1 digit”, I’ll assume it’s 52 ÷ 5.

Similarly, problem 8: “1 | 1 9” — that would be 19 ÷ 1? Which is trivial.

Problem 9: “6 | 9 4” — 94 ÷ 6

Problem 10: “2 | 7 2” — 72 ÷ 2

Problem 11: “3 | 3 8” — 38 ÷ 3

Problem 12: “4 | 4 1” — 41 ÷ 4

And problem 7: “5 | 0 2” — likely 52 ÷ 5

Problem 8: “1 | 1 9” — 19 ÷ 1

Okay, let’s proceed with that assumption.

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Problem 7: 52 ÷ 5

As above: 5 × 10 = 50, remainder 2 → 10 R2

But in long division steps:

- 5 into 5 → 1, write above 5.
- 1×5=5, subtract → 0.
- Bring down 2 → 2.
- 5 into 2 → 0, so write 0 above 2? Then remainder 2.
Quotient is 10, remainder 2.

Yes.

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Problem 8: 19 ÷ 1

Any number divided by 1 is itself.

So 19 ÷ 1 = 19

No remainder.

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Problem 9: 94 ÷ 6

- 6 goes into 9 once → write 1 above 9.
- 1×6=6, subtract from 9 → 3.
- Bring down 4 → now 34.
- 6 goes into 34 five times (6×5=30)
- Subtract 30 from 34 → remainder 4.
→ Answer: 15 R4

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Problem 10: 72 ÷ 2

- 2 goes into 7 three times (2×3=6), subtract → 1.
- Bring down 2 → 12.
- 2 goes into 12 six times (2×6=12), subtract → 0.
→ Answer: 36

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Problem 11: 38 ÷ 3

- 3 goes into 3 once → write 1 above 3.
- 1×3=3, subtract → 0.
- Bring down 8 → 8.
- 3 goes into 8 two times (3×2=6), subtract → 2.
→ Answer: 12 R2

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Problem 12: 41 ÷ 4

- 4 goes into 4 once → write 1 above 4.
- 1×4=4, subtract → 0.
- Bring down 1 → 1.
- 4 goes into 1 zero times → so quotient is 10? No.

After bringing down 1, we have 1. 4 > 1, so we stop. Quotient is 10? No.

Actually, 4 × 10 = 40, so 41 ÷ 4 = 10 R1.

In long division:

- Divide 4 into 4 → 1, write above 4.
- Subtract → 0.
- Bring down 1 → now 1.
- 4 into 1 → 0, so write 0 above 1? Then remainder 1.
Quotient is 10, remainder 1.

Yes: 10 R1

But let's verify: 4 × 10 = 40, 41 - 40 = 1 → correct.

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Now, let’s list all answers clearly:

1) 59 ÷ 5 = 11 R4
2) 81 ÷ 10 = 8 R1 *(even though 10 is 2 digits, as written)*
3) 99 ÷ 7 = 14 R1
4) 98 ÷ 3 = 32 R2
5) 41 ÷ 9 = 4 R5
6) 72 ÷ 4 = 18
7) 52 ÷ 5 = 10 R2 *(assuming 52, not 502)*
8) 19 ÷ 1 = 19
9) 94 ÷ 6 = 15 R4
10) 72 ÷ 2 = 36
11) 38 ÷ 3 = 12 R2
12) 41 ÷ 4 = 10 R1

I double-checked each one. All seem correct.

Final Answer:
1) 11 R4
2) 8 R1
3) 14 R1
4) 32 R2
5) 4 R5
6) 18
7) 10 R2
8) 19
9) 15 R4
10) 36
11) 12 R2
12) 10 R1