Four Digit Division with Remainders worksheet with 18 problems and a student illustration.

Let’s solve each division problem step by step. We’ll divide the 4-digit number by the divisor and find both the quotient and the remainder.

We’ll go one by one:

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1. 6593 ÷ 8

8 × 824 = 6592 → Remainder = 6593 - 6592 = 1
→ Quotient: 824, Remainder: 1

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2. 3901 ÷ 5

5 × 780 = 3900 → Remainder = 3901 - 3900 = 1
→ Quotient: 780, Remainder: 1

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3. 8288 ÷ 3

3 × 2762 = 8286 → Remainder = 8288 - 8286 = 2
→ Quotient: 2762, Remainder: 2

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4. 1291 ÷ 6

6 × 215 = 1290 → Remainder = 1291 - 1290 = 1
→ Quotient: 215, Remainder: 1

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5. 2210 ÷ 9

9 × 245 = 2205 → Remainder = 2210 - 2205 = 5
→ Quotient: 245, Remainder: 5

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6. 8302 ÷ 5

5 × 1660 = 8300 → Remainder = 8302 - 8300 = 2
→ Quotient: 1660, Remainder: 2

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7. 7401 ÷ 4

4 × 1850 = 7400 → Remainder = 7401 - 7400 = 1
→ Quotient: 1850, Remainder: 1

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8. 3230 ÷ 9

9 × 358 = 3222 → Remainder = 3230 - 3222 = 8
→ Quotient: 358, Remainder: 8

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9. 7774 ÷ 5

5 × 1554 = 7770 → Remainder = 7774 - 7770 = 4
→ Quotient: 1554, Remainder: 4

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10. 8900 ÷ 6

6 × 1483 = 8898 → Remainder = 8900 - 8898 = 2
→ Quotient: 1483, Remainder: 2

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11. 3891 ÷ 12

12 × 324 = 3888 → Remainder = 3891 - 3888 = 3
→ Quotient: 324, Remainder: 3

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12. 5594 ÷ 17

17 × 329 = 5593 → Remainder = 5594 - 5593 = 1
→ Quotient: 329, Remainder: 1

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13. 7589 ÷ 24

24 × 316 = 7584 → Remainder = 7589 - 7584 = 5
→ Quotient: 316, Remainder: 5

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14. 8781 ÷ 31

31 × 283 = 8773 → Remainder = 8781 - 8773 = 8
→ Quotient: 283, Remainder: 8

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15. 3289 ÷ 38

38 × 86 = 3268 → Remainder = 3289 - 3268 = 21
→ Quotient: 86, Remainder: 21

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16. 4028 ÷ 46

46 × 87 = 4002 → Remainder = 4028 - 4002 = 26
→ Quotient: 87, Remainder: 26

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Now let’s do the right side (problems 1 to 20):

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Right Side – Problem 1: 6593 ÷ 8 → Same as left #1 → Remainder 1

Problem 2: 3901 ÷ 5 → Same as left #2 → Remainder 1

Problem 3: 8288 ÷ 3 → Same as left #3 → Remainder 2

Problem 4: 1291 ÷ 6 → Same as left #4 → Remainder 1

Problem 5: 2210 ÷ 9 → Same as left #5 → Remainder 5

Problem 6: 8302 ÷ 5 → Same as left #6 → Remainder 2

Problem 7: 7401 ÷ 4 → Same as left #7 → Remainder 1

Problem 8: 3230 ÷ 9 → Same as left #8 → Remainder 8

Problem 9: 7774 ÷ 5 → Same as left #9 → Remainder 4

Problem 10: 8900 ÷ 6 → Same as left #10 → Remainder 2

Problem 11: 3891 ÷ 12 → Same as left #11 → Remainder 3

Problem 12: 5594 ÷ 17 → Same as left #12 → Remainder 1

Problem 13: 7589 ÷ 24 → Same as left #13 → Remainder 5

Problem 14: 8781 ÷ 31 → Same as left #14 → Remainder 8

Problem 15: 3289 ÷ 38 → Same as left #15 → Remainder 21

Problem 16: 4028 ÷ 46 → Same as left #16 → Remainder 26

Wait — actually, looking again, the right side has different numbers! Let me recheck carefully.

Actually, I think I made a mistake — the right side is NOT the same problems. Let me read them again from the image description.

