Practice dividing 3-digit numbers by 1-digit numbers to find the remainder and quotient.

Let’s solve each division problem step by step. We’ll divide the 3-digit number by the 1-digit number and find both the quotient (the answer) and the remainder (what’s left over).

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Problem 1: 236 ÷ 3

- 3 goes into 2 → no, so look at 23.
- 3 × 7 = 21 → write 7 above the 3 in 236.
- Subtract: 23 - 21 = 2.
- Bring down the 6 → now we have 26.
- 3 × 8 = 24 → write 8 next to the 7.
- Subtract: 26 - 24 = 2.
→ Quotient = 78, Remainder = 2

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Problem 2: 315 ÷ 4

- 4 goes into 3 → no, so look at 31.
- 4 × 7 = 28 → write 7 above the 1 in 315.
- Subtract: 31 - 28 = 3.
- Bring down the 5 → now we have 35.
- 4 × 8 = 32 → write 8 next to the 7.
- Subtract: 35 - 32 = 3.
→ Quotient = 78, Remainder = 3

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Problem 3: 494 ÷ 5

- 5 goes into 4 → no, so look at 49.
- 5 × 9 = 45 → write 9 above the 9 in 494.
- Subtract: 49 - 45 = 4.
- Bring down the 4 → now we have 44.
- 5 × 8 = 40 → write 8 next to the 9.
- Subtract: 44 - 40 = 4.
→ Quotient = 98, Remainder = 4

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Problem 4: 341 ÷ 6

- 6 goes into 3 → no, so look at 34.
- 6 × 5 = 30 → write 5 above the 4 in 341.
- Subtract: 34 - 30 = 4.
- Bring down the 1 → now we have 41.
- 6 × 6 = 36 → write 6 next to the 5.
- Subtract: 41 - 36 = 5.
→ Quotient = 56, Remainder = 5

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Problem 5: 818 ÷ 9

- 9 goes into 8 → no, so look at 81.
- 9 × 9 = 81 → write 9 above the 1 in 818.
- Subtract: 81 - 81 = 0.
- Bring down the 8 → now we have 8.
- 9 goes into 8 → 0 times, so write 0 next to the 9? Wait — actually, since 8 is less than 9, we stop here.
But let’s check: 9 × 90 = 810, then 818 - 810 = 8 → so quotient is 90, remainder 8?
Wait — better way:

Actually, 9 × 90 = 810 → 818 - 810 = 8 → yes.

But in long division format:

After subtracting 81 from 81, bring down 8 → 8.

9 doesn’t go into 8 → so quotient digit is 0? But we don’t usually write leading zeros after decimal unless needed. Since this is whole number division with remainder:

We say: 9 × 90 = 810, remainder 8.

But in standard long division steps:

- After first step: 81 ÷ 9 = 9 → write 9 above the tens place.
- Then bring down 8 → 8.
- 9 > 8 → so quotient digit for units place is 0? Actually, no — we just say the quotient is 90 and remainder 8.

Wait — let me recalculate properly:

818 ÷ 9:

9 × 90 = 810 → 818 - 810 = 8 → so quotient = 90, remainder = 8.

Yes.

Alternatively, if doing digit-by-digit:

- 9 into 81 → 9 → write 9 above the 1 (tens place).
- Multiply: 9×9=81, subtract → 0.
- Bring down 8 → 8.
- 9 into 8 → 0, but we can’t leave it blank — so we write 0 in the ones place? Actually, in elementary math, we often just say the quotient is 90 and remainder 8.

To avoid confusion, let’s do it as:

Quotient = 90, Remainder = 8.

Check: 9 × 90 = 810 + 8 = 818 ✔

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Problem 6: 569 ÷ 7

- 7 goes into 5 → no, so look at 56.
- 7 × 8 = 56 → write 8 above the 6 in 569.
- Subtract: 56 - 56 = 0.
- Bring down the 9 → now we have 9.
- 7 × 1 = 7 → write 1 next to the 8.
- Subtract: 9 - 7 = 2.
→ Quotient = 81, Remainder = 2

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Now, let’s double-check all answers quickly:

1. 3 × 78 = 234 + 2 = 236 ✔
2. 4 × 78 = 312 + 3 = 315 ✔
3. 5 × 98 = 490 + 4 = 494 ✔
4. 6 × 56 = 336 + 5 = 341 ✔
5. 9 × 90 = 810 + 8 = 818 ✔
6. 7 × 81 = 567 + 2 = 569 ✔

All correct!

Final Answer:
1. Quotient: 78, Remainder: 2
2. Quotient: 78, Remainder: 3
3. Quotient: 98, Remainder: 4
4. Quotient: 56, Remainder: 5
5. Quotient: 90, Remainder: 8
6. Quotient: 81, Remainder: 2