Looking back at your original input:

Right side list:

1. 8|6593 → same as left #1 → R=1
2. 5|3901 → same as left #2 → R=1
3. 3|8288 → same as left #3 → R=2
4. 6|1291 → same as left #4 → R=1
5. 9|2210 → same as left #5 → R=5
6. 5|8302 → same as left #6 → R=2
7. 4|7401 → same as left #7 → R=1
8. 9|3230 → same as left #8 → R=8
9. 5|7774 → same as left #9 → R=4
10. 6|8900 → same as left #10 → R=2
11. 12|3891 → same as left #11 → R=3
12. 17|5594 → same as left #12 → R=1
13. 24|7589 → same as left #13 → R=5
14. 31|8781 → same as left #14 → R=8
15. 38|3289 → same as left #15 → R=21
16. 46|4028 → same as left #16 → R=26

Then it continues:

17. 16|9482
18. 56|8492
19. 18|7401
20. 46|9991

Ah! So problems 17–20 on the right are new. Let’s solve those.

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Right Side – Problem 17: 9482 ÷ 16

16 × 592 = 9472 → Remainder = 9482 - 9472 = 10
→ Quotient: 592, Remainder: 10

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Problem 18: 8492 ÷ 56

56 × 151 = 8456 → Remainder = 8492 - 8456 = 36
→ Quotient: 151, Remainder: 36

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Problem 19: 7401 ÷ 18

18 × 411 = 7398 → Remainder = 7401 - 7398 = 3
→ Quotient: 411, Remainder: 3

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Problem 20: 9991 ÷ 46

46 × 217 = 9982 → Remainder = 9991 - 9982 = 9
→ Quotient: 217, Remainder: 9

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Now, since the user didn’t specify which problem to solve, but uploaded a worksheet with many problems, and the instruction says “solve the problem accurately”, I assume they want all answers.

But to be safe — perhaps they want just the remainders? Or full quotients and remainders?

Since it's titled "Four Digit Division with Remainders", likely they want the remainder for each.

But to be thorough, I’ll provide both quotient and remainder for each problem in order.

However, note that the left side has 18 problems, right side has 20 — total 38 problems. That’s too long to list all unless asked.

Wait — maybe the user expects only the first few? But no instruction.

Alternatively, perhaps this is a trick — the image shows two columns, but maybe the task is to complete all? Since the assistant must solve accurately, I should provide all.

But that would make the answer extremely long.

Re-reading the user message: “Solve the problem accurately.” — singular “problem”. But there are many.

Perhaps the intended task is to understand how to do one, but since no specific one is chosen, I’ll pick the first one as an example and show full work, then give all remainders briefly.

But the rules say: “First work through the problem step by step... ONLY THEN provide the final answer.”

And “Final Answer” should be the correct answer — implying one answer.

This is ambiguous.

Alternative approach: Since the worksheet is called “Four Digit Division with Remainders”, and often such worksheets ask for the remainder, I’ll compute the remainder for each problem and list them in order.

But again — 38 problems.

Wait — looking back at the image description, the left column has 18 problems numbered 1 to 18, right column has 20 problems numbered 1 to 20. They are separate sets.

Perhaps the user wants both sides solved.

To avoid making the response too long, I’ll provide the remainders for all problems in sequence.

Let me compile all remainders:

Left Side (Problems 1 to 18):

1. 6593 ÷ 8 → R = 1
2. 3901 ÷ 5 → R = 1
3. 8288 ÷ 3 → R = 2
4. 1291 ÷ 6 → R = 1
5. 2210 ÷ 9 → R = 5
6. 8302 ÷ 5 → R = 2
7. 7401 ÷ 4 → R = 1
8. 3230 ÷ 9 → R = 8
9. 7774 ÷ 5 → R = 4
10. 8900 ÷ 6 → R = 2
11. 3891 ÷ 12 → R = 3
12. 5594 ÷ 17 → R = 1
13. 7589 ÷ 24 → R = 5
14. 8781 ÷ 31 → R = 8
15. 3289 ÷ 38 → R = 21
16. 4028 ÷ 46 → R = 26
17. 9482 ÷ 16 → R = 10 [Note: This was on right side problem 17, but left side only goes to 18, and left side problem 17 is 16|9482? Wait no — in left side, problem 17 is 16|9482? Let me check original.]

Original left side:

16. 46|4028
17. 16|9482
18. 56|8492

Oh! I missed that. In my initial solving, I did up to 16 on left, but left has 18 problems.

Let me correct:

Left Side Problems:

1. 8|6593 → R=1
2. 5|3901 → R=1
3. 3|8288 → R=2
4. 6|1291 → R=1
5. 9|2210 → R=5
6. 5|8302 → R=2
7. 4|7401 → R=1
8. 9|3230 → R=8
9. 5|7774 → R=4
10. 6|8900 → R=2
11. 12|3891 → R=3
12. 17|5594 → R=1
13. 24|7589 → R=5
14. 31|8781 → R=8
15. 38|3289 → R=21
16. 46|4028 → R=26
17. 16|9482 → R=10 (as calculated)
18. 56|8492 → R=36 (as calculated for right side prob 18)

Right Side Problems 1 to 20:

1. 8|6593 → R=1
2. 5|3901 → R=1
3. 3|8288 → R=2
4. 6|1291 → R=1
5. 9|2210 → R=5
6. 5|8302 → R=2
7. 4|7401 → R=1
8. 9|3230 → R=8
9. 5|7774 → R=4
10. 6|8900 → R=2
11. 12|3891 → R=3
12. 17|5594 → R=1
13. 24|7589 → R=5
14. 31|8781 → R=8
15. 38|3289 → R=21
16. 46|4028 → R=26
17. 16|9482 → R=10
18. 56|8492 → R=36
19. 18|7401 → R=3
20. 46|9991 → R=9

So essentially, the first 16 problems on both sides are identical, then right side adds two more: 19 and 20.

But left side also has 17 and 18 which are the same as right side 17 and 18.

In fact, left side problems 1-18 are exactly the same as right side problems 1-18, and right side has two extra: 19 and 20.

Is that true?

Left side problem 17: 16|9482
Right side problem 17: 16|9482 — same

Left side problem 18: 56|8492
Right side problem 18: 56|8492 — same

Then right side has 19: 18|7401 and 20: 46|9991

So if the user wants all, I need to provide 20 remainders for the right side, or 18 for left.

But since the instruction is vague, and to keep it manageable, I'll provide the remainders for the first 10 problems on the left side as a sample, but that might not be sufficient.

Another idea: perhaps the "problem" refers to the entire worksheet, and I need to output all answers.

Given the constraints, I think the best way is to list all remainders for the left side (18 problems) since it's listed first, and mention that the right side is similar with two additional problems.

But to follow the rule of providing a final answer after reasoning, I'll box the list of remainders for the left side.

Let me double-check a couple to ensure accuracy.

For example, problem 15: 3289 ÷ 38

38 * 86 = 38*80 + 38*6 = 3040 + 228 = 3268

3289 - 3268 = 21 — correct.

Problem 16: 4028 ÷ 46

46 * 87 = 46*80 + 46*7 = 3680 + 322 = 4002

4028 - 4002 = 26 — correct.

Problem 17: 9482 ÷ 16

16 * 592 = 16*500=8000, 16*92=1472, total 8000+1472=9472

9482 - 9472 = 10 — correct.

Problem 18: 8492 ÷ 56

56 * 150 = 8400, 56*1=56, so 56*151=8400+56=8456

8492 - 8456 = 36 — correct.

Now for the right side additional problems:

19. 7401 ÷ 18

18 * 411 = 18*400=7200, 18*11=198, total 7200+198=7398

7401 - 7398 = 3 — correct.

20. 9991 ÷ 46

46 * 217 = 46*200=9200, 46*17=782, total 9200+782=9982

9991 - 9982 = 9 — correct.

Since the user may expect the answers for the left side, I'll provide those.

Final decision: Provide the remainders for the 18 problems on the left side, as they are listed first and form a complete set.

So the final answer will be a list of remainders for problems 1 to 18 on the left.

To present it clearly:

Final Answer:
1. 1
2. 1
3. 2
4. 1
5. 5
6. 2
7. 1
8. 8
9. 4
10. 2
11. 3
12. 1
13. 5
14. 8
15. 21
16. 26
17. 10
18. 36

This matches our calculations.

If the user meant something else, they can clarify, but based on the information, this is accurate